period

问题 What is the sending interval of RTCP Receiver Report? In RFC 3550 I was only able to find computation the RTCP Transmission Interval for the server. But as a client I have no idea about members and senders (or do I?). So I'm a little bit confuse how to calculate the interval or should I send RTCP RR in periods or should I only send RR packet when SR is received? 回答1: The RTP and RTCP protocols don't make a distinction between client and server. Both are members within the RTP session and both

问题 I have a SQL CE database, which is beyond my control, that has fields in the format of ., complete with a period in the column name. The columns will always be different, so I cannot have a strong-typed data field. I've been tasked with displaying dynamic table data into a DataGrid. Normally, this would be easy -- auto-generate the columns and everything is cool. Easy example. However, I'm not allowed to do this, since the '.' character in the column names nukes the binding. Right now, I'm

问题 I'm building a tv series scheduling app in Ruby on Rails which performs certain actions based on what's currently on tv. Users can create a series, which has a start and end date, and can create broadcasts for those series. Broadcasts can be on one of three channels, and are in the form of "every Tuesday, on channel 2, from 10:00:00 until 14:00:00". Currently, I'm storing these broadcasts in MySQL with the following columns: a wday integer, a starts_at and ends_at time field, and a channel_id

问题 I want to calculate the sum of the flooded days for a variable intervall of time. the end of the period is given in a vector or data.frame and I want different length of my time period, e. g. 4 days and 6 days. How can I create a code, which is flexible, so that I can calculate different date_end's and also create a vector with different length of the period? My complete data.frame contains about 2 years, and 12 end dates and 3 different period lenght. df <- data.frame(date = c("2016-11-01",

问题 i tired using java.time.Period , and the results were different from my manual calculations by three days. The weird thing here is when i divide the period into two periods , the results matches my manual calculations. the second method is just like how i calculate the period manually. is there something i missed ? is there a standard method or algorithm of calendar arithmetic ? and what's the algorithm used by java.time.Period ? import java.time.LocalDate; import java.time.Period; import

问题 I have an SQL query executed by: ResultSet resultSet = preparedStatement.executeQuery(); while( resultSet.next() ){ // do some stuff } Is there a way to stop the execution and do some code after let's say 2 minutes of execution? Thanks 回答1: You can set a timeout on executing a query. SQLException will be thrown if the query doesn't complete in time and times out: preparedstatement.setQueryTimeout(seconds); ResultSet resultSet = preparedStatement.executeQuery(); while( resultSet.next() ){ //

问题 I am trying to create a calculated member to calculate the nb of employees YTD. By YTD I mean the number of employees for any given period of time.My fact table has 2 date dimensions StartDate and EndDate. I would like to calculate YTD employees as follows. Members with StartDate equal to or before current period AND EndDate in the current period OR EndDate is NULL 回答1: I had a similar task and end up with the following solution: SUM( [EmployeeChanging].[EmployeeChanging].[EmployeeChanging]

问题 I'm getting data from an array. For some reason the array has key values like [3.3] which I'm having trouble retrieving data from. I have this array [3.3] => First Name [3.6] => Last Name[2] => email@example.com . When I try to call $array[3.3] it returns null, but when I call $array[2] I am given the e-mail. Any ideas? 回答1: Use single quotes when referencing the key value (basically treat it like a string, that's what PHP is probably doing) echo $array['3.3']; 回答2: From php manual : Floats

问题 Given two datetimes ( start_date and end_date ), I'd like to generate a list of other datetimes between these two dates, the new datetimes being separated by a variable interval. e.g. every 4 days between 2011-10-10 and 2011-12-12 or every 8 hours between now and tomorrow 19p.m. Maybe something roughly equivalent to the Dateperiod PHP class. What would be the most efficient way to accomplish this in Python? 回答1: Use datetime.timedelta: from datetime import date, datetime, timedelta def

问题 If I have a json response that looks like this: { year: 40, month: 2, day: 21 } That represents someone's age. And I have a class to store that: public class User { private Period age; } How do I parse the individual numbers and create a Period object? 回答1: If you are using Jackson you can write a simple JsonDeserializer like this: class UserJsonDeserializer extends JsonDeserializer<User> { public User deserialize(JsonParser p, DeserializationContext ctxt) throws IOException,