relative-path

AngularJS: Relative link paths are broken when html5mode(true) is on

可紊 提交于 2019-12-04 08:10:44
I've been searching and I've found "solutions" to this problem, yet I still can't get this to work right. The Scenario: I'm building an Angular (version 1.2) website with the UI Router and running it on a Node server on localhost. I'm trying to make it have "pretty" url's with the $locationProvider and by turning html5(true) on. My website works fine when clicking through it, but when I try to navigate to a relative link path or refresh the link path the page breaks. I also intend to deploy this webapp to Heroku when completed: RELATIVE LINK PATH: http://localhost:8000/locksmith-services PAGE

How do I use a relative path in Xcode project settings?

笑着哭i 提交于 2019-12-04 07:40:57
问题 How do I use a relative path in Xcode project settings? 回答1: All paths in Build Settings are assumed relative to the directory that contains the .xcodeproj file. Use the standard Unix path tokens . project directory .. parent directory So if your project file is trunk/Mac/proj.xcodeproj, and your headers are in trunk/Headers/foo.h, you would add ../Headers to your Header Search Paths. 回答2: Also there are two paths: $SRCROOT and $SDKROOT. 回答3: In the upper left corner next to the build/stop

How can I use relative paths to external response files for soapUI MockService

北城余情 提交于 2019-12-04 06:38:34
What I've Done I am using soapUI (3.6.1 Free version) mock services to serve up specific data to 2 client applications I am testing. With some simple Groovy script I've set up some mock operations to fetch responses from specific files based on the requests made by the client applications. The static contents of the mock response is: ${responsefile} The groovy in the operation dispatch scripting pane is: def req = new XmlSlurper().parseText(mockRequest.requestContent) if (req =~ "CategoryA") { context.responsefile = new File("C:/soapProject/Test_Files/ID_List_CategoryA.xml").text } else {

Absolute vs Relative Links : Technical Difference

青春壹個敷衍的年華 提交于 2019-12-04 05:51:26
问题 Which is better option or there is no difference in terms of speed or other issues like SEO, Backlinks href="http://www.example.com/contact" href="../../contact" From what i observe, Absolute paths uses paths from left to right finally move to rightmost position as in http//www.example/contact fpr relative paths: first it gets the current location, then based ../../contact or ../blog/articles move there. Technically which is faster, as mentioned in answers speed difference is ignorable/minute

Which directories does PHP check when including a relative path with include()?

谁说我不能喝 提交于 2019-12-04 05:05:00
It's very odd,has anyone ever sum up with a conclusion yet? Sometimes it checks the directory of the included file,too. But sometimes not. D:\test\1.php <?php include('sub\2.php'); D:\test\2.php <?php include('3.php'); Where 3.php is in the same dir as 2.php . The above works,but why?The current directory should be D:\test ,but it can still find 3.php,which is in D:\test\sub More story ( final ) About a year ago I met this problem,and then I ended up fixed it with the hardcoding like below: Common.php: if (file_exists("../../../Common/PHP/Config.inc")) include('../../../Common/PHP/Config.inc')

Achieving the effect of changing the Java working directory

家住魔仙堡 提交于 2019-12-04 04:24:28
问题 Context: My software depends on calling a library which can only accept relative paths as an input because of an old limitation. I need the paths to be relative to a known directory. The library might make a call internally like java.io.File fooBar = new java.io.File("foo/bar"); I need this to give me /nwd/foo/bar and not, say, /cwd/foo/bar where /cwd is the working directory from which java was run. For all intents and purposes, I cannot modify the internal behavior of this library. Manually

Python import modules, folder structures

99封情书 提交于 2019-12-04 03:24:30
I have been looking for a way to solve this. I have a python project, and this is the folder structure I want: /project/main.py /project/src/models.py /project/test/tests.py I want to be able to run the tests by executing the tests.py in terminal. tests.py imports modules in /project/src/ for testing. First I solved this by adding sys.path.insert(0, '..') in tests.py. But then the paths used in models.py for opening text files had to be relative to the tests.py , etc. Which means the program wouldn't run when excecuted from main.py , cause of the paths. I also tried with dots when importing

How to get a path from a directory in a C# console application?

余生长醉 提交于 2019-12-04 02:50:44
Say I have this file structure Soultion-> Folder1 -> FileIwant.html So this could be something like C:\Soultion\Folder1\FilterIwant.html Now I need to read this file into my application. I can't just hardcode it since when I give it to someone else they might put it on F: drive or something. Or when I create a msi file the path might be completely different. So how can I say maybe take "Folder1\FilterIwant.html" and use that to get the folder path regardless of where they put it? Edit I tried Path.GetFullPath but I land up in the bin/debug directory. But my file is not in that directory. I

webpack: Module not found: Error: Can't resolve (with relative path)

不羁的心 提交于 2019-12-04 02:41:23
I have this structure of an app ( node_modules dir excluded from this list): ├── actions.js ├── bundle.js ├── components │ ├── App.js │ ├── Footer.js │ ├── Link.js │ ├── Todo.js │ └── TodoList.js ├── Containers │ ├── AddTodo.js │ ├── FilterLink.js │ └── VisibleTodoList.js ├── index.html ├── index.js ├── main.js ├── package.json ├── package-lock.json ├── reducers.js └── webpack.config.js My webpack config looks like this: module.exports = { entry: "./main.js", output: { path: __dirname, filename: "bundle.js" }, module: { loaders: [ { test: /\.js$/, loader: 'babel-loader', query: { presets: [

Unix paths that work for any platform in Python?

天涯浪子 提交于 2019-12-04 02:14:35
Can all paths in a Python program use ".." (for the parent directory) and / (for separating path components), and still work whatever the platform ? On one hand, I have never seen such a claim in the documentation (I may have missed it), and the os and os.path modules do provide facilities for handling paths in a platform agnostic way (os.pardir, os.path.join,…), which lets me think that they are here for a reason. On the other hand, you can read on StackOverflow that "../path/to/file" works on all platforms… So, should os.pardir, os.path.join and friends always be used, for portability