primitive

Are the primitive data types like int & short thread-safe in Java? I have executed the following code and couldn't see expected result 500 some times. public class SampleThree extends Thread { static long wakeUpTime = System.currentTimeMillis() + (1000*20); static int inT; public static void main(String args[]) { System.out.println("initial:" + inT); for(int i=0; i<500; i++) new SampleThree().start(); try { Thread.sleep(wakeUpTime - System.currentTimeMillis() + (1000*30)); System.out.println("o/p:" + inT); } catch(Exception e){ e.printStackTrace(); } } public void run() { try { long s =

In the Kotlin language we, by default, have to initialize each variable when it is introduced. To avoid this, the lateinit keyword can be used. Referring to a lateinit variable before it has been initialized results in a runtime exception. lateinit can not, however, be used with the primitive types. Why is it so? For object types, Kotlin uses the null value to mark that a lateinit property has not been initialized and to throw the appropriate exception when the property is accessed. For primitive types, there is no such value, so there is no way to mark a property as non-initialized and to

In my application I use Jersey REST to serialize complex objects. This works quite fine. But there are a few method which simply return an int or boolean. Jersey can't handle primitive types (to my knowledge), probably because they're no annotated and Jersey has no default annotation for them. I worked around that by creating complex types like a RestBoolean or RestInteger, which simply hold an int or boolean value and have the appropriate annotations. Isn't there an easier way than writing these container objects? Have a look at Genson .It helped me a lot with a similar problem.With Genson

In my C# source code I may have declared integers as: int i = 5; or Int32 i = 5; In the currently prevalent 32-bit world they are equivalent. However, as we move into a 64-bit world, am I correct in saying that the following will become the same? int i = 5; Int64 i = 5; No. The C# specification rigidly defines that int is an alias for System.Int32 with exactly 32 bits. Changing this would be a major breaking change. The int keyword in C# is defined as an alias for the System.Int32 type and this is (judging by the name) meant to be a 32-bit integer. To the specification: CLI specification

I am new to Java, and wondering how does double to int cast work ? I understand that it's simple for long to int by taking the low 32 bits, but what about double (64 bits) to int (32 bits) ? those 64 bits from double in binary is in Double-precision floating-point format (Mantissa), so how does it convert to int internally ? Jon Skeet It's all documented in section 5.1.3 of the JLS. In the first step, the floating-point number is converted either to a long, if T is long, or to an int, if T is byte, short, char, or int, as follows: If the floating-point number is NaN (§4.2.3), the result of the