recursion

List folders at or below a given depth in Powershell

孤街浪徒 提交于 2020-02-20 21:37:16
问题 I have a directory which contains a lot of folders. I want to list all folder (path) that go deeper than 2 levels. So in below case folder 1 & 2. Directory/folder1 Directory/folder1/test1/test/testsub Directory/folder1/test2 Directory/folder1/test3 Directory/folder2/blablabla/bla/1 Directory/folder3/test Directory/folder4/test Directory/folder5/test I was trying the following: $Depth = 3 $Path = "." $Levels = "\*" * $Depth $Folder = Get-Item $Path $FolderFullName = $Folder.FullName Resolve

List folders at or below a given depth in Powershell

戏子无情 提交于 2020-02-20 21:36:18
问题 I have a directory which contains a lot of folders. I want to list all folder (path) that go deeper than 2 levels. So in below case folder 1 & 2. Directory/folder1 Directory/folder1/test1/test/testsub Directory/folder1/test2 Directory/folder1/test3 Directory/folder2/blablabla/bla/1 Directory/folder3/test Directory/folder4/test Directory/folder5/test I was trying the following: $Depth = 3 $Path = "." $Levels = "\*" * $Depth $Folder = Get-Item $Path $FolderFullName = $Folder.FullName Resolve

List folders at or below a given depth in Powershell

若如初见. 提交于 2020-02-20 21:33:50
问题 I have a directory which contains a lot of folders. I want to list all folder (path) that go deeper than 2 levels. So in below case folder 1 & 2. Directory/folder1 Directory/folder1/test1/test/testsub Directory/folder1/test2 Directory/folder1/test3 Directory/folder2/blablabla/bla/1 Directory/folder3/test Directory/folder4/test Directory/folder5/test I was trying the following: $Depth = 3 $Path = "." $Levels = "\*" * $Depth $Folder = Get-Item $Path $FolderFullName = $Folder.FullName Resolve

Understand and avoid infinite recursion R

痴心易碎 提交于 2020-02-20 08:46:04
问题 I can't find any advice on how to deal with infinite recursion in R. I would like to illustrate my problem in the most general way so that others can benefit from it. Feel free to edit it. I used to run a double for loop for (k in 1:n){ for (i in 1:m){ f[i,,k] <- an expression that depends on g[i-1,,k] g[i,,k] <- a mixture of g[i-1,,k] and f[i,,k]}} This was running fine but now I hoped to find the k that would best fit my criterion. So I decided to turn it into a function so that i could

Can Python generate a random number that excludes a set of numbers, without using recursion?

被刻印的时光 ゝ 提交于 2020-02-18 05:41:11
问题 I looked over Python Docs (I may have misunderstood), but I didn't see that there was a way to do this (look below) without calling a recursive function. What I'd like to do is generate a random value which excludes values in the middle. In other words, Let's imagine I wanted X to be a random number that's not in range(a - b, a + b) Can I do this on the first pass, or 1. Do I have to constantly generate a number, 2. Check if in range() , 3. Wash rinse ? As for why I don't wish to write a

Using os.walk in order to recurse into folders in Python

谁都会走 提交于 2020-02-15 20:20:26
问题 I have the following code as part of a Python file, and it traverses .py files in the folder called controllers, and preforms some operations with them. This is my prototype, but now I want to use os.walk to recurse into the folders. controller_folder_path = "applications/%s/controllers/*.py" % application_name for module_path in glob.glob(controller_folder_path): print module_path Any help? 回答1: import os controller_folder_path = "applications/%s/controllers" % application_name for root,

Recursively rename files to ASCII Standard

依然范特西╮ 提交于 2020-02-15 10:05:10
问题 So we have a problem where we need to crawl through hundreds of thousands of images and rename all of them to comply with ASCII standards. After doing a lot of research online, we found this handy piece of code: mv 'file' $(echo 'file' | sed -e 's/[^A-Za-z0-9._-]/_/g') sourced from: How to remove invalid characters from filenames I have tried merging it into a recursive find command, to be run whilst in our main images directory: find . -print0 | xargs -0 mv $(echo | sed -e 's/[^A-Za-z0-9._-]

Extract set of leaf values found in nested dicts and lists excluding None

纵然是瞬间 提交于 2020-02-14 02:19:48
问题 I have a nested structure read from YAML which is composed of nested lists and/or nested dicts or a mix of both at various levels of nesting. It can be assumed that the structure doesn't contain any recursive objects. How do I extract from it the leaf values only? Also, I don't want any None value. The leaf values contain strings which is all I care for. It's okay for recursion to be used, considering that the maximum depth of the structure is not large enough to exceed stack recursion limits

Why does this recursive copy function copy all files into every directory above the correct one?

爱⌒轻易说出口 提交于 2020-02-07 09:08:34
问题 I write a function to copy files from directory A to directory B recursive. The code is like this: import os import shutil import sys from os.path import join, exists def copy_file(src, dest): for path, dirs, files in os.walk(src, topdown=True): if len(dirs) > 0: for di in dirs: copy_file(join(path, di), join(dest, di)) if not exists(dest): os.makedirs(dest) for fi in files: shutil.copy(join(path, fi), dest) In my test, the input args are like this: src = d:/dev and it have one sub directory

How to rewrite a program to use recursion?

折月煮酒 提交于 2020-02-07 05:25:08
问题 Just started to deal with recursion - I don’t understand everything in it yet. I think that i don't use a basic conditional, but i don't have any idea how to write it. The program itself works and execute everything i need, but there is no recursion. The idea of the program is that there is a list in which is neede to sum of every x'th number in the list - x here as a step. If x = 0, then the sum is automatically zero. If x is out of range, then the sum is also 0 def sum_elements(nums, x) ->