rectangles

问题 The next code lets you draw Rectangles in the Form with mouse clics. Why not, or how can be draw over a PictureBox? Public Class Form1 Dim SelectRect As Rectangle = New Rectangle() Dim ps As Point = New Point() Dim pe As Point = New Point() This catch the first click, starting point or corner of the rectangle Private Sub Form1_MouseDown(ByVal sender As Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles Me.MouseDown SelectRect.Width = 0 SelectRect.Height = 0 SelectRect.X = e.X

问题 I want to enclose the pair of checkboxes and the radio buttons here: ...in a rectangle or "bounding box" so that it look something like this: ...but less ugly, of course. How can I do that with the following XML as a starting point: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" android:paddingLeft="@dimen/activity

问题 I want to enclose the pair of checkboxes and the radio buttons here: ...in a rectangle or "bounding box" so that it look something like this: ...but less ugly, of course. How can I do that with the following XML as a starting point: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" android:paddingLeft="@dimen/activity

问题 I'm student at university and I have a specific question. Presently I display a white rectangle in center of a window with pygame above a black background. But presently I would like to blinking my white rectangle at a specific frequency, and it's why a I need help. Presently I implement that: import pygame, sys from pygame.locals import * def main(): pygame.init() fenetre = pygame.display.set_mode((500,400),0,32) black=(0,0,0) white=(255,255,255) fenetre.fill(black) pygame.draw.rect(fenetre,

问题 My code prints a sets of (X,Y) coordinates in 2D space in the range [0,1]. void Rect_Print() { cout << "In counter-clockwise fashion" << endl; cout << "#Rectangle ( x0, y0) ( x1, y1) " << endl; for (int b=0; b<Rect_Count; b++) { double Area = (Rect[b].x0 - Rect[b].x1) * (Rect[b].y0 - Rect[b].y1); cout << fixed << setprecision(4) << (b+1) << " (" << Rect[b].x0 << "," << Rect[b].y0 << ") (" << Rect[b].x1 << "," << Rect[b].y1 << ")" << endl; } cout << "Number of divisions (N = 3j-2) = " << Rect

问题 I'm looking for an algorithm here, independent of specific programming language. The problem: We have a 2-dimensional display area (think simple buffer of pixels). Periodically, some of the pixels are changed. We need to find a set of rectangles that encapsulate all changed pixels. It would be trivial, but undesirable, to compute a single, potentially large, rectangle that encapsulates all changed pixels. We would rather have multiple, smaller, tight-fitting rectangles down to a specified

问题 I have a rectangle that has a rotation already applied to it. I want to get the the unrotated dimensions (the x, y, width, height). Here is the dimensions of the element currently: Bounds at a 90 rotation: { height 30 width 0 x 25 y 10 } Here are the dimensions after the rotation is set to none: Bounds at rotation 0 { height 0 width 30 x 10 y 25 } In the past, I was able to set the rotation to 0 and then read the updated bounds . However, there is a bug in one of the functions I was using, so

问题 I'm designing a collision detection game tutorial for young adults, so I want this to be as simple as possible to make it easier to explain. The requirements are very simple. The world is 2D and contains only rectangles (of arbitrary sizes). BSP and even quadtrees seems like it would be overkill (again, the emphasis is on simplicity) but I would like something more efficient than brute forcing through all n(n-1)/2 possible collisions. 2D, rectangles only, and simple. Can anyone point to an

问题 For example we have two rectangles and they overlap. I want to get the exact range of the union of them. What is a good way to compute this? These are the two overlapping rectangles. Suppose the cords of vertices are all known: How can I compute the cords of the vertices of their union polygon? And what if I have more than two rectangles? 回答1: There exists a Line Sweep Algorithm to calculate area of union of n rectangles. Refer the link for details of the algorithm. As said in article, there

问题 I'm working on this Python task that I can't figure out. It is the last of 3 functions and the first 2 were much easier to program then this one. The instructions are "Given a message that may contain multiple lines, utilize the split() function to identify the individual lines, and the format() function so that when printed, it draws a box around the message's lines, all centered. Box uses vertical bars & dashes on the sides (|, -), +'s in the corners (+), and there is always a column of