query-by-example

Mixing Likes and Equals with NHibernate Query-By-Example?

由 安稳与你 提交于 2019-12-23 03:37:23
问题 I have a rather large SOA solution and a newly added service queries approx 9.8 million records using NHibernate's Query By Example. Thus far the performance has been terrible, and a profile on the database shows the query as: exec sp_executesql N'SELECT this_.Id as Id3_0_, this_.ESIID as ESIID3_0_, this_.ADDRESS as ADDRESS3_0_, this_.ADDRESS_OVERFLOW as ADDRESS4_3_0_, this_.CITY as CITY3_0_, this_.STATE as STATE3_0_, this_.ZIP5 as ZIP7_3_0_, this_.ZIP4 as ZIP8_3_0_, this_.DUNS as DUNS3_0_,

How to secure Hibernate QBE query

由 僤鯓⒐⒋嵵緔 提交于 2019-12-13 13:48:08
问题 By the moment, I know four kinds of doing transactions with hibernate: Using objects Using HQL Using DB-specific SQL Using criteria (QBE) Well, regarding how strong are they against injections, I think these are (correct me if I'm wrong): Secure, because the internal SQL call is parameterized. Secure if the query is parameterized, insecure otherwise. Same as #2 but not as portable. Insecure? My question is about #4, Query by Example, because i've found it is also vulnerable. Example: Account

how to search an Id using hibernate query by example?

由 北城以北 提交于 2019-12-11 02:06:08
问题 hi i have the following class public class Label { private Long TableId; private Long Id; private String LabelName; //getters and setters for corresponding fields } i was supposed to search on multiple fields dynamically i came across hibernate query by example construct my code looks like some thing Label bean =new Label(); if(Id!=null) { bean.setId(Id); } if(LabeName!=null) { bean.setLabelName(LabelName) } System.out.println(bean.toString()); Example exampleObject=Example.create(bean)

Are there any possible ways to ignore all paths of JPA Example Matcher

由 大憨熊 提交于 2019-12-10 21:18:22
问题 I'm new to Spring JPA. I has two questions about Example and ExampleMatcher API. Are there any ways to ignore all paths except some paths which I set matchers. Or are there any ways to ignore all paths if Example object's path has null value. It is quite annoying to set all path names like below: ExampleMatcher<Product> matcher =ExampleMatcher.matching().ignorePaths("field_a", "field_b"); How to match joined column using Example. For example. Product entity has User entity field as @ManyToOne

Hibernate: Query By Example involving one-to-many relationship

由 对着背影说爱祢 提交于 2019-12-08 18:27:26
I've recently started playing with the query by example component of the Criteria API and have run into a strange issue - an org.hibernate.QueryException is thrown when trying to perform a search. My scenarios is as follows: I have a class A, which as one of its properties has a set of instances of class B (Set< B> listOfBs). This is mapped as a one-to-many relationship in A. I was hoping to set a criteria query on an example instance of B, for example specifying all B's with a property value of "somevalue", and then apply that criteria to find all A's that have such a B in their set. This is

Hibernate: Query By Example involving one-to-many relationship

由 心不动则不痛 提交于 2019-12-08 04:32:44
问题 I've recently started playing with the query by example component of the Criteria API and have run into a strange issue - an org.hibernate.QueryException is thrown when trying to perform a search. My scenarios is as follows: I have a class A, which as one of its properties has a set of instances of class B (Set< B> listOfBs). This is mapped as a one-to-many relationship in A. I was hoping to set a criteria query on an example instance of B, for example specifying all B's with a property value

Query by Example Spring Data - In Clause?

由 那年仲夏 提交于 2019-12-08 04:04:00
问题 As per Spring Docs, I can write exact matching only for QBE. I need exact matching only but among a set of values (IN clause of query). e.g. Person p = new Person(); p.setId(); // need to match among set of ids. Example.of(p); Is this somehow achievable with QBE or am I totally down the wrong path? Something like : Page<S> findByIdIn(List<Integer> ids, Example<S> e, Pageable p) best of both worlds? What I really need, dynamic query based on multiple fields (in possible combinations, say id in

Query by Example Spring Data

由 你离开我真会死。 提交于 2019-11-30 19:42:01
问题 I have domain object Person with date fields: public class Person { @Id private Long id; private Date date Build example like this: Person person = new Person(); person.setSomeOtherFields("some fields"); Example<Person> example = Example.of(person); How i can create example query with date range (search entity contains date greater or equal from some date and less or equal some another date)? 回答1: The Spring Data JPA query-by-example technique uses Example s and ExampleMatcher s to convert

Spring Boot & JPA: Implementing search queries with optional, ranged criteria

由 亡梦爱人 提交于 2019-11-26 16:30:56
This is an SSCCE , shows research, isn't a dupe and is on topic!!! Spring Boot REST service and MySQL here. I have the following Profile entity: @Entity @Table(name = "profiles") public class Profile extends BaseEntity { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Long id; @Column(name = "profile_given_name") private String givenName; @Column(name = "profile_surname") private String surname; @Column(name = "profile_is_male") private Integer isMale; @Column(name = "profile_height_meters", columnDefinition = "DOUBLE") private BigDecimal heightMeters; @Column(name = "profile

Spring Boot & JPA: Implementing search queries with optional, ranged criteria

由 杀马特。学长 韩版系。学妹 提交于 2019-11-26 04:48:30
问题 This is an SSCCE, shows research, isn\'t a dupe and is on topic!!! Spring Boot REST service and MySQL here. I have the following Profile entity: @Entity @Table(name = \"profiles\") public class Profile extends BaseEntity { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Long id; @Column(name = \"profile_given_name\") private String givenName; @Column(name = \"profile_surname\") private String surname; @Column(name = \"profile_is_male\") private Integer isMale; @Column(name = \
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