How to shave off last character using sed?
问题 That is, going from ABCD -> ABC 回答1: You can try: sed s'/.$//' The regex used is .$ . is a regex meta char to match anything (except newline) $ is the end of line anchor. By using the $ we force the . to match the last char This will remove the last char, be it anything: $ echo ABCD | sed s'/.$//' ABC $ echo ABCD1 | sed s'/.$//' ABCD But if you want to remove the last char, only if its an alphabet, you can do: $ echo ABCD | sed s'/[a-zA-Z]$//' ABC $ echo ABCD1 | sed s'/[a-zA-Z]$//' ABCD1 回答2: