r-corrplot

问题 I am trying to recreate someone's image using corrplot. This is the original image I am trying to re-create: I use the following R-code: corrplot(as.matrix(rgs), method="circle", type="upper", col=brewer.pal(n=8, name="PuOr"), tl.col="black", tl.srt=45, p.mat = as.matrix(pvalues), sig.level = 0.05, insig = "blank") Which gives me this: The problem I have is that the colour as well as the size of the circles in my plot are based on the correlations, but in the original image above the colour

问题 Does anyone have a method to adorn an R corrplot correlation plot with a dendrogram? 回答1: The closest solution I know of is to use a heatmap on a correlation matrix, for example you could also use gplots::heatmap.2. Here is how to do it using the heatmaply R package, which also offers an interactive interface where you can zoom-in and get a tooltip when hovering over the cells: # for the first time: # install.packages("heatmaply") library(heatmaply) my_cor <- cor(mtcars) heatmaply_cor(my_cor)

问题 Does anyone have a method to adorn an R corrplot correlation plot with a dendrogram? 回答1: The closest solution I know of is to use a heatmap on a correlation matrix, for example you could also use gplots::heatmap.2. Here is how to do it using the heatmaply R package, which also offers an interactive interface where you can zoom-in and get a tooltip when hovering over the cells: # for the first time: # install.packages("heatmaply") library(heatmaply) my_cor <- cor(mtcars) heatmaply_cor(my_cor)

问题 I am trying to use grid.arrange to combine multiple types of graph/table, one of which is a correlation matrix using corrplot . Is there a way to convert a corrplot to a grob or export/import as an image compatible with grid.arrange ? Since the other plots I'm combining are from ggplot and tableGrob, I can't seem to use par(mfrow = c(2, 2)) or layout(matrix(1:2)) as suggested in other posts. P1 <- corrplot(PANAcor, order="hclust", addgrid.col = "gray", type="full", col = col2(50), tl.cex=1.5,

问题 I have a simple 8 by 8 matrix M <- matrix(rnorm(64), nrow=8, ncol=8) How should I transform it to plot it with library(corrplot) ? Without transformation the error is: corrplot.mixed(M) Error in corrplot(corr, type = "upper", method = upper, diag = TRUE, tl.pos = tl.pos, : The matrix is not in [-1, 1]! which I guess would assume that the matrix should be [-1, 1]? 回答1: Just indicate that it is not a correlation matrix: library(corrplot) corrplot(M, is.corr = FALSE, method = "square") 来源： https

问题 I have a time series data (in day format) of 5 places for 15 days stored as a matrix . The structure of data is meter_daywise<-structure(c(24.4745528484842, 21.5936510486629, 58.9120896540103, 49.4188338105575, 568.791971631185, 27.1682608244523, 23.3482757939878, 74.710966227615, 82.6947717673258, 704.212340152625, 23.7581651139442, 21.154634543401, 64.9680107059625, 420.903181621575, 672.629513512841, 128.22871420984, 601.521395359887, 74.6606087800009, 335.87599588534, 576.451039365565,

问题 I like to use correlation plot using corrplot function with correlation coefficients printed in the cells (using addCoef.col and addCoefasPercent = TRUE ). I also like to remove the insignificant correlations from the plot (using insig = "blank" ). The problem is that this only works for the background color, but not for the coefficient itself, so the coefficient itself is still printed! See: set.seed(123) par(cex=0.8) # trick for cor. coef font size, see http://stackoverflow.com/q/26574054

问题 I am using the following with corrplo t: require("corrplot") ## needs the corrplot package corrplot(cor(lpp_axis1, lpp_axis2), method=c("number"), bg = "grey10", addgrid.col = "gray50", tl.offset = 2, tl.cex=2, tl.col = "black", col = colorRampPalette(c("yellow","green","navyblue"))(100)) This is created with a csv file available here. The graph is fine and I can adjust the cl labels all I want. I've tried adjusting the labels on x and y axis with no impact. I looked at changing mar - yet I

问题 Hi I want to customize the plot to something like this: -I want to have some straight line inside the plot and want to change the legend to something in the left side rather than the normal legend in right side. Also add some texts beside the variables (categorize). I have tried ggcorrplot, ggcorr, corrplot, ggplot to make this, but still can't find the solution. Anyone can help? Thanks. Sample plot-How to make it? ggcorr(data = NULL, cor_matrix = corr, nbreaks = 4, hjust = 1, size = 3, color

问题 I would like to return the significant matches from the following result shown in Fig. 1 library("corrplot") M <- cor(mtcars) # http://www.sthda.com/english/wiki/visualize-correlation-matrix-using-correlogram cor.mtest <- function(mat, ...) { mat <- as.matrix(mat) n <- ncol(mat) p.mat<- matrix(NA, n, n) diag(p.mat) <- 0 for (i in 1:(n - 1)) { for (j in (i + 1):n) { tmp <- cor.test(mat[, i], mat[, j], ...) p.mat[i, j] <- p.mat[j, i] <- tmp$p.value } } colnames(p.mat) <- rownames(p.mat) <-