redefine

问题 I would like to construct a network in Caffe in which the incoming data is split up initially, passes separately through the same set of layers, and is finally recombined using an eltwise layer. After this, all the parts will move as a single blob. The layer configuration of the part of the network for which the data moves parallely will be identical, except for the learned parameters. Is there a way to define this network in Caffe without redefining the layers through which the different

问题 I am trying to extend and tailor an external xsd schema (of the fixml standard). I need to change the data type of some of the elements, without touching the original schema, but by redefining it; but have been finding it exceedingly cumbersome. What exists: fields-base.xsd <xs:simpleType name="LastUpdateTime_t"> <xs:restriction base="UTCTimestamp"> <xs:simpleType> what I want it to become: <xs:simpleType name="LastUpdateTime_t"> <xs:restriction base="xs:string"> <xs:simpleType> What I have

问题 Is it possible to redefine the _function_used_by_exported_function only for the exported_function call in the second_routine ? #!/usr/bin/env perl use warnings; use strict; use Needed::Module qw(exported_function); sub first_routine { return exported_function( 2 ); } no warnings 'redefine'; sub Needed::Module::_function_used_by_exported_function { return 'B'; } sub second_routine { return exported_function( 5 ); } say first_routine(); say second_routine(); 回答1: You can locally redefine the

问题 Is it possible to redefine the _function_used_by_exported_function only for the exported_function call in the second_routine ? #!/usr/bin/env perl use warnings; use strict; use Needed::Module qw(exported_function); sub first_routine { return exported_function( 2 ); } no warnings 'redefine'; sub Needed::Module::_function_used_by_exported_function { return 'B'; } sub second_routine { return exported_function( 5 ); } say first_routine(); say second_routine(); 回答1: You can locally redefine the

问题 I have a mem_malloc() and mem_free() defined for me and I want to use them to replace the malloc() and free() and consequently C++'s new and delete. I define them as follows: extern "C" { extern void *mem_malloc(size_t); extern void mem_free(void *); void * malloc(size_t size) { return mem_malloc(size); } void free(void *memory) { mem_free(memory); } } However, I get two link errors: [user@machine test]$ g++ -m32 -pthread main.cpp -static libmemnmf-O.a /usr/lib/../lib/libc.a(malloc.o): In

问题 I originally had an array[1..1000] that was defined as a global variable. But now I need that to be n, not 1000 and I don't find out n until later. I know what n is before I fill the array up but I need it to be global therefore need a way to define the size of a global array at run time. Context is filling an array with a linear transformation of the bytes in a file. I don't know how big the file is until someone wants to open it and the files can be of any size. 回答1: As of Delphi 4, Delphi

问题 I want to do two things: In production code, I want to redefine the open command to enable me to add automagic file logging. I work on data processing applications/flows and as part of that, it's important for the user to know exactly what files are being processed. If they are using an old version of a file, one way for them to find out is by reading through the list of files being processed. I could just create a new sub that does this logging and returns a file pointer and use that in

问题 I want to do two things: In production code, I want to redefine the open command to enable me to add automagic file logging. I work on data processing applications/flows and as part of that, it's important for the user to know exactly what files are being processed. If they are using an old version of a file, one way for them to find out is by reading through the list of files being processed. I could just create a new sub that does this logging and returns a file pointer and use that in

问题 Why I can't redefine the __and__ operator? class Cut(object): def __init__(self, cut): self.cut = cut def __and__(self, other): return Cut("(" + self.cut + ") && (" + other.cut + ")") a = Cut("a>0") b = Cut("b>0") c = a and b print c.cut() I want (a>0) && (b>0) , but I got b, that the usual behaviour of and 回答1: __and__ is the binary (bitwise) & operator, not the logical and operator. Because the and operator is a short-circuit operator, it can't be implemented as a function. That is, if the

问题 How can I redefine the exponential function .^ in MATLAB? From: x.^y to: sign(x).*abs(x.^y)) 回答1: Can you redefine an arithmetic operator in MATLAB?... Yes Should you redefine an arithmetic operator in MATLAB?... Eh, probably not. Why? Because every other function in MATLAB expects that the arithmetic operator will behave as defined by the built-in implementation. I've answered a few other related questions that have dealt with overloading arithmetic operators and shadowing built-in behavior,