position

UIImageView Position Resetting during label text update

孤者浪人 提交于 2019-12-02 10:02:15
Really weird issue going on here. Using XCode6 with iOS8 I have a simple UIImageView, which moves across the screen when I click. No problem- works great. I Just have a simple method to update specific labels...based on an int called StrikesLeft. Here is my updateLabels method: -(void)displayLabels{ //update strikes label strikesLeftDisplay = [NSString stringWithFormat: @"%d", strikesLeft]; lblStrikes.text=strikesLeftDisplay; } Here is the weird issue though: If I don't actually update the label, it runs no problem...but as soon as the label updates on the viewController, the UIImageView

How to center div in the page? (Height & Width)?

ε祈祈猫儿з 提交于 2019-12-02 09:53:21
silly question, but I can't find answer on it as all answers assume centering div in terms of width. What I need is to center div in means of height and width so in a very very center of the page. I tried this, but it just centers div in means of page width no height. #myDiv { width: 500px; height: 500px; margin: auto; } So how can I get it in the VERY center of the page? ))) Create a wrapper with ID wrapper around the #myDiv element, and apply this CSS code: #wrapper{ display: table; } #myDiv{ display: table-cell; vertical-align: middle; /*Vertically centered*/ text-align: center; /*

深入理解CSS中的层叠上下文和层叠顺序

主宰稳场 提交于 2019-12-02 09:52:19
深入理解CSS中的层叠上下文和层叠顺序 上下文 前端大全 · 2016-01-20 20:12 (点击 上方 公 众 号 ,可快速关注) 作者:张鑫旭 网址:http://www.zhangxinxu.com/wordpress/2016/01/understand-css-stacking-context-order-z-index/ 零、世间的道理都是想通的 在这个世界上,凡事都有个先后顺序,凡物都有个论资排辈。比方说食堂排队打饭,对吧,讲求先到先得,总不可能一拥而上。再比如说话语权,老婆的话永远是对的,领导的话永远是对的。 在CSS届,也是如此。只是,一般情况下,大家歌舞升平,看不出什么差异,即所谓的众生平等。但是,当发生冲突发生纠葛的时候,显然,是不可能做到完全等同的,先后顺序,身份差异就显现出来了。例如,杰克和罗斯,只能一人浮在木板上,此时,出现了冲突,结果大家都知道的。那对于CSS世界中的元素而言,所谓的“冲突”指什么呢,其中,很重要的一个层面就是“层叠显示冲突”。 默认情况下,网页内容是没有偏移角的垂直视觉呈现,当内容发生层叠的时候,一定会有一个前后的层叠顺序产生,有点类似于真实世界中论资排辈的感觉。 而要理解网页中元素是如何“论资排辈”的,就需要深入理解CSS中的层叠上下文和层叠顺序。 我们大家可能都熟悉CSS中的z-index属性,需要跟大家讲的是,z

css定位——position和float的用法详解

ε祈祈猫儿з 提交于 2019-12-02 09:49:29
网页开发中布局是一个永恒的话题。巧妙的布局会让网页具有良好的适应性和扩展性。css的布局主要涉及两个属性——position和float。它们俩看上去很容易被弄混,可是仔细分析一下,它们的区别还是很明显的。下面和大家分享一下我的学习心得。 首先,先介绍一个很重要的概念 “文档流 ” ,明白了这个概念之后就很容易理解position和float的定位原理了。 在css中有一个z-index属性,因为网页是“立体的”,它有z轴,这个z轴的大小就由z-index控制。默认情况下,所有页面元素均位于z-index:0这一层,而这一层顺序排列的元素就构成了 “文档流 ” 。无论是position还是float,它们都是通过改变文档流来实现定位。 css有三种基本的定位机制: 文档流 、浮动和绝对定位 。除非专门指定,否则所有元素都在文档流中定位。也就是说,文档流中的元素的位置由元素在 X(HTML) 中的位置决定。css定位的基本思想很简单,它允许你使得元素相对于其正常应该出现的位置,或者相对于父元素、另一个元素甚至浏览器窗口本身的位置来进行定位。 下面介绍position和float的定位原理。 (一)float: float属性定位的元素位于z-index:0层。它是通过float:left和float:right来控制元素在0层左浮或右浮。float会改变正常的文档流排列

How can I get the screen position of the DockTile in OSX?

