projection

3d to 2d Projection Matrix

吃可爱长大的小学妹 提交于 2019-11-28 19:34:31
I have 3 points in a 3D space of which I know the exact locations. Suppose they are: (x0,y0,z0) , (x1,y1,z1) and (x2,y2,z2) . Also I have a camera that is looking at these 3 points and I know the 2D locations of those three points on camera view plane. So for example (x0,y0,z0) will be (x0',y0') , and (x1,y1,z1) will be (x1',y1') and (x2,y2,z2) will be (x2',y2') from the camera's point of view. What is the easiest way to find the projection matrix that will project those 3D points into 2D points on camera view plane. We don't know anything about the camera location. This gives you two sets,

How to create 2d plot of arbitrary, coplanar 3d curve

旧城冷巷雨未停 提交于 2019-11-28 12:59:01
问题 I have a set of points which comprise a (in theory) co-planar curve. My problem is that the plane is arbitrary and can move between each time I collect the data (these points are being collected from a camera). I was wondering if you guys could help me figure out how to: find the plane which is closest to the one which these points are co-planar on project the points on this plane in such a way that gives me a 2-d curve I believe that I know how to do point 2, it is really mainly point 1 that

3D Ray Picking use Mouse Coordinates when Mouse isn't locked

流过昼夜 提交于 2019-11-28 08:30:37
So basically I've made a program using OpenGL which can perform 3D Ray Picking. If the Camera View Direction Ray touches/intersects anything (which isn't air) then a little purple box will get rendered at the intersection point/points. If the ray intersects with any of the "Red Boxes" the once that are intersecting with the ray will turn green. The ground and walls won't change color or texture at all. Examples: The current way I do the 3D Ray Picking, is getting the camera's view direction ray, and then just calculating for intersections. My function for calculating intersections doesn't

Circle clip and projection with D3 orthographic

丶灬走出姿态 提交于 2019-11-28 06:04:36
I'm working on this and I'm having trouble with clipping the red circle elements as they appear on the globe even past the 90˚ clip angle. Also, is there a way you can apply the projection to the red circles, as in so it looks like they're on the surface of the globe relative to the orthographic angle? At the moment they just appear as 2d circles relative to the screen. Instead of using <circle> elements, you can use GeoJSON point geometries: {type: "Point", coordinates: [λ, φ]} These can then be clipped via D3’s projection system, depending on the clipAngle that you’ve set. So you might have

Transpose z-position from perspective to orthographic camera in three.js

纵然是瞬间 提交于 2019-11-28 05:25:52
问题 I have a scene where I want to combine perspective objects (ie. objects that appear smaller when they are far away) with orthogographic objects (ie. objects that appear the same size irrespective of distance). The perspective objects are part of the rendered "world", while the orthogographic objects are adornments, like labels or icons. Unlike a HUD, I want the orthogographic objects to be rendered "within" the world, which means that they can be covered by world objects (imagine a plane

What exactly are eye space coordinates?

女生的网名这么多〃 提交于 2019-11-28 03:35:41
As I am learning OpenGL I often stumble upon so-called eye space coordinates. If I am right, you typically have three matrices. Model matrix, view matrix and projection matrix. Though I am not entirely sure how the mathematics behind that works, I do know that the convert coordinates to world space, view space and screen space. But where is the eye space, and which matrices do I need to convert something to eye space? Perhaps the following illustration showing the relationship between the various spaces will help: Depending if you're using the fixed-function pipeline (you are if you call

Hibernate Query By Example and Projections

 ̄綄美尐妖づ 提交于 2019-11-28 03:07:10
To make it short: hibernate doesn't support projections and query by example? I found this post: The code is this: User usr = new User(); usr.setCity = 'TEST'; getCurrentSession().createCriteria(User.class) .setProjection( Projections.distinct( Projections.projectionList() .add( Projections.property("name"), "name") .add( Projections.property("city"), "city"))) .add( Example.create(usr)) Like the other poster said, The generated sql keeps having a where class refering to just y0_= ? instead of this_.city . I already tried several approaches, and searched the issue tracker but found nothing

what is a projection in LINQ, as in .Select()

风格不统一 提交于 2019-11-28 02:57:22
问题 I typically do mobile app development, which doesn't always have .Select. However, I've seen this used a bit, but I don't really know what it does or how it's doing whatever it does. It is anything like from a in list select a // a.Property // new Thing { a.Property} I'm asking because when I've seen code using .Select(), I was a bit confused by what it was doing. 回答1: .Select() is from method syntax for LINQ, select in your code from a in list select a is for query syntax. Both are same,

Projections in NHibernate

末鹿安然 提交于 2019-11-28 01:58:25
suppose in an entity there are attributes id, username, age, address. Now I just want id and username and I use this code for it. Projections enable the returning of something other than a list of entities from a query. var proj = Projections.ProjectionList() .Add(Projections.Property("Id"), "Id") .Add(Projections.Property("Username"), "Username"); var list2 = DetachedCriteria.For<User>() .Add(Expression.Eq("Username", "lachlan")) .GetExecutableCriteria( sessionFactory.GetCurrentSession()) .SetProjection( proj ) .List(); How will I retrieve the values. In which object will these value be taken

Perspective Projection in Android in an augmented reality application

☆樱花仙子☆ 提交于 2019-11-27 22:35:35
Currently I'm writing an augmented reality app and I have some problems to get the objects on my screen. It's very frustrating for me that I'm not able to transform gps-points to the correspending screen-points on my android device. I've read many articles and many other posts on stackoverflow (I've already asked similar questions) but I still need your help. I did the perspective projection which is explained in wikipedia. What do I have to do with the result of the perspective projection to get the resulting screenpoint? benjaminplanche The Wikipedia article also confused me when I read it