python-3.3

I have this code (as written in BS4 documentaion): from bs4 import BeautifulSoup When I run the script (using python3) I get the error: ImportError: No module named 'bs4' So installed BeatifulSoup by: sudo pip install BeatifulSoup4 But when I try to run the script again I get the same error. Indeed BS4 is installed in: BeautifulSoup4 in /usr/local/lib/python2.7/dist-packages But I want to install and use it with python3.3 (as there are other module which are not working with python2.7). I tried with: virtualenv --python=/usr/bin/python2.7 /usr/bin/python3.3 and then install BS4 again, but

In Python 3.3, itertools.accumulate() , which normally repeatedly applies an addition operation to the supplied iterable, can now take a function argument as a parameter; this means it now overlaps with functools.reduce() . With a cursory look, the main differences between the two now would seem to be: accumulate() defaults to summing but doesn't let you supply an extra initial condition explicitly while reduce() doesn't default to any method but does let you supply an initial condition for use with 1/0-element sequences, and accumulate() takes the iterable first while reduce() takes the

When I create the Combobox, it has no items in the list. Now when I click on the dropdown button a function is called (via the postcommand option), but once in my function I don't know how to set the values in the listbox of the Combobox. Code something like this: #update list upon drop down self.cbox = Combobox(self, width = 10, postcommand = self.updtcblist) def updtcblist(self): list = self.getPortLst() self.cbox.getlistbox.set(list) #getlistbox doesn't work Thanks, Harvey Answered my own question. I Finally found an example that helped, and got it to work with the following code: #update

I can't quite figure out the code to do this, there are similar posts: Repeating elements in list comprehension but I want to repeat a value in the list by the value in the list In [219]: l = [3,1] [i for x in range(i) for i in l] --------------------------------------------------------------------------- TypeError Traceback (most recent call last) <ipython-input-219-84d6f25dfd96> in <module>() 1 l = [3,1] 2 ----> 3 [i for x in range(i) for i in l] TypeError: 'tuple' object cannot be interpreted as an integer What I want is a list like so: [3,3,3,1] Also can someone explain the error. Note I

seq1_values = [5, 40, 180, 13, 30, 20, 25, 24, 29, 31, 54, 46, 42, 50, 67, 17, 76, 33, 84, 35, 100, 37, 110, 32, 112, 15, 123, 3, 130, 42] def get_num_values(): global seq1_values return len( seq1_values ) def get_values(): global seq1_values for value in seq1_values: yield value yield None def next_value(): return next( next_value.values ) next_value.values = get_values() def main(): numbers = [] value = next_value() while value is not None: numbers.append(value) input_size = len(numbers)-1 for i in range(input_size): print("|", str(input_size).rjust(4), end="") for j in range(input_size):

I know this may be a repeat question, but all the answers I've found on here are WAY above my head. I'm very new at Python, but I would like to use NumPy in IDLE (python 3.3.2). IDLE doesn't seem to access the numpy that comes w/ OSX 10.8 (which is python 2.7). I can't find a Numpy for Python 3 installer for Mac OSX. All of the instructions I've found are very complicated and assume I know a lot more than I do and they still wouldn't help me get it into IDLE even if I could execute them. Can anyone point me to instructions for BEGINNERS on this installation? For example, most start with a