谁说我不能喝 提交于 2019-12-02 08:33:29
问题 I need a window to 'point' to the icon that was clicked on in the dock, similar to the way the context menu has the little callout-arrow pointing to it. This means I need to get the screen location of the dock, or more accurately the DockTile. (Yes I could use the mouse coordinates, but that doesn't look as good as it 'moves'.) Now my thought is to get the associated view (I already have that), then use view-to-screen coordinate conversions, but that's becoming problematic as the x/left and y

Position:fixed to work on IE 6/7/8 and mozilla

醉酒当歌 提交于 2019-12-02 08:21:04
I want to make a div's position fixed on the bottom right of a page..( a chat box) ..how do i do that through a css file which will work on all IE6/7/8 and mozilla ....for now i have #chatBox{ position: fixed; bottom: 0%; right: 1%;} This doesn't work on IE..and my constraint is that I am just allowed to edit this CSS file ( so can't set the html to strict mode too). Workarounds I found on the web just talk about position w.r.t to the top of the page not bottom. thanks Mohan You can fix IE with CSS expressions. Serve the following to IE with conditional comments : /* smooths out the IE

Android ViewPager使用详解

為{幸葍}努か 提交于 2019-12-02 08:16:25
这是谷歌官方给我们提供的一个兼容低版本安卓设备的软件包,里面包囊了只有在安卓3.0以上可以使用的api。而viewpager就是其中之一利用它,我们可以做很多事情,从最简单的导航,到页面菜单等等。那如何使用它呢,与LisstView类似,我们也需要一个适配器,他就是PagerAdapter。看一下api的图片, ViewPager的功能就是可以使视图滑动,就像Lanucher左右滑动那样。分三个步骤来使用它: 1.在住布局文件里加入 <android.support.v4.view.ViewPager 这个组件,注意这个组件是用来显示左右滑动的界面的,如果不加载xml布局文件,他是不会显示内容的。 android:id="@+id/viewpager" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center" > 2.加载要显示的页卡, LayoutInflater lf = getLayoutInflater().from(this); view1 = lf.inflate(R.layout.layout1, null); view2 = lf.inflate(R.layout.layout2, null); view3 = lf

Displaying third tier submenus properly with css only menu

对着背影说爱祢 提交于 2019-12-02 07:36:49
I am developing a new site, and am having problems with the css menu. It is easier to explain by example: Here is the link of the site: http://www.webau.net/CSFF/index.asp Under the "Home" parent menu item, I have the following configuration: Top level menu (parent) Submenu 1 (child 1) Submenu 2 (grandchild 1) Submenu 3 (child 2) Submenu 4 (child 3) Instead it appears on the page like this where the grandchild 1 looks like it takes the place of the child 2 menu: Top level menu (parent) Submenu 1 (child 1) Submenu 2 (grandchild 1) Submenu 4 (child 3) I can see a slight offset on the listing of

How do i find the position of MORE THAN ONE substring in a string (Python 3.4.3 shell)

[亡魂溺海] 提交于 2019-12-02 07:17:18
问题 The following code displays the position of "word" if it appears once in the string. How can i change my code so that if the "word" appears more than once in the string, it will print all positions? string = input("Please input a sentence: ") word = input("Please input a word: ") string.lower() word.lower() list1 = string.split(' ') position = list1.index(word) location = (position+1) print("You're word, {0}, is in position {1}".format (word, location)) 回答1: sentence = input("Please input a

ByteBuffer使用实例

谁说胖子不能爱 提交于 2019-12-02 07:05:16
  ByteBuffer作为老牌的字节流处理对象,这里举个小例子说明下用法,直接上代码: package com.wlf.netty.nettyserver; import org.junit.Assert; import org.junit.Test; import java.nio.ByteBuffer; public class ByteBufferTest { @Test public void byteBufferTest() { // 写入消息体 ByteBuffer byteBuffer = ByteBuffer.allocate(10); byteBuffer.putInt(0xabef0101); byteBuffer.putInt(1024); // 今天过节 byteBuffer.put((byte) 1); byteBuffer.put((byte) 0); // 读取消息头,因为写完后position已经到10了,所以需要先反转为0,再从头读取 byteBuffer.flip(); printDelimiter(byteBuffer); // 读取length printLength(byteBuffer); // 继续读取剩下数据 byteBuffer.get(); byteBuffer.get(); printByteBuffer(byteBuffer