r

问题 I am trying to build a r shiny app where the user will get to know about each function in just a click. For this I have coded below in R . But print(??input$A) is not working. Could anyone help please library(shinydashboard) library(readxl) out <- data.frame(baseFns = ls('package:base')) ui <- dashboardPage( dashboardHeader(title = "Loading data"), dashboardSidebar(sidebarMenu( menuItem("Analysis", tabName = "Analysis", icon = icon("chart-bar")) )), dashboardBody( tabItems(tabItem(tabName =

问题 Here is a simplified and testable example: dataset <- data.frame( emp_month = c("January","March","April","May","December"), salary = c(623.3,515.2,611.0,729.0,843.25)) library(ggplot2) ggplot(dataset)+ geom_boxplot(aes(x = sort(factor(emp_month)), y = salary))+ geom_point(aes( x = sort(factor(emp_month)), y=salary))+ facet_grid(. ~ sort(factor(emp_month)),space = "free", scales="free",margins = T) Error Description: I can write this code library(ggplot2) MesDeConclusao = factor

问题 I have used sprintf and formatC to take a double value and round it to two decimal places. However, when I go to use it in ggplot and ggplotly, it makes my visuals act out. Dput: structure(list(Date = structure(c(18328, 18329, 18330, 18331, 18332, 18333), class = "Date"), State = c("Louisiana", "Louisiana", "Louisiana", "Louisiana", "Louisiana", "Louisiana"), variablename1 = c(0, 0, 1, 1, 6, 14), variablename2 = c(5, 5, 5, 11, 37, 37), death = c(0, 0, 0, 0, 0, 0), variablename3 = c(5, 5, 6,

问题 Here is a simplified and testable example: dataset <- data.frame( emp_month = c("January","March","April","May","December"), salary = c(623.3,515.2,611.0,729.0,843.25)) library(ggplot2) ggplot(dataset)+ geom_boxplot(aes(x = sort(factor(emp_month)), y = salary))+ geom_point(aes( x = sort(factor(emp_month)), y=salary))+ facet_grid(. ~ sort(factor(emp_month)),space = "free", scales="free",margins = T) Error Description: I can write this code library(ggplot2) MesDeConclusao = factor

问题 --- title: "esc" output: html_document --- ```{r setup, include=FALSE} knitr::opts_chunk$set(echo = TRUE) ``` A. An amount between $5 and $10. B. An amount between \$5 and \$10. C. An amount between \\$5 and \\$10. X. An equation $1 and 1 = 2$. Y. An equation \$1 and 1 = 2\$. Z. An equation \\$1 and 1 = 2\\$. I've got a similar, but different question here. Please comment if I need to add clarification to differences. I'm asking two different questions and hope that's obvious. Anyways, the

问题 Been stuck on this for a while now. Looked everywhere for an answer, but I can't seem to find anything on Stack. Any help you all can give that would be very appreciated. My main issue is that I need to import many, many netcdf4 files, create raster bricks of each, then combine many bricks to make a "master brick" per variable. To give you a clearer example, I have 40 years (netcdf = 40) of many climate variables (n = 15) that are at a daily resolution. The goal is to aggregate to monthly,

问题 I found a lot of SO question and answers addressing break and gaps in axis. But most of them are of low quality (in an SO meaning) because of no example code, no picture or to complex codes. This is why I asking. I try to use library(plotrix) . If there is a solution without it and/or another library it would be ok for me, too. This is a normal R-barplot. barplot(c(10,20,500)) To break the axis and add gap I tried this. gap.barplot(c(10,20,500),gap=c(50,400), col=FALSE) The result is not

问题 I found a lot of SO question and answers addressing break and gaps in axis. But most of them are of low quality (in an SO meaning) because of no example code, no picture or to complex codes. This is why I asking. I try to use library(plotrix) . If there is a solution without it and/or another library it would be ok for me, too. This is a normal R-barplot. barplot(c(10,20,500)) To break the axis and add gap I tried this. gap.barplot(c(10,20,500),gap=c(50,400), col=FALSE) The result is not

问题 After I scraped a list of names, I have the following name in R: DAPHN\303\211 DE MEULEMEESTER If I use the function tolower, all the letters are set to lowercase, but not the special characters. What is the best way to achieve this? 回答1: The reason is that your locale is C. Non-ASCII special characters and their letter-case classifications are not recognized under that locale. You should be able to get it to work by switching to a UTF-8 locale: Sys.setlocale(locale='C'); ## [1] "C/C/C/C/C/en

问题 After I scraped a list of names, I have the following name in R: DAPHN\303\211 DE MEULEMEESTER If I use the function tolower, all the letters are set to lowercase, but not the special characters. What is the best way to achieve this? 回答1: The reason is that your locale is C. Non-ASCII special characters and their letter-case classifications are not recognized under that locale. You should be able to get it to work by switching to a UTF-8 locale: Sys.setlocale(locale='C'); ## [1] "C/C/C/C/C/en