regex

Python Regex escape operator \ in substitutions & raw strings

由 感情迁移 提交于 2021-01-24 09:45:07
问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to

Python Regex escape operator \ in substitutions & raw strings

由 守給你的承諾、 提交于 2021-01-24 09:44:17
问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to

Splitting a string based on Pattern Java

由 一世执手 提交于 2021-01-24 08:30:48
问题 Hi I have log files of the following pattern- 2014-03-06 03:21:45,432 ERROR [mfs:pool-3-thread-19] dispatcher.StatusNotification - Error processing notification. Operation aborted. java.sql.SQLException: Network error IOException: Connection timed out: connect 2014-03-06 03:22:06,454 ERROR [mfs:pool-3-thread-19] dispatcher.ClientStatusNotification - Error processing notification. Operation aborted. java.sql.SQLException: Network error IOException: Connection timed out: connect 2014-03-06 03

Redirect to dynamic relative paths with .htaccess?

由 人盡茶涼 提交于 2021-01-22 10:38:15
问题 Is it possible to make .htaccess "understand" dynamic relative paths and redirect to them properly? My setup goes as follows: http://domain.com/htroot/aaa/xyz http://domain.com/htroot/bbb/xyz http://domain.com/htroot/ccc/xyz And so on. For the sake of the example, "htroot" contains the .htaccess I need to modify. The following sublevels (aaa, bbb, ccc) can be any a-z0-9 name, and the folders have an index.php (or any other .php to be redirected to). The xyz should work as a parameter of sorts

Ansible lineinfile模块详解

由 笑着哭i 提交于 2021-01-22 10:23:39
[toc] 简介 之所以专门说一说这个模块，是因为lineinfile在实际使用中非常有用。 实际上，在大多数时候，我们在linux上的操作，就是针对文件的操作，通过配置管理工具对配置文件作统一的配置修改是一个非常酷的功能。 下面是官方针对该模块的说明： lineinfile - Ensure a particular line is in a file, or replace an existing line using a back-referenced regular expression 简单讲，这个模块就是针对一个文件中行内容的操作。 下面我们详细说一说其具体可以做的事情。 修改匹配行 下面是一个简单的task示例： # 将/etc/selinux/config中匹配到以'SELINUX='开头的行，将其替换为'SELINUX=disabled' - name: modify selinux to disabled lineinfile: path: /etc/selinux/config regex: '^SELINUX=' line: 'SELINUX=disabled' 在匹配行前或后添加内容 示例文件如下： # cat /etc/http.conf Listen 127.0.0.1:80 Listen 80 Port 在匹配行前添加 在http.conf文件的

Using like operator to check for pattern in hive

由 ↘锁芯ラ 提交于 2021-01-22 10:15:06
问题 I need to retrieve the columns from a hive table that must begin with uppercase letter and end with digit. I used this query select * from tab1 where col1 like '[A-Z]%[0-9]'; But not able to retrieve the records ,getting only empty result. 回答1: rlike / regexp select * from tab1 where col1 rlike '^[A-Z].*[0-9]$'; 来源： https://stackoverflow.com/questions/42809183/using-like-operator-to-check-for-pattern-in-hive

Using like operator to check for pattern in hive

由 僤鯓⒐⒋嵵緔 提交于 2021-01-22 10:10:43
问题 I need to retrieve the columns from a hive table that must begin with uppercase letter and end with digit. I used this query select * from tab1 where col1 like '[A-Z]%[0-9]'; But not able to retrieve the records ,getting only empty result. 回答1: rlike / regexp select * from tab1 where col1 rlike '^[A-Z].*[0-9]$'; 来源： https://stackoverflow.com/questions/42809183/using-like-operator-to-check-for-pattern-in-hive

Using like operator to check for pattern in hive

由 隐身守侯 提交于 2021-01-22 10:07:13
问题 I need to retrieve the columns from a hive table that must begin with uppercase letter and end with digit. I used this query select * from tab1 where col1 like '[A-Z]%[0-9]'; But not able to retrieve the records ,getting only empty result. 回答1: rlike / regexp select * from tab1 where col1 rlike '^[A-Z].*[0-9]$'; 来源： https://stackoverflow.com/questions/42809183/using-like-operator-to-check-for-pattern-in-hive

How to split string but keep delimiters in java? [duplicate]

由 给你一囗甜甜゛ 提交于 2021-01-22 05:26:11
问题 This question already has answers here : How to split a string, but also keep the delimiters? (23 answers) Closed 1 year ago . I'm trying to recreate the way discord parses messages with emoji's inside of it. For example, I want the message Hello, :smile::hearth: world! to split into the following array: ["Hello, ", ":smile:", ":hearth:", " world!"] I've already tried to split the array with the following code: Arrays.toString(message.split("(:[A-Za-z]+:)")) However, the split method removes

How to split string but keep delimiters in java? [duplicate]

由 泪湿孤枕 提交于 2021-01-22 05:25:10
问题 This question already has answers here : How to split a string, but also keep the delimiters? (23 answers) Closed 1 year ago . I'm trying to recreate the way discord parses messages with emoji's inside of it. For example, I want the message Hello, :smile::hearth: world! to split into the following array: ["Hello, ", ":smile:", ":hearth:", " world!"] I've already tried to split the array with the following code: Arrays.toString(message.split("(:[A-Za-z]+:)")) However, the split method removes
订阅 regex