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Jerky playback from avplayer on Applying Rate greater than 2x

由 非 Y 不嫁゛ 提交于 2019-12-01 01:41:09
I want to tweak Avplayer rate , I able to do with help of [_avplayer play]; [_avplayer setRate:1.5]; Also disabled audio tracks , it is running good when it is less than 2.0. But when we apply it greater than 2X it results in Choppy or jerky video. When i googled about this - I found this one link suggesting same behaviour https://developer.apple.com/library/content/qa/qa1772/_index.html Playing at rates greater than 2.0 can result in jerky or choppy playback when the data rate or other processing requirements of playing at the specified rate exceeds the ability of AVFoundation to keep up. In

Jerky playback from avplayer on Applying Rate greater than 2x

由 流过昼夜 提交于 2019-11-30 21:08:06
问题 I want to tweak Avplayer rate , I able to do with help of [_avplayer play]; [_avplayer setRate:1.5]; Also disabled audio tracks , it is running good when it is less than 2.0. But when we apply it greater than 2X it results in Choppy or jerky video. When i googled about this - I found this one link suggesting same behaviour https://developer.apple.com/library/content/qa/qa1772/_index.html Playing at rates greater than 2.0 can result in jerky or choppy playback when the data rate or other

Playing MP3 files with Python

由 被刻印的时光 ゝ 提交于 2019-11-30 19:08:42
I'm trying to write my own media player (like Foobar), and I'm having trouble tracking down a Python library that'll play MP3s. I know Pymedia does mp3s, but it looks outdated - the latest installer is for Python version 2.4, and I'm using 2.6. I've never had much success with Pygame, and Pyglet doesn't look like it has too much in the way of documentation. Are there any other alternatives? Terry Felkrow There is http://pyglet.org/ and also have you tried http://code.google.com/p/mp3play/ ? It's also available from PyPi ( http://pypi.python.org/pypi/mp3play/ ) However, I think mp3play is Win32

Android button click to play music, click again to stop sound

由 本秂侑毒 提交于 2019-11-30 14:25:26
问题 I have a button, when I click it plays music, how to do it, when I click second time, to stop the music? Button two = (Button)this.findViewById(R.id.button2); final MediaPlayer mp2 = MediaPlayer.create(this, R.raw.two); two.setOnClickListener(new OnClickListener(){ public void onClick(View v) { mp2.start(); } }); Ok, this one works: Button one = (Button)this.findViewById(R.id.button1); final MediaPlayer mp1 = MediaPlayer.create(this, R.raw.n); one.setOnClickListener(new OnClickListener(){

How to play a video file in android?

由 為{幸葍}努か 提交于 2019-11-30 13:00:18
问题 I am placed video MP4 to my domain space. I have its public URL, Now i want to play it in my android app; but don't know how can I do this. I used following code which is not working. Track controller is moving but I can't see any video on screen. public class MPlayer extends Activity{ public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.playvideo); VideoView videoView = new VideoView(MPlayer.this); videoView.setMediaController(new

Android comprehensive failproof music service across multiple activities

由 拥有回忆 提交于 2019-11-30 11:21:08
问题 I know this question has been asked many times before and might seem to be a conglomeration of several questions, but I feel that it is relevant and important to many developers; I need to create a background music Service that can run across multiple activities for my Android game that ends when the application is terminated and pauses in all of the following circumstances: A certain Activity that has its own music is started. (Resume when this Activity finishes. This happens to be an

Android button click to play music, click again to stop sound

由 别等时光非礼了梦想. 提交于 2019-11-30 10:39:00
I have a button, when I click it plays music, how to do it, when I click second time, to stop the music? Button two = (Button)this.findViewById(R.id.button2); final MediaPlayer mp2 = MediaPlayer.create(this, R.raw.two); two.setOnClickListener(new OnClickListener(){ public void onClick(View v) { mp2.start(); } }); Ok, this one works: Button one = (Button)this.findViewById(R.id.button1); final MediaPlayer mp1 = MediaPlayer.create(this, R.raw.n); one.setOnClickListener(new OnClickListener(){ @Override public void onClick(View v) { if (mp1.isPlaying()) { mp2.pause(); } else { mp2.start(); } ; }});

JLayer - Pause and resume song

由 放肆的年华 提交于 2019-11-30 08:35:43
问题 I've noticed that a lot of topics were about pausing/resuming an MP3 using JLayer , so in order to help everybody, I've made a whole entire class designed just for that! Please see the answer below. Note: This was for my personal use, so it may not be as robust as some people were hoping. But it is not that hard to make simple modifications, due to its simplicity. 回答1: A very simple implementation of a player that is really pausing playback. It works by using a separate thread to play the

AVPlayer cannot resume upon Wifi drops in iOS 8

由 半城伤御伤魂 提交于 2019-11-30 08:34:46
问题 I'm using AVPlayer to play streaming video. When Wifi drops and later enables, I see that AVPlayer cannot resume, no matter how many times I call AVPlayer play , and its currentItem 's duration is NaN, seekableTimeRanges is empty. This is not the case for iOS 7, it resumes and plays well. The workaround I can think of is to restart the player. How to deal with this? 来源： https://stackoverflow.com/questions/28059019/avplayer-cannot-resume-upon-wifi-drops-in-ios-8

HTML5 Audio and jQuery

由 孤街醉人 提交于 2019-11-30 05:50:51
I am trying to use a button to start a track in an HTML5 audio tag using jQuery, but I keep getting an error. var song = $('#audio'); $('#play').click(function() { song.play(); }); When I use document.getElementById('audio'), it works, but when using the jQuery selector I get the following error: Uncaught TypeError: Object [object Object] has no method 'play' Thanks for any help. Try getting the native DOM element as jQuery knows nothing about .play method on the wrapped array returned by the $('#audio') selector: song.get(0).play(); You can also write it like song.trigger('play'); . That will
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