pixels

I'm using OpenCV to iterate through an image and find the colour of each pixel, here's some of the code I'm using: IplImage* img = cvLoadImage("c:\\test.png"); int pixels = img->height * img->width; int channels = img->nChannels; for (int i = 0; i < pixels*channels; i+= channels) { unsigned char red = img->imageData[i + 2]; unsigned char green = img->imageData[i + 1]; unsigned char blue = img->imageData[i]; outputRGBValues(red, green, blue); if (red == REDCOLOUR && green == GREENCOLOUR && blue == BLUECOLOUR) { count++; } } cvReleaseImage(&img); When I run it, it outputRGBValues outputs

There is this image comparison code I am supposed to modify to highlight/point out the difference between two images. Is there a way to modify this code so as to highlight the differences in images. If not any suggestion on how to go about it would be greatly appreciated. int width1 = img1.getWidth(null); int width2 = img2.getWidth(null); int height1 = img1.getHeight(null); int height2 = img2.getHeight(null); if ((width1 != width2) || (height1 != height2)) { System.err.println("Error: Images dimensions mismatch"); System.exit(1); } long diff = 0; for (int i = 0; i < height1; i++) { for (int j

I am looking to convert pixes to inches and vice versa. I understand that I need DPI, but I am not sure how to get this information (e.g. I don't have the Graphics object, so that's not an option). Is there a way? On a video device, any answer to this question is typically not very accurate. The easiest example to use to see why this is the case is a projector. The output resolution is, say, 1024x768, but the DPI varies by how far away the screen is from the projector apeture. WPF, for example, always assumes 96 DPI on a video device. Presuming you still need an answer, regardless of the

I have an integer array of RGB pixels that looks something like: pixels[0] = <rgb-value of pixel(0,0)> pixels[1] = <rgb-value of pixel(1,0)> pixels[2] = <rgb-value of pixel(2,0)> pixels[3] = <rgb-value of pixel(0,1)> ...etc... And I'm trying to create a BufferedImage from it. I tried the following: BufferedImage img = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); img.getRaster().setPixels(0, 0, width, height, pixels); But the resulting image has problems with the color bands. The image is unclear and there are diagonal and horizontal lines through it. What is the proper way to

For a project, I need to know the current size (in pixels) of my matplotlib figure, but I can't find how to do this. Does anyone know how to do this ? Thanks, Tristan import matplotlib.plt fig = plt.figure() size = fig.get_size_inches()*fig.dpi # size in pixels To do it for the current figure, fig = plt.gcf() size = fig.get_size_inches()*fig.dpi # size in pixels You can get the same info by doing: bbox = fig.get_window_extent().transformed(fig.dpi_scale_trans.inverted()) width, height = bbox.width*fig.dpi, bbox.height*fig.dpi 来源： https://stackoverflow.com/questions/29702424/how-to-get

I was reading dp, dip, px, sp measurements , but I still have some questions about dp/dpi vs ppi vs px vs inch. I am not able to compare them... is an inch the largest? They say 160 dpi means 160 pixels per one inch. Does that mean 1 inch contains 160 pixels? They also say 1 pixel on a 160 dpi screen = 1 dp. Does that mean 1 pixel and 1 dp are equal? And lastly, why should we use dp instead of px? I understand that it is ideal, but why ? You should (almost) always use flexible sizing units, like dp , which is Density-Independent Pixels, because 300px on one device is not necessarily the same