regex

Count number of line in txt file when new line is inside data

时光怂恿深爱的人放手 提交于 2021-01-02 18:08:25
问题 I have one txt file which has below data Name mobile url message text test11 1234567890 www.google.com "Data Test New Date:27/02/2020 Items: 1 Total: 3 Regards ABC DATa Ph:091 : 123456789" test12 1234567891 www.google.com "Data Test New one Date:17/02/2020 Items: 26 Total: 5 Regards user test Ph:091 : 433333333" Now you can see my last column data has new line character. so when I use below command awk 'END{print NR}' file.txt it is giving my length is 15 but actually line length is 3 .

Count number of line in txt file when new line is inside data

[亡魂溺海] 提交于 2021-01-02 18:05:29
问题 I have one txt file which has below data Name mobile url message text test11 1234567890 www.google.com "Data Test New Date:27/02/2020 Items: 1 Total: 3 Regards ABC DATa Ph:091 : 123456789" test12 1234567891 www.google.com "Data Test New one Date:17/02/2020 Items: 26 Total: 5 Regards user test Ph:091 : 433333333" Now you can see my last column data has new line character. so when I use below command awk 'END{print NR}' file.txt it is giving my length is 15 but actually line length is 3 .

Count number of line in txt file when new line is inside data

烈酒焚心 提交于 2021-01-02 18:03:45
问题 I have one txt file which has below data Name mobile url message text test11 1234567890 www.google.com "Data Test New Date:27/02/2020 Items: 1 Total: 3 Regards ABC DATa Ph:091 : 123456789" test12 1234567891 www.google.com "Data Test New one Date:17/02/2020 Items: 26 Total: 5 Regards user test Ph:091 : 433333333" Now you can see my last column data has new line character. so when I use below command awk 'END{print NR}' file.txt it is giving my length is 15 but actually line length is 3 .

Count number of line in txt file when new line is inside data

不打扰是莪最后的温柔 提交于 2021-01-02 18:03:15
问题 I have one txt file which has below data Name mobile url message text test11 1234567890 www.google.com "Data Test New Date:27/02/2020 Items: 1 Total: 3 Regards ABC DATa Ph:091 : 123456789" test12 1234567891 www.google.com "Data Test New one Date:17/02/2020 Items: 26 Total: 5 Regards user test Ph:091 : 433333333" Now you can see my last column data has new line character. so when I use below command awk 'END{print NR}' file.txt it is giving my length is 15 but actually line length is 3 .

Does String match glob pattern

被刻印的时光 ゝ 提交于 2021-01-02 08:24:39
问题 I have an array of paths, let's say: /Users/alansouza/workspace/project/src/js/components/chart/Graph.js Also I have an entry in a configuration file with additional attributes for this path in a wildcard(glob) format, as in: { '**/*.js': { runBabel: true } } Question : Is there an easy way to validate if the path matches the wildcard expression? For example: const matches = Glob.matches( '**/*.js', '/Users/alansouza/workspace/project/src/js/components/chart/Graph.js' ); if (matches) { //do

Does String match glob pattern

坚强是说给别人听的谎言 提交于 2021-01-02 08:20:30
问题 I have an array of paths, let's say: /Users/alansouza/workspace/project/src/js/components/chart/Graph.js Also I have an entry in a configuration file with additional attributes for this path in a wildcard(glob) format, as in: { '**/*.js': { runBabel: true } } Question : Is there an easy way to validate if the path matches the wildcard expression? For example: const matches = Glob.matches( '**/*.js', '/Users/alansouza/workspace/project/src/js/components/chart/Graph.js' ); if (matches) { //do

HTACCESS redirect using URL parameter ID number range

旧巷老猫 提交于 2021-01-02 06:34:41
问题 I'm hoping someone can help as this is proving difficult to figure out. I am trying to redirect via HTACCESS and mod_rewrite a number of pages that have a URL parameter ID value within a particular range (from 1 to 7603). Here is what I have so far: <IfModule mod_rewrite.c> RewriteEngine On RewriteCond %{QUERY_STRING} &?id=\b([1-9][0-9]{0,2}|[1-6][0-9]{3}|7[0-5][0-9]{2}|760[0-3])\b [NC] RewriteRule ^example\.php$ http://www.website.com/? [R=301,L] </IfModule> It currently does redirect the

How to delete all lines before the first and after the last occurrence of a string?

纵然是瞬间 提交于 2021-01-02 06:00:26
问题 cat grab.txt My Dashboard Fnfjfjf. random test 00:50 1:01:56 My Notes No data found. Change Language + English Submit Estimation of Working Capital Lecture 1 Estimation of Working Capital Lecture 2 Estimation of Working Capital Lecture 3 Money Market Lecture 254 Money Market Lecture 255 Money Market Lecture 256 International Trade Lecture 257 International Trade Lecture 258 International Trade Lecture 259 Terms And Conditions 84749473837373 Random text fifjfofifofjfkfkf I need to filter this

Ant: Malformed \uxxxx encoding in propertyfile task

戏子无情 提交于 2021-01-02 05:14:06
问题 I get the error below with an Ant skript I wrote. I already did some googling and found out, that the problem lies with strings containing \u, which happens under Windows because of the directory separator. I changed all those to / but the error remains. There are definitely no remaining \u strings in my script. java.lang.IllegalArgumentException: Malformed \uxxxx encoding. The error occurs when executing the propertyfile task, so I examined the file I want to change. This on the other hand

Ant: Malformed \uxxxx encoding in propertyfile task

China☆狼群 提交于 2021-01-02 05:13:26
问题 I get the error below with an Ant skript I wrote. I already did some googling and found out, that the problem lies with strings containing \u, which happens under Windows because of the directory separator. I changed all those to / but the error remains. There are definitely no remaining \u strings in my script. java.lang.IllegalArgumentException: Malformed \uxxxx encoding. The error occurs when executing the propertyfile task, so I examined the file I want to change. This on the other hand