recursion

问题 public class Demo { static int i=0; public static void main(String args[]) { System.out.println("Hello"+(i++)); main(args); } } In this program I am calling main with instance variable. It runs properly upto some point but after some Hello prints it gives StackOverFlow Exception. So i put int to find how many times it gets printed. I run this program it gives Exception after i=4158 . But I run it several times it gives Exception at different value of i like 4155,4124,4154 etc. As I know here

问题 Im having trouble converting a working solution that takes a directory folder as an input and outputs the filenames and other file attributes of files container in the folder into an excel spreadsheet to a recursive solution that also outputs the files contained in subfolders. I would greatly appreciate any help! Sub GetFileList() Dim strFolder As String Dim varFileList As Variant Dim FSO As Object, myFile As Object Dim myResults As Variant Dim l As Long ' Get the directory from the user With

问题 Im having trouble converting a working solution that takes a directory folder as an input and outputs the filenames and other file attributes of files container in the folder into an excel spreadsheet to a recursive solution that also outputs the files contained in subfolders. I would greatly appreciate any help! Sub GetFileList() Dim strFolder As String Dim varFileList As Variant Dim FSO As Object, myFile As Object Dim myResults As Variant Dim l As Long ' Get the directory from the user With

问题 I am having problems with the level order traversal of my binary tree whilst using recursion. I am inputing the following values: 50,60,70,30,20,10 Here is the code I am using: public void levelOrder(Node localRoot){ if(localRoot != null){ if(localRoot.leftChild != null && localRoot.rightChild != null){ System.out.print(localRoot.iData + " "); System.out.print(localRoot.leftChild.iData + " "); System.out.print(localRoot.rightChild.iData + " "); levelOrder(localRoot.leftChild); levelOrder

问题 I am building a multi-select checkdown group item list. The goal is to have only ONE active group at a time. So the user can select parents - but if they select a child item, that child group becomes the focus and the selected parents become unchecked. <div class="checkboxhandler"> <input type="checkbox" checked={{@item.checked}} onclick={{action @onClick @item.id}} > <label>{{@item.label}} -- checked: {{@item.checked}}</label> {{#if @item.children}} {{#each @item.children as |child|}}

问题 I'm wondering how you would make the recursive calls in Strassen's algorithm, and where exactly they're required. I understand that the 7 multipliers is more efficient than the 8 we would have otherwise, but I'm confused as to how these multipliers are calculated recursively. In particular, if we are following the divide and conquer paradigm, exactly which part of the matrices are we "dividing" and how are we going about doing that until we get to a base case in which we can conquer the

问题 I need help regarding recursive function We have a category table contains category_id,category_name and parent_id: category_id category_name parent_id ------------+--------------+---------- 1 Agriculture 0 2 Appearl & Fashion 0 3 Chemicalas 0 4 Plastic & Plastic Products 0 5 Automobile 0 14 Coconut Shell Products 1 15 Nuts & Kernels 1 16 Plant & Animal Oil 1 17 Potpourri 1 18 Raw Cotton & Cotton Waste 1 19 Rice 1 20 Tea 1 21 Seeds 1 22 Vegetable 1 23 White Rice 19 24 Green Rice 19 25 Basmati

问题 I wrote the following code in scheme today, but the evaluation is wrong. Please don't tell me I suck at programming, I understand that this is a classic recursion problem, but I am having trouble with it: (define (towers-of-hanoi n source temp dest) (if (= n 1) (begin (display "Move the disk from ") (display source) (display " to " ) (display dest) (newline)) (begin (towers-of-hanoi (- n 1) source temp dest) (display "Move the disk from ") (display source) (display " to ") (display dest)

问题 I'm writing a program that determines if a string is a palindrome recursively. I've decided to try and use regex, but I'm having a bit of trouble understanding the syntax. What I need to do is compare the first and last char to see if they are identical. How can I go about doing this? Thanks! EDIT: I found this helpful: AirSource Ltd's answer to Degvik's question 回答1: Yes, you can determine using regex if the first and last characters are the same: str.matches("(.).*\\1") This uses a "back

问题 Would like to do the following by recursion so that I can vary the number of 'for' loops: n = 5 out = [] for i in range(n): for j in range(i,n): for k in range(j,n): out.append([i,j,k]) To return out = [[0 0 0] [0 0 1] [0 0 2] [0 0 3] [0 0 4] [0 1 1] [0 1 2] [0 1 3] [0 1 4] [0 2 2] [0 2 3] [0 2 4] [0 3 3] [0 3 4] [0 4 4] [1 1 1] [1 1 2] [1 1 3] [1 1 4] [1 2 2]...] e.g. def Recurse(n, p): # where p is the number of for loops some magic recursion return out I've had a look at some of the other