pinterest

oschina 中收录了类Pinterst 瀑布流的一个实现方式 http://www.oschina.net/p/android_waterfall 实现方式是ScrollView 嵌套多列LinearLayout ，通过计算当前图片与上下两屏距离来判断是否被回收或者重载。 单个瀑布流也可以从布局文件中 Infalte 出来，实现自定义。 Github 上还有另外一种 瀑布流的实现方式 https://github.com/huewu/PinterestLikeAdapterView Git clone git://github.com/huewu/PinterestLikeAdapterView.git 韩文。韩国人写的。 写的有点特别 。 我估计： 他首先将google的 android.widget 包中的 AdapterView ,AdapterListView和 ListView 源码copy下来。 对其中的某些部分进行了修改.(代码太多 还没有看完) ，最后使用 MultiColumnListView 类实现了 多列的ListView。 如果预计没错 ，单个View的显示方式和回收方式是和ListView相同的，有个pool of recycled views 。Adapter 中调用 getView（int posititon ,View converView ..

How they are counting whether a pin is popular or not? I had something like this in mind: {reposts}*150+{comments}*100+{likes}*50-{time}/150 They probably won't tell anyone outside... But from my experience, popularity algorithms start off like the one you suggested, but tend to be refined and get more complex over time. Every similar algorithm I have been developing so far kept evoluting for months even after go live. As people try to trick the algorithm into making their own stuff more popular than other stuff, additional constraints are added to avoid this. Most probably there will be more

I'm trying to setup a UICollectionViewLayout programmatically. I'm using a UICollectionView also without using storyboards, as well as settings its constraints. I've followed Ray Wenderlich tutorial on the subject with some changes to adapt the code to Swift 3 (as AZCoder2 did https://github.com/AZCoder2/Pinterest ). Since all these examples uses storyboards, I've also introduced some changes to create the UICollectionView and its UICollectionViewLayout : collectionViewLayout = PinterestLayout() collectionViewLayout.delegate = self collectionView = UICollectionView.init(frame: .zero,

I was looking for pinterest API endpoints... I've founded some URL.. https://api.pinterest.com/v3/domains/<domains>/search/pins/?query=<query>&access_token=<access_token> I was able to generate the access_token..but every time I've tried a POST on that URL it gave me: { "status":"failure", "code":12, "host":"ngapi2-b2fc674c", "generated_at":"Mon, 09 Feb 2015 17:45:29 +0000", "message":"Something went wrong on our end. Sorry about that.", "data":"path: /v3/domains/www.vtracker.com.br/search/pins/\nparams: [('access_token', [u'blablahblahblah']), ('query', [u'como'])]\nTraceback (most recent

Using the Pinterest-IOS SDK (2.3) I'm getting a EXC_BAD_ACCESS error when creating an instance of the SDK via the Swift Bridge and then calling createPinWithImageURL. When converting the same code back to objective-c and then calling a wrapper method from Swift it works as expected. The root cause seems to be passing the appID and suffix strings from Swift to Objective-C. This code fails: self.pinterest = Pinterest(clientId:"your_app_id", urlSchemeSuffix:"prod")! if(pinterest.canPinWithSDK()) { pinterest.createPinWithImageURL(NSURL(string: imageUrl)!, sourceURL:NSURL(string: sourceUrl)!,

using this request to get the pins of a user for Pinterest Api(from pinterest api documentation ) http://widgets.pinterest.com/v3/pidgets/users/ {username}/pins/ but by default returns a array of 50 pins is there a way to limit to lower number of pins returned? Go here, click Generate , and get an access token: https://developers.pinterest.com/tools/access_token/ Get the statuses using note&limit=int : https://api.pinterest.com/v1/me/pins/?access_token=TOKEN&fields=id,creator,note&limit=2 See docs for extra parameters: https://developers.pinterest.com/docs/api/overview/ 来源： https:/

Currently I am working on pinterest api to get pin from my domain. I am able to get access token by api. Than I am making api call to get domain pin by using below : https://api.pinterest.com/v3/domains/<domain>/search/pins?access_token=ACCESSTOKEN But I am not sure what to put as <domain> . How can I know what is my domain name in pinterest. Note : I have created app using http:developer.pinterest.com/manage Also, there is not any provision of domain name over there, it should be your profile name or we may have to make some different process to get domain name. the value of domain is the