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Django form “takes exactly 1 argument (2 given) ” error - possibly related to CSRF?

由 杀马特。学长 韩版系。学妹 提交于 2020-01-17 02:26:32
问题 I am attempting a fairly simple form on Django 1.3, and am trying to understand how CSRF works. I think I've followed the three steps detailed on the Django site, but am still unable to make the form work. The form displays when the URL is loaded, however upon hitting the submit button, I get the following error: TypeError at /txt/ txt() takes exactly 1 argument (2 given) Here's the actual code: views.py: from django.http import HttpResponse from django.shortcuts import render_to_response,

HTTP POST GET 本质区别详解

由 泪湿孤枕 提交于 2020-01-17 01:57:54
一 原理区别 一般在浏览器中输入网址访问资源都是通过GET方式；在FORM提交中，可以通过Method指定提交方式为GET或者POST，默认为GET提交 Http定义了与服务器交互的不同方法，最基本的方法有4种，分别��?SPAN style="COLOR: #ff0000"> GET，POST，PUT，DELETE URL全称是资源描述符，我们可以这样认为：一个URL地址，它用于描述一个网络上的资源，而HTTP中的GET，POST，PUT，DELETE就对应着对这个资源的 ��?/SPAN> ��?SPAN style="COLOR: #ff6600">��?/SPAN> ��?SPAN style="COLOR: #ff6600">��?/SPAN> ��?SPAN style="COLOR: #ff6600">��?/SPAN> 4个操作。到这里，大家应该有个大概的了解了，GET一般用��?SPAN style="COLOR: #ff6600">获取/查询 资源信息，而POST一般用��?SPAN style="COLOR: #ff6600">更新 资源信息( 个人认为这是GET和POST的本质区别，也是协议设计者的本意，其它区别都是具体表现形式的差异 )��? 　　 根据HTTP规范，GET用于信息获取，而且应该是安全的和幂等的 ��?/P> 　　1

python爬虫

由 北战南征 提交于 2020-01-17 01:31:56
在看这篇文章之前，需要大家掌握的知识技能： python基础 html基础 http状态码 让我们看看这篇文章中有哪些知识点： get方法 post方法 header参数，模拟用户 data参数，提交数据 proxies参数，使用代理 进阶学习 安装上requests库 pip install requests 先来看下帮助文档，看看requests的介绍，用python自带的help命令 import requests help(requests) output： Help on package requests: NAME requests DESCRIPTION Requests HTTP Library ~~~~~~~~~~~~~~~~~~~~~ Requests is an HTTP library, written in Python, for human beings. Basic GET usage: >>> import requests >>> r = requests.get(‘https://www.python.org’) >>> r.status_code 200 >>> ‘Python is a programming language’ in r.content True … or POST: >>> payload = dict(key1=

Send back json to client side

由 流过昼夜 提交于 2020-01-17 00:34:47
问题 I just started developing with cherrypy, so I am struggling a little bit. In client side I am selecting some data, converting it to json and sending to server side via post method. Then I am doing a few operations with json and finally I want to send it back to client side. So the question is how to return modified json to the client side (browser). Server side: @cherrypy.expose def drawChart(self): __test = cherrypy.request.body.read().strip() logging.debug(__test) #...some operations with

How should HTTP Post look like for saving model and associated model data?

由 雨燕双飞 提交于 2020-01-17 00:30:46
问题 I am using Cakephp 2.4.5. I have 2 tables with a one-to-many relationship. Table B belongs to Table A. I want a controller in Table A that can save records in Table A and Table B. The controller code should be simple and looks like this; public function add_tableA($id=null) { if ($this->request->is('post')) { $this->layout = null ; $this->TableA->create(); $this->TableA->saveAll($this->request->data, array('deep' => true)); } } My problem comes when trying to send the right HTTP POST format

How should HTTP Post look like for saving model and associated model data?

由 萝らか妹 提交于 2020-01-17 00:29:08
问题 I am using Cakephp 2.4.5. I have 2 tables with a one-to-many relationship. Table B belongs to Table A. I want a controller in Table A that can save records in Table A and Table B. The controller code should be simple and looks like this; public function add_tableA($id=null) { if ($this->request->is('post')) { $this->layout = null ; $this->TableA->create(); $this->TableA->saveAll($this->request->data, array('deep' => true)); } } My problem comes when trying to send the right HTTP POST format

How should HTTP Post look like for saving model and associated model data?

由 断了今生、忘了曾经 提交于 2020-01-17 00:28:37
问题 I am using Cakephp 2.4.5. I have 2 tables with a one-to-many relationship. Table B belongs to Table A. I want a controller in Table A that can save records in Table A and Table B. The controller code should be simple and looks like this; public function add_tableA($id=null) { if ($this->request->is('post')) { $this->layout = null ; $this->TableA->create(); $this->TableA->saveAll($this->request->data, array('deep' => true)); } } My problem comes when trying to send the right HTTP POST format

Volley send JsonArrayRequest via POST with JsonObject data

由 落花浮王杯 提交于 2020-01-16 22:22:07
问题 I would like to create JsonArrayRequest using Volley POST but I need to put JSON parameters to the request which look like this {"filter":{"minLat":15.0,"minLng":14.0,"maxLng":12.0,"maxLat":16.2,"validOnly":true,"groupDistance":1,"vehicleType":1,"serviceTypes":[1,2]},"username":"email@email.cz","securityToken":"securityToken"} And I'm not able to figure it out. Is there somebody who can help me? Thank you 回答1: If not too late and your issue hasn't been solved. IMO, you can init your

PHP实现登录，注册，密码修改

由 ╄→尐↘猪︶ㄣ 提交于 2020-01-16 22:16:57
注册，登录，修改密码 1.登录 2.忘记密码 3.免费注册 页面布局 <div id="views" class="views"> <div id="view-login" class="page-view view-login active"> <present name="wxuser"> <div id="wxuser" class="form-group text-center"> <div> <img src="{sh:$wxuser.headimgurl}"> </div> <h4 class="nickname">{sh:$wxuser.nickname}</h4> </div> </present> <!--登录--> <div id="login" class="step"> <h4 class="popup-title login">登录</h4> <div class="go-forget">忘记密码</div> <form class="form-horizontal" role="form" type="get"> <div class="form-group"> <label>手机号码</label> <input type="tel" name="tel" class="form-item" id="tel_num" placeholder=

Redirect after posting a HTML form

由 拈花ヽ惹草 提交于 2020-01-16 18:25:30
问题 Is there anyway to redirect the user after posting a HTML form? I have a form which looks like this <form action="/URL/" method="post"> <input type="radio" name="answer" value="W" />W<br /> <input type="radio" name="answer" value="X" />X<br /> <input type="radio" name="answer" value="Y" />Y<br /> <input type="radio" name="answer" value="Z" />Z<br /> <input type="submit" /> </form> Is there anyway I can redirect the user to a new page after they click the submit button? I found a bit of
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