point

问题 This is a pretty simple issue but I am new to Python and I can't seem to accomplish it. I want to convert Skeleton data co-ordinates in Python (PyKinect) to Points (X,Y). I know that the similar task can be achieved in C# (using Microsoft.Kinect libraries) like the below code: var p = new Point[6]; Point shoulderRight = new Point(), shoulderLeft = new Point(); foreach (Joint j in data.Joints) { switch (j.ID) { case JointID.HandLeft: p[0] = new Point(j.Position.X, j.Position.Y); // ... In

问题 I want to convert from string {X=-24,Y=10} which generated by Point.ToString(); to Point again? I save the string value in xml file in save mode and I want read it back to point again in read mode. 回答1: var myStringWhichCantBeChanged="{X=-24,Y=10}"; var g=Regex.Replace(myStringWhichCantBeChanged,@"[\{\}a-zA-Z=]", "").Split(','); Point pointResult = new Point( int.Parse (g[0]), int.Parse( g[1])); 回答2: System.Drawing.Point doesn't define a Parse method at all - you will need to write your own

问题 SOLUTION Dynamic Margin on Window Drag So I'm trying to get my polygon to move as the window is moved. I have; private void ResetPolygon(Point Point1, Point Point2, Point Point3) { SpeechPoly.Points.Clear(); ObservableCollection<Point> myPointCollection = new ObservableCollection<Point>(); myPointCollection.Add(Point3); myPointCollection.Add(Point2); myPointCollection.Add(Point1); foreach (Point p in myPointCollection) { SpeechPoly.Points.Add(p); } } private void Window_LocationChanged(object

问题 for a geo-based online game I'm looking for an algorithm which finds the shortest distance between a specified point and a known path connected by x/y-coordinates, so that I can kill all redundant points/nodes. A link or keyword for this algorithm would help me a lot! thanks for reading For better understanding: 回答1: Are you wanting to calculate this in order to say something like "if the point-to-path distance is zero, then remove the point"? If so, then there is probably an easier way to

问题 To find if the point is on a specified line containing two points i do the following checks: -(Boolean)isOnLine:(Line*) line point:(CGPoint) point{ //If between two dots: if (((line.first.x <= point.x && point.x <= line.last.x)||(line.first.x >= point.x && point.x >= line.last.x))&&((line.first.y<=point.y && point.y<= line.last.y)||(line.first.y>=point.y && point.y>=line.last.y)) ) { //Calculate distance: double dist = (((double)point.y - line.first.y)) / (0.00001+((double)(point.x - line

问题 I have list of vertices i.e List<Point> , which contains following points for square: (0,0), (1,0), (2,0), (3,0), (4,0), (4,1), (4,2), (4,3), (4,4), (3,4), (2,4), (1,4), (0,4), (0,3), (0,2), (0,1), (0,0) To draw a square I just need four points (0,0), (0,4), (4,4), (4,0), how do I remove redundant (which makes straight line) points from list? It is not always square, basically I want to reduced the number of points if they form straight line. For example (0,0), (0,1), (0,2), (0,3), (0,4)

问题 I'm trying to make an immutable POINT class in Eiffel. Is the code below defines one? The {NONE} accessibility for the x and y fields is enough for it? Can I write something to the class invariant like x = x' , or how else can I achieve immutability? class POINT create make feature {NONE} x: DOUBLE y: DOUBLE feature make (x_: DOUBLE; y_: DOUBLE) do x := x_ y := y_ ensure set: x = x_ and y = y_ end feature --accessors get_x: DOUBLE do Result := x ensure Result = x end end 回答1: Eiffel does not

问题 Is there an official specification for the XYZ format for point clouds? I've been searching all over and I didn't find it. I've seen that there are some files which line contains: points coordinates, (X Y Z for each point ) others contain coordinates plus colors, (X Y Z R G B for each point ) there are even others that have an "Intensity" parameter. I need to consider all the possibilities. 回答1: No, there is not an official specification about the .xyz format for point clouds. The .xyz format

问题 I'm using python to develop a map (Google Maps) and add some points in specific location. After searching I found it can be done using pygmaps . So I installed it using pip , then I wrote this code and I need to add points and open a webpage for the map find the points there. import pygmaps import webbrowser mymap = pygmaps.maps(37.428, -122.145, 16) mymap.setgrids(37.42, 37.43, 0.001, -122.15, -122.14, 0.001) mymap.addpoint(37.427, -122.145, "#0000FF") mymap.addradpoint(37.429, -122.145, 95,

问题 I have two points and I would like to compute n evenly distributed points on top of the line created by the given line. How could I perform this in c++? 回答1: Linear interpolation (affectionately called lerp by the Graphics community) is what you want. Given the end points it can generate the points lying in between with a parameter t . Let the end points be A (Ax, Ay) and B (Bx, By) . The vector spanning from A to B would be given by V = B − A = <Vx, Vy> L(t) = A + tV This essentially means