random

问题 I am building a program using various methods of generating psudo random numbers. With reasonable results. I of course get better results (statistically speaking), if I use either the inbuilt random number generator in visual C#, or some other formal psudo random code where the method is not known to me. This is not my question. My question is, given any of the methods used, and given the fact that any computer generated random number is done according to a specified formula and code logic,

问题 In my postgres database, I have the following relationships (simplified for the sake of this question): Objects (currently has about 250,000 records) ------- n_id n_store_object_id (references store.n_id, 1-to-1 relationship, some objects don't have store records) n_media_id (references media.n_id, 1-to-1 relationship, some objects don't have media records) Store (currently has about 100,000 records) ----- n_id t_name, t_description, n_status, t_tag Media ----- n_id t_media_path So far, so

问题 So I have an enum here: public enum Party { DEMOCRAT, INDEPENDENT, REPUBLICAN } and I currently have this, one of three classes: public class ElectoralCollege { public static final String FILE = "Electoral201X.txt"; private ArrayList <State> stateVotes; Random rand = new Random(); public ElectoralCollege() throws IOException { stateVotes = new ArrayList<State>(); assignStates(); } public void assignStates() throws IOException { File f = new File(FILE); Scanner fReader = new Scanner(f); while

问题 How to generate 10 random numbers from normal distribution using latin hypercube sampling technique in python 2.7? The range of the random number should be 5 to 14. I tried following import random from random import randint iter = 10 segSize = 1 / iter for i in range(iter): segMin = i * segSize point = segMin+ (random.normalvariate(7.5,1)*segSize) pointValue = (point * (14 - 5)) + 4 print point print pointValue Thanks 回答1: Try this: def rand: import random from random import randint iter = 10

问题 How to generate 10 random numbers from normal distribution using latin hypercube sampling technique in python 2.7? The range of the random number should be 5 to 14. I tried following import random from random import randint iter = 10 segSize = 1 / iter for i in range(iter): segMin = i * segSize point = segMin+ (random.normalvariate(7.5,1)*segSize) pointValue = (point * (14 - 5)) + 4 print point print pointValue Thanks 回答1: Try this: def rand: import random from random import randint iter = 10

问题 i have a array and i need to do it randomly show the output by probability below are my code var shirts = [ ["images/fantastic-logo.png","12.65"], ["images/fantastic-word.png","10.00"], ["images/free-product.png","15.50"] ]; var pos = Math.floor((Math.random() * shirts.length) + 0); $("#image").html($("<img/>").attr("src", shirts[pos][0])); $(".price").html("$" + shirts[pos][1]); i have do the basic math.random() to make it random show the image, now i need to make it show with probability,

问题 I have three main constraints for int8 key generation: Keys need be unpredictably random Number of rows created should not be calculable Order of row creation should not be calculable Keys need to be unique across the entire db Future table merges should not require changing keys Future Table-Per-Class superclass additions should not require changing keys Keys need to be bounded These keys will be base58 encoded in various places such as URLs Range will be narrower at first but should be

问题 i have a array and i need to do it randomly show the output by probability below are my code var shirts = [ ["images/fantastic-logo.png","12.65"], ["images/fantastic-word.png","10.00"], ["images/free-product.png","15.50"] ]; var pos = Math.floor((Math.random() * shirts.length) + 0); $("#image").html($("<img/>").attr("src", shirts[pos][0])); $(".price").html("$" + shirts[pos][1]); i have do the basic math.random() to make it random show the image, now i need to make it show with probability,

问题 I want to continuously generate a random number between 1 to 10 but stop if it generates the number 9 or 10. I'm using this to get the random number import random for x in range(1): random.randint(1,10) However, I don't know how to continue from there besides if range<9 : print("Again") elif: for x in range(1): random.randint(1,10) else: print("End") 回答1: >>> from random import randint >>> while True: ... n = randint(1,10) ... if n in range(1,9): ... print(n) ... else: ... break ... 6 1 5 7

问题 I'm writing a program which is intended to compare the numbers in 2 arrays and output the number of matches that there are. RandomNumber.h #pragma once #include <iostream> #include <cstdlib> #include <ctime> class RandomNumber { public: void randomNumber(); int actualRandomNumber; }; RandomNumber.cpp #include "RandomNumberGenerator.h" void RandomNumber::randomNumber() { actualRandomNumber = rand() % 66 + 1; } Game.h #include "RandomNumberGenerator.h" class Game { private: int randomNumbers[6]