popup

Show pop-ups the most elegant way

由 僤鯓⒐⒋嵵緔 提交于 2019-11-26 17:53:17
问题 I have this AngularJS app. Everything works just fine. Now I need to show different pop-ups when specific conditions become true, and I was wondering what would be the best way to proceed. Currently I’m evaluating two options, but I’m absolutely open to other options. Option 1 I could create the new HTML element for the pop-up, and append to the DOM directly from the controller. This will break the MVC design pattern. I’m not happy with this solution. Option 2 I could always insert the code

Open page in new window without popup blocking

由 一世执手 提交于 2019-11-26 17:37:10
Hope you can help a bit here... I have a form that translate a word in a field, populate the field with the translated term and then do submit action all in one submit button. the submit is being made by jquery. problem is the target page is being blocked as all 3 major browsers treat it as popup, Do you know how to let it open just as a new tab or new window ? I don't want to set the target as _self as I want people to have my site open as well. I believe the problem is in this string: document.forms.form1.submit(); but I also know there should be a way to rephrase it so the target won't be

How do I prevent Google Chrome from blocking my popup?

由 妖精的绣舞 提交于 2019-11-26 17:36:51
问题 On my website there is a button that just used to call a function that calls window.open , however, recently an adjustment was needed to do a server-side check before the popup was opened. Ever since the code was added that does the AJAX call, browsers blocks the popup, that is opened in the success callback of the AJAX call. I read that browsers might block the popup if it's not called by a user click event, so I tried setting the AJAX request to async: false , which solved the problem in

chrome Pop-up blocker when to re-check after allowing page

由 半腔热情 提交于 2019-11-26 17:16:33
问题 I've having app which sometimes open the popup blocker, when the user run the application chrome have some flag in the url box (right side) which tell to the user that the pop-up is blocked ,in this case I give to the user in addition new warning message like "please pay attention the page was blocked please enable it..." My question is when and in which term I need to do this check again ,assume the user allow the new App page if user close and open the browser does he need to enable this

PortletURL to open another portlet in pop-up

由 ⅰ亾dé卋堺 提交于 2019-11-26 17:08:26
问题 I have a hook for create_account.jsp . In this jsp I have a javascript code where I try to open a portlet in an iframe pop-up or some pop-up from Liferay. The question is: How to give the portlet URL? How can I access it? In that portlet I only want to ask a question with YES or NO, and based on the user answer, redirect to some other page. 回答1: To create a URL, you can either use <portlet:renderURL> or <liferay-portlet:renderURL> <liferay-portlet:renderURL var="testPopupURL" portletName=

How to display input errors in popup?

由 ↘锁芯ラ 提交于 2019-11-26 16:56:01
I want to show all my validation error's of EdiText fields in a popup as shown in below image: As far as I know Android has drawables: 1) popup_inline_error.9.png 2) popup_inline_error_above.9.png 3) indicator_input_error.png I am able to display the red error indicator inside the right side of the EditText by using: Drawable err_indiactor = getResources().getDrawable(R.drawable.indicator_input_error); mEdiText.setCompoundDrawablesWithIntrinsicBounds(null, null, err_indiactor, null); Now also i want to display the error message as shown is the first image but it seems I am not getting any idea

jqGrid - Change filter/search pop up form - to be flat on page - not a dialog

由 断了今生、忘了曾经 提交于 2019-11-26 16:48:42
问题 I am using jqgrid. I really need help with this, and have no clue how to do it, but i am sure its possible... can any one give me even a partial answer? were to start from? I now have a requirement saying that for searching and filtering the grid I dont want the regular model form pop op thing opening, instead the filter should be open when entering the page but not as a pop up form , but should be on the top of the page but still have all the functions to it. Needs to look like this: And

Javascript,calling child window function from opener doesn't work

由 爷，独闯天下 提交于 2019-11-26 16:44:21
问题 I'm developing a web application that opens a popup using windows.open(..). I need to call a function on the opened window using the handle returned by "window.open", but I'm always getting the error message "addWindow.getMaskElements is not a function", as if it couldn't access the function declared on child window. This is the behavior in both IE and FF. My code looks like this: function AddEmail(target,category) { if(addWindow == null) { currentCategory = category; var left = getDialogPos

How to make PopUp window in java

由 安稳与你 提交于 2019-11-26 16:39:44
问题 I am currently developing a java application. I want to show a new Window which contains a text area and a button. Do you have any ideas? 回答1: The same answer : JOptionpane with an example :) package experiments; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JOptionPane; public class CreateDialogFromOptionPane { public static void main(final String[] args) { final JFrame parent = new JFrame(); JButton button = new JButton(); button.setText("Click me to show dialog!

jQuery beforeunload custom pop up window for leaving a page

由 落花浮王杯 提交于 2019-11-26 16:33:57
问题 Hi I would like to customize my pop up for leaving a page, is there any simple way to do that? I am using simple jQuery $(document).ready(function() { var myPopUp = $('#pop-up').css('display', 'block'); $(window).bind('beforeunload', function(){ return 'load my pop up here instead of the default browser message'; }); }); my html for the pop up is which is hidden by default <div id="pop-up"> <h2>Are you sure wanna leave</h2> <a href="#">Leave</a> <a href="#" class="close">Stay</a> </div>
订阅 popup