regex

Regular expression optional match start/end of line

由 可紊 提交于 2021-02-07 20:53:23
问题 How do I optionally match the start ^ or end $ of a line in a regular expression. For example: /(?<=[\s\^])/ does not match starts with space character or start of line. As requested my problem was in PHP matching the following. $str = '**bold** **bold** **bold**'; echo preg_replace('/(?<=\s|^)\*\*(.+?)\*\*(?=\s|$)/', '<strong>\\1</strong>', $str); My edge cases were the bold at the start and end of the string were not being matched. Some edge cases I came across with other variants were

Regular expression optional match start/end of line

由 烂漫一生 提交于 2021-02-07 20:49:41
问题 How do I optionally match the start ^ or end $ of a line in a regular expression. For example: /(?<=[\s\^])/ does not match starts with space character or start of line. As requested my problem was in PHP matching the following. $str = '**bold** **bold** **bold**'; echo preg_replace('/(?<=\s|^)\*\*(.+?)\*\*(?=\s|$)/', '<strong>\\1</strong>', $str); My edge cases were the bold at the start and end of the string were not being matched. Some edge cases I came across with other variants were

Chunking sentences using the word 'but' with RegEx

由 十年热恋 提交于 2021-02-07 20:43:04
问题 I am attempting to chunk sentences using RegEx at the word 'but' (or any other coordinating conjunction words). It's not working... sentence = nltk.pos_tag(word_tokenize("There are no large collections present but there is spinal canal stenosis.")) result = nltk.RegexpParser(grammar).parse(sentence) DigDug = nltk.RegexpParser(r'CHUNK: {.*<CC>.*}') for subtree in DigDug.parse(sentence).subtrees(): if subtree.label() == 'CHUNK': print(subtree.node()) I need to split the sentence "There are no

Chunking sentences using the word 'but' with RegEx

由 谁说我不能喝 提交于 2021-02-07 20:42:31
问题 I am attempting to chunk sentences using RegEx at the word 'but' (or any other coordinating conjunction words). It's not working... sentence = nltk.pos_tag(word_tokenize("There are no large collections present but there is spinal canal stenosis.")) result = nltk.RegexpParser(grammar).parse(sentence) DigDug = nltk.RegexpParser(r'CHUNK: {.*<CC>.*}') for subtree in DigDug.parse(sentence).subtrees(): if subtree.label() == 'CHUNK': print(subtree.node()) I need to split the sentence "There are no

Chunking sentences using the word 'but' with RegEx

由 耗尽温柔 提交于 2021-02-07 20:41:45
问题 I am attempting to chunk sentences using RegEx at the word 'but' (or any other coordinating conjunction words). It's not working... sentence = nltk.pos_tag(word_tokenize("There are no large collections present but there is spinal canal stenosis.")) result = nltk.RegexpParser(grammar).parse(sentence) DigDug = nltk.RegexpParser(r'CHUNK: {.*<CC>.*}') for subtree in DigDug.parse(sentence).subtrees(): if subtree.label() == 'CHUNK': print(subtree.node()) I need to split the sentence "There are no

Vim - Macro to expand verilog bus

由 穿精又带淫゛_ 提交于 2021-02-07 20:22:10
问题 I can't seem to be able to create a vim macro that does the following: Source: this_is_a_bus[10:0] another_bus[2:0] Required Dest: this_is_a_bus[10] this_is_a_bus[9] this_is_a_bus[8] this_is_a_bus[7] this_is_a_bus[6] this_is_a_bus[5] this_is_a_bus[4] this_is_a_bus[3] this_is_a_bus[2] this_is_a_bus[1] this_is_a_bus[0] another_bus[2] another_bus[1] another_bus[0] What I tried to do: I can search for \d\+:\d\+ and put the cursor on the first number, then copy that with yw to the memory. However

Remove spaces only before and after commas

由 ♀尐吖头ヾ 提交于 2021-02-07 20:13:32
问题 I am looking for a regex (?) way to remove spaces before and after commas only. Example: ((100 0, 101 0, 101 1, 100 1, 100 0) , (100.2 0.2, 100.8 0.2, 100.8 0.8, 100.2 0.8, 100.2 0.2)) Expected result: ((100 0,101 0,101 1,100 1,100 0),(100.2 0.2,100.8 0.2,100.8 0.8,100.2 0.8,100.2 0.2)) I could not yet find a satisfactory answer despite numerous searches. 回答1: You can use the following regex: s = Regex.Replace(s, " *, *", ","); This searches for every comma preceded and/or followed by any

Form Regex that finds pattern within a repeating decimal

由 随声附和 提交于 2021-02-07 19:45:39
问题 How can I form a regular expression that match the unique numbers that repeat in a repeating decimals? Currently my regular expressions is the following. var re = /(?:[^\.]+\.\d*)(\d+)+(?:\1)$/; Example: // Pass deepEqual( func(1/111), [ "0.009009009009009009", "009" ] ); // Fails, since func(11/111) returns [ "0.099099099099099", "9" ] deepEqual( func(11/111), [ "0.099099099099099", "099" ] ); Live demo here: http://jsfiddle.net/9dGsw/ Here's my code. // Goal: Find the pattern within

零基础入门前端开发工程师

由 那年仲夏 提交于 2021-02-07 18:42:05
download： 零基础入门前端开发工程师 本微专业由来自网易云音乐、网易邮箱、严选、考拉的一线前端开发专家联手打造，聚焦HTML、css、JavaScript、DOM四大核心知识技能模块，剖析网易明星产品真实案例，助你夯实基础，成为一名合格的前端开发人员 Q: 零基础可以学习这门微专业课程吗？ A: 可以，这套课程就是为零基础学员而打造的，专门设置有《前端入门》章节，帮助零基础学员快速理清课程内容体系，提前熟悉前端开发工具、调试工具，并通过直观的案例展示，形成对前端领域整体的清晰认知。 1。四位数字字母验证码的生成实例 1 import random 2 if __name__ == " __main__ " : # 四位数字字母验证码的生成 3 checkcode= "" # 保存验证码的变量 4 for i in range(4 ): 5 index=random.randrange(0,4) # 生成一个0~3中的数 6 if index!=i and index +1 != i: 7 checkcode +=chr(random.randint(97,122)) # 生成a~z中的一个小写字母 8 elif index +1== i: 9 checkcode +=chr(random.randint(65,90) ) # 生成A~Z中的一个大写字母 10 else :

How to use Beautiful Soup to find a tag with changing id?

由 别来无恙 提交于 2021-02-07 18:34:38
问题 I am using Beautiful Soup in Python. Here is an example URL: http://www.locationary.com/place/en/US/Ohio/Middletown/McDonald%27s-p1013254580.jsp In the HTML, there are a bunch of tags and the only way I can specify which ones to find is with their id. The only thing I want to find is the telephone number. The tag looks like this: <td class="dispTxt" id="value_xxx_c_1_f_8_a_134242498">5134231582</td> I have gone to other URLs on the same website and found almost the same id for the telephone
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