rawstring

问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to

问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to

问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to

问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to

问题 I came across this code snippet in C++17 draft n4713: #define R "x" const char* s = R"y"; // ill-formed raw string, not "x" "y" What is a "raw string"? What does it do? 回答1: Raw string literals are string literals that are designed to make it easier to include nested characters like quotation marks and backslashes that normally have meanings as delimiters and escape sequence starts. They’re useful for, say, encoding text like HTML. For example, contrast "<a href=\"file\">C:\\Program Files\\<

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago . We are doing a school project where we need to explain code line by line. We need to explain the following 3 lines: // TODO: This is where the magic of XOR is happening. Are you able to explain what is going on? for (int i = 0; i < rawString.length(); i++) { thisIsEncrypted.append((char) (rawString

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago . We are doing a school project where we need to explain code line by line. We need to explain the following 3 lines: // TODO: This is where the magic of XOR is happening. Are you able to explain what is going on? for (int i = 0; i < rawString.length(); i++) { thisIsEncrypted.append((char) (rawString

问题 In Computer Science is there any difference between a raw string and an escaped string? For me these two terms appears to be synonym, it means that all the symbols in the string will be treated a literal characters. Am I missing something? 来源： https://stackoverflow.com/questions/59627014/difference-between-escape-strings-and-raw-strings

问题 I know that you can create a multi-line string a few ways: Triple Quotes ''' This is a multi-line string. ''' Concatenating ('this is ' 'a string') Escaping 'This is'\ 'a string' I also know that prefixing the string with r will make it a raw string, useful for filepaths. r'C:\Path\To\File' However, I have a long filepath that both spans multiple lines and needs to be a raw string. How do I do this? This works: In [1]: (r'a\b' ...: '\c\d') Out[1]: 'a\\b\\c\\d' But for some reason, this doesn

问题 C++11 introduced the raw string literals which can be pretty useful to represent quoted strings, literals with lots of special symbols like windows file paths, regex expressions etc... std::string path = R"(C:\teamwork\new_project\project1)"; // no tab nor newline! std::string quoted = R"("quoted string")"; std::string expression = R"([\w]+[ ]+)"; This raw string literals can also be combined with encoding prefixes ( u8 , u , U , or L ), but, when no encoding prefix is specified, does the