protected

I'm writing a custom view that directly extends android.view.View . If I try to access fields mScrollX or mScrollY , I see an error that the field "cannot be resolved or is not a field." The source code for android.view.View has mScrollX, mScrollY, and similar variables declared protected . How is it that my direct subclass cannot access protected fields of its parent class? (Classes like ScrollView apparently can.) P.S. I realize that I can call getScrollX() , but I want to update these fields; calling setScroll() has side effects that I don't want. It's because they are not part of the

We all know members specified protected from a base class can only be accessed from a derived class own instance. This is a feature from the Standard, and this has been discussed on Stack Overflow multiple times: Cannot access protected member of another instance from derived type's scope ; Why can't my object access protected members of another object defined in common base class? And others. But it seems possible to walk around this restriction with member pointers, as user chtz has shown me : struct Base { protected: int value; }; struct Derived : Base { void f(Base const& other) { //int n

I looked at the previous threads regarding this topic, but they have not helped solve the problem. how to read password protected excel in python How to open write reserved excel file in python with win32com? I'm trying to open a password protected file in excel without any user interaction. I searched online, and found this code which uses win32com.client When I run this, I still get the prompt to enter the password... from xlrd import * import win32com.client import csv import sys xlApp = win32com.client.Dispatch("Excel.Application") print "Excel library version:", xlApp.Version filename

I am confused: I thought protected data was read/writable by the children of a given class in C++. The below snippet fails to compile in MS Compiler class A { protected: int data; }; class B : public A { public: B(A &a) { data = a.data; } }; int main() { A a; B b = a; return 0; } Error Message: Microsoft (R) 32-bit C/C++ Optimizing Compiler Version 15.00.30729.01 for 80x86 Copyright (C) Microsoft Corporation. All rights reserved. demoFail.cpp demoFail.cpp(12) : error C2248: 'A::data' : cannot access protected member declared in class 'A' demoFail.cpp(4) : see declaration of 'A::data' demoFail

This code: class B { protected: void Foo(){} } class D : public B { public: void Baz() { Foo(); } void Bar() { printf("%x\n", &B::Foo); } } gives this error: t.cpp: In member function 'void D::Bar()': Line 3: error: 'void B::Foo()' is protected Why can I call a protected method but not take its address? Is there a way to mark something fully accessible from derived classes rather than only accessible from derived classes and in relation to said derived class? BTW: This looks related but what I'm looking for a reference to where this is called out in the spec or the like (and hopefully that