quartz-scheduler

I'm reading the Spring 3.0 doc s regarding scheduling. I'm leaning towards Spring's JobDetailBean for Quartz. However, the @Scheduled annotation has captured my eye. It appears this is another way of scheduling task using the Spring Framework. Based on the docs, Spring provides three way of scheduling: @Scheduled Via Quartz Via JDK Timer I have no interest in the JDK Timer. Why should I choose @Scheduled over Quartz? (When I mention Quartz I mean using Spring's bean wrapper for Quartz). Let's say my use case is complex enough that I will be communicating to a third-party web service to import

How do you set up a jobstore with Quartz.net. The tutorial they have on the site is not that of help for me. In this page though there are steps http://quartznet.sourceforge.net/tutorial/lesson_9.html I am not able to get how to set this one org.quartz.jobStore.type = Quartz.Impl.AdoJobStore.JobStoreTX, Quartz Thanks Here's an adapted example of programmatic configuration from Quartz.NET's example 13: NameValueCollection properties = new NameValueCollection(); properties["quartz.scheduler.instanceName"] = "TestScheduler"; properties["quartz.scheduler.instanceId"] = "instance_one"; properties[

Is it possible to crate a job that will trigger immediately ? when i want the job to be triggres now i builed a cron expression string with the current date and time - i think it's too complicated, is there another way to trigger the job immediately ? Thank's In Advance. All the Jobs registered in the Quartz Scheduler are uniquely identified by the JobKey which is composed of a name and group . You can fire the job which has a given JobKey immediately by calling triggerJob(JobKey jobKey) of your Scheduler instance. //Create a new Job JobKey jobKey = JobKey.jobKey("myNewJob", "myJobGroup");

I'm trying to build a quartz scheduler ejb app and have it deployed on JBOSS EAP 6.4. Additionally, I'm trying to do so using quartz JDBC jobstore using an Oracle 11g database. Now, the problem is that whenever I try to schedule a job, I get this exception : 18:45:01,024 ERROR [org.jboss.msc.service.fail] (ServerService Thread Pool -- 50) MSC000001: Failed to start service jboss.deployment.unit."com.hp.heimdall.jar".component.QuartzBootstraper.START: org.jboss.msc.service.StartException in service jboss.deployment.unit."com.hp.heimdall.jar".component.QuartzBootstraper.START: java.lang

I need help in retrieving the data from database using Quartz. I am reading the hibernate properties from config.xml in the main class and using those properties I tried to retrieve the data from my job class (Quartz Process.java) which is getting Null Pointer Exception. Please help me in resolving the issue. Thanks and advance This is my main class: @Component("TestProgram") public class TestProgram { static ClassPathXmlApplicationContext applicationContext=null; public void testMethod() throws SchedulerException { JobDetail job = new JobDetail(); job.setName("Retriving The Master Details");

I need a cron expression which will fire every day at 12 pm starting from jan 25 2016. This is what I came up with: 0 0 12 25/1 * ? * but after jan 31, the next firing time is feb 25. Is there a cron expression expression for doing this? If not what can I use? Assuming that after January 25th you want to run this process forever after (i.e. 2032, when probably the server will be already substituted), I would do it with three expressions: 0 0 12 25-31 1 * 2016 command # Will run the last days of Jan 2016 after the 25th 0 0 12 * 2-12 * 2016 command # Will run the rest of the months of 2016 0 0

I am using spring version 4.0.6 and quartz with it, version 1.8.6. The problem is, when I try to use a configuration class instead of xml (with @Configuration annotation), I am not able to set the cron expression with the method CronTriggerBean ctBean = new CronTriggerBean(); ctBean.setCronExpression("0 35 15 ? * MON *"); Please tell me if there is a version compatibility issue. The exact error is this: The method setCronExpression(String) is undefined for the type CronTriggerBean Consider using CronTriggerFactoryBean : @Bean public CronTriggerFactoryBean cronTriggerFactoryBean() {

i need your help to learn Quartz.Net. But every sample is the same as each other. i want to startTime: 07.03.2012 13:28:10 but not working. Not return error code.how to start this time? DateTime startdate = DateTime.Parse("07.03.2012 10:28:10", culture, System.Globalization.DateTimeStyles.AssumeLocal); // DateTime startdate = Convert.ToDateTime("07.03.2012 09:46:10", culture); //DateTime zaman = new DateTime(2012, 3,6,17, 12, 11); DateTime parsedStartTime = DateTime.SpecifyKind(startdate, DateTimeKind.Utc); DateTime localStartTime = parsedStartTime.ToLocalTime(); Trigger trigger = new