python-3.6

Sending and receiving frames over the same websocket connection without blocking

删除回忆录丶 提交于 2021-02-11 12:45:54
问题 Sorry for the long post but I've been poking at this for over a week so I've tried a lot of different stuff. I know Python well enough but I don't have any experience with asyncio or non-blocking functions in Python. I'm writing an API library/module/package/whatever for a web service that requires a websocket connection. There are many incoming messages to act on, and some control-related (web app level, not websocket control messages) that I need to send on occasion. I can easily receive

__classcell__ generates error in Python 3.6 when the metaclass calls multiple super().__new__ from inherited class

送分小仙女□ 提交于 2021-02-10 14:39:16
问题 Here is an executable code which works in Python 2.7 but results in an error in Python 3.6: import six class AMeta(type): def __new__(cls, name, bases, attrs): module = attrs.pop('__module__') new_attrs = {'__module__': module} classcell = attrs.pop('__classcell__', None) if classcell is not None: new_attrs['__classcell__'] = classcell new = super(AMeta, cls).__new__( cls, name, bases, new_attrs) new.duplicate = False legacy = super(AMeta, cls).__new__( cls, 'Legacy' + name, (new,), new_attrs

ModuleNotFoundError: No module named 'six'

人走茶凉 提交于 2021-02-10 14:24:26
问题 I am trying to setup lamp server on my Fedora 27 . Referring this site, I am following every step, but running this command firewall-cmd --permanent --add-service=http , here are the following errors I get Traceback (most recent call last): File "/usr/bin/firewall-cmd", line 31, in <module> from firewall.client import FirewallClient, FirewallClientIPSetSettings, \ File "/usr/lib/python3.6/site-packages/firewall/client.py", line 29, in <module> import slip.dbus File "/usr/lib/python3.6/site

Pygame sound keeps repeating

狂风中的少年 提交于 2021-02-10 06:44:20
问题 I am trying to play a sound at the end of a game when there is a lose. Previously this code below worked with Python 3.5 but it would abort after it played the sound. I upgraded to python 3.6 and now it just keeps on repeating. How can I play the sound until the end? import pygame def sound(): pygame.mixer.init() sound1 = pygame.mixer.Sound('womp.wav') while True: sound1.play(0) return 回答1: while True is an endless loop: while True: sound1.play(0) The sound will be played continuously. Use

How do I allow for multiple possible responses in a discord.py command?

做~自己de王妃 提交于 2021-02-08 07:01:33
问题 I'm attempting to set up a Discord bot while being relatively new to discord.py (and in reality, Python 3). I want to add the command "greet", which will prompt the user to say "hello" to it. It only responds to "hello", however, when I want it to respond to both "hello" and "Hello". The only things I could think about fixing it was placing them in an or statement, which in theory should've made Python 3 and the bot choose between the two responses (as shown below). @client.event async def on

How do I allow for multiple possible responses in a discord.py command?

做~自己de王妃 提交于 2021-02-08 07:01:20
问题 I'm attempting to set up a Discord bot while being relatively new to discord.py (and in reality, Python 3). I want to add the command "greet", which will prompt the user to say "hello" to it. It only responds to "hello", however, when I want it to respond to both "hello" and "Hello". The only things I could think about fixing it was placing them in an or statement, which in theory should've made Python 3 and the bot choose between the two responses (as shown below). @client.event async def on

Issue with installing geopandas

旧巷老猫 提交于 2021-02-08 02:12:37
问题 I'm trying to install geopandas on my laptop, a Windows 10 version 1709 machine. After executing the pip install geopandas command, I'm getting the message: command python setup.py egg_info failed with error code 1. I already tried to upgrade pip and setuptools, but still no success. I installed Python 3.6. 回答1: Assuming you got something like this error: File "C:\Users\Simon\Anaconda3\lib\site-packages\setuptools\msvc.py", line 848, in __init__ raise distutils.errors.DistutilsPlatformError

APScheduler:Trigger New job after completion of previous job

我只是一个虾纸丫 提交于 2021-02-07 22:38:41
问题 I'm using APScheduler(3.5.3) to run three different jobs. I need to trigger the second job immediately after the completion of first job. Also I don't know the completion time of first job.I have set trigger type as cron and scheduled to run every 2 hours. One way I overcame this is by scheduling the next job at the end of each job. Is there any other way we can achieve it through APScheduler? 回答1: This can be achieved using scheduler events. Check out this simplified example adapted from the

APScheduler:Trigger New job after completion of previous job

巧了我就是萌 提交于 2021-02-07 22:37:31
问题 I'm using APScheduler(3.5.3) to run three different jobs. I need to trigger the second job immediately after the completion of first job. Also I don't know the completion time of first job.I have set trigger type as cron and scheduled to run every 2 hours. One way I overcame this is by scheduling the next job at the end of each job. Is there any other way we can achieve it through APScheduler? 回答1: This can be achieved using scheduler events. Check out this simplified example adapted from the

Recursive logging crashes Interpreter in Python 3

。_饼干妹妹 提交于 2021-02-07 17:22:19
问题 Following code logs an error and calls itself leading to stack overflow and eventually core dump in Python 3.6. >>> import logging >>> def rec(): ... logging.error("foo") ... rec() >>> rec() [1] 101641 abort (core dumped) python3 FTR, this doesn't crash Python 2.7. Attaching the error (condensed) in Python 3.6: ERROR:root:foo ... --- Logging error --- Traceback (most recent call last): ... RecursionError: maximum recursion depth exceeded in comparison ... Fatal Python error: Cannot recover