pdo | 易学教程

PDO 查询mysql返回字段整型变为String型解决方法

阅读更多关于 PDO 查询mysql返回字段整型变为String型解决方法

【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> PDO 查询 mysql 返回字段整型变为String型解决方法使用PDO查询mysql数据库时，执行prepare,execute后，返回的字段数据全都变为字符型。例如id在数据库中是 Int 的，查询后返回是 String 型。对于php这种弱类型的语言，影响不大。在做API返回数据时，如果类型与数据库不一致，对于java和Objective C这些强类型，影响就很大了。解决方法： <?php$pdo = new PDO($dsn, $user, $pass, $param);// 在创建连接后，加入$pdo->setAttribute(PDO::ATTR_STRINGIFY_FETCHES, false);$pdo->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);?>1234567 这两句设置的作用 PDO::ATTR_STRINGIFY_FETCHES 提取的时候将数值转换为字符串。 PDO::ATTR_EMULATE_PREPARES 启用或禁用预处理语句的模拟。更多 PDO setAttribute 可参考： http://php.net/manual/zh/pdo.setattribute.php 顶 0 踩来源： oschina 链接

How do I convert this PDO code to MySQLi?

阅读更多关于 How do I convert this PDO code to MySQLi?

问题 I'm quite new to PHP and MySQL and I try to learn how to change a code from PDO to MySQLi. Its about a remember me function with a securitytoken and identifier for a login system that I found in the web. I would like to learn and understand how I can change the code from PDO to MySQLi. I know in MySQLi there is a statement create and prepare, also I have to bind parameters and execute. But in this case, I don't know how to start anyway. $pdo = new PDO('mysql:host=localhost;dbname=dbname',

JOIN multiple tables in single query using LEFT OUTER JOIN

阅读更多关于 JOIN multiple tables in single query using LEFT OUTER JOIN

问题 I'm having difficulties using the LEFT OUTER JOIN in multiple tables. My tables are: countries , customer_info , package_types , service_types and shipping_info This is my code so far: $sql = "SELECT shipping_info.shipping_id, shipping_info.weight, shipping_info.width, shipping_info.height, shipping_info.length, shipping_info.cost, shipping_info.status, service_types.service, package_types.package_type, countries1.country AS fromCountry, countries2.country AS toCountry, countries3.country AS

JOIN multiple tables in single query using LEFT OUTER JOIN

阅读更多关于 JOIN multiple tables in single query using LEFT OUTER JOIN

JOIN multiple tables in single query using LEFT OUTER JOIN

阅读更多关于 JOIN multiple tables in single query using LEFT OUTER JOIN

Return results within a given radius using a bounding circle as a 'First Cut' in MySQL

阅读更多关于 Return results within a given radius using a bounding circle as a 'First Cut' in MySQL

问题 I was working with Chris Veness' scripts from http://www.movable-type.co.uk I was trying to run a query against a MySQL database to return only rows that fall within a given radius, using his Bounding Circle script. As follows: <?php require 'inc/dbparams.inc.php'; // defines $dsn, $username, $password $db = new PDO($dsn, $username, $password); $db->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_OBJ); $lat = $_GET['lat']; // latitude of centre of bounding circle in degrees $lon = $_GET

PDO prepared Statements correct?

阅读更多关于 PDO prepared Statements correct?

问题 I am trying to use some PDO prepared statements for the first time to prevent a SQL Injection. I am quite new to SQL so the prepared statements are very bewildering to me. Do you think my SQL code with prepared statements is correct? <?php if ( $_SERVER["REQUEST_METHOD"] == 'POST' ) { $suche = htmlspecialchars($_POST['suche']); $stmt->bindParam(':suche', $suche); if (!empty($suche)) { $sql = new rex_sql; $sql->debugsql = 0; $stmt = $sql->prepare("SELECT * FROM rex_downloads WHERE dateiname

PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number [closed]

阅读更多关于 PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number [closed]

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . I´m trying to do an update with PDO and I´m getting an error that Im not detecting where the problem is. The error is this : PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: parameter was not defined in $updateCategory->execute(); Someone there have any idea why this is happening? $urledit = $

Fatal error: Call to a member function count() on a non-object in not solved

阅读更多关于 Fatal error: Call to a member function count() on a non-object in not solved

问题 Sorry i think this question has a lot , but I still do not get the solution of this question, so solved my script please:( sorry my bad english. <?php class Validate{ private $_passed = false, $_error = array(), $_db = null; public function __construct(){ $this->_db = DB::getInstance(); } public function check($source, $items = array()){ foreach ($items as $item => $rules) { foreach ($rules as $rule => $rule_value) { $value = trim($source[$item]); $item = escape($item); if($rule === 'required

SQL database value to variable

阅读更多关于 SQL database value to variable

问题 So, I am kinda new to php and mysql, but I have found a login form and adapted it to my needs as I dont have the knowledge to make one my self yet. I added a firstname and surname column into the database and the register form adds the values into the database fine. Now I want to be able to display the firstname and surname onto a restricted page, the reason why I need this is because I want it to say: Welcome Jo Blogs. Below is the register form. <?php session_start(); if( isset($_SESSION[