pattern-matching

问题 I have two lists: list1<-list("q","w","e","r","t") list2<-list("a","a","aq","c","f","g") I need a code that will give TRUE because q is in the third cell of list2 . I need to search for every cell of list1 in list2 . I mean that I need to search every cell of list2 for any strings that are contained in every cell of list1 . Matching should be as for the whole match but also for partial (if string from list1 is a part of the bigger string in list2 ) and in both cases I need to receive TRUE .

问题 I was trying to use sed to do the following: In file looks something like: FirstLine SecondLine EEE AAA blablabla ForthLineEEE FifthLine LastLine I want to remove EEE (but keep the rest of second line) and the whole line starting with AAA and keep other part of the file intact. The expected result is (as seen, if the following line doesn't start with AAA, it will be kept, that's why I need to match multiple lines.) FirstLine SecondLine ForthLineEEE FifthLine LastLine How should I do it?

问题 I'm attempting to condense some repetitive code that has structure similar to: match self.foo() { None => self.bar(), Some(MyStruct { foo: x, .. }) => match x { Pattern1 => result, Pattern2 => { block_result } } } which I would like to write as something like: my_macro!( Pattern1 => result, Pattern2 => { block_result } ) avoiding the repetitive None handling and MyStruct destructuring. This seems like it should be pretty simple, as it's essentially just substituting the macro body into a

问题 I have this logfile New connection: 141.8.83.213:64400 (172.17.0.6:2222) [session: e696835c] 2016-04-29 21:13:59+0000 [SSHService ssh-userauth on HoneyPotTransport,3,141.8.83.213] login attempt [user1/test123] failed 2016-04-29 21:14:10+0000 [SSHService ssh-userauth on HoneyPotTransport,3,141.8.83.213] login attempt [user1/test1234] failed 2016-04-29 21:14:13+0000 [SSHService ssh-userauth on HoneyPotTransport,3,141.8.83.213] login attempt [user1/test123] failed I want to output to file a

问题 I'm trying to write a regular expression to mach an IRC PRIVMSG string. It is something like: :nick!name@some.host.com PRIVMSG #channel :message body So i wrote the following code: Pattern pattern = Pattern.compile("^:.*\\sPRIVMSG\\s#.*\\s:"); Matcher matcher = pattern.matcher(msg); if(matcher.matches()) { System.out.println(msg); } It does not work. I got no matches. When I test the regular expression using online javascript testers, I got matches. I tried to find the reason, why it doesn't

问题 My problem is quite simple, i am parsing a CSV file, line after line and i want to get the values of the columns. The separators used are simply " ; ", but my file can have quite a lot of columns, and they won't be always in the same order. So as example for my .CSV file : time;columnA;columnB,ColumnC 27-08-2013 14:43:00; this is a text; this too; same here And i would like to be able to get all the values of time, columnA, columnB and columnC. What would be the easiest way? I used

问题 I'm trying to figure out how exactly does @@ operator work in postgres. I have the two queries: SELECT description FROM product WHERE description @@ '%apple%' SELECT description FROM product WHERE description @@ 'apple' The two queries return the same number of rows. Apparently postgres removes all non alfanumeric characters from the query. Is this actually the case? I can also do @@ '@apple..,,.' and I still get the same number of results. 回答1: @@ operator is part of TSearch2 Full Text

问题 This question already has an answer here : Encode an ADT / sealed trait hierarchy into Spark DataSet column (1 answer) Closed last year . Hi I have an RDD which is basically made after reading a CSV file. I have defined a method which basically maps the lines of rdd to different case classes based on input parameter. The RDD returned need to be converted to dataframe When I try to run the same I get below error. Method defined is case class Australiafile1(sectionName: String, profitCentre:

问题 I have read the following post about How to match content between HTML specific tags with attribute using grep?. However, when I use the code derived from that page, I'm unable to match the content. I keep getting a blank output. Here's the code I'm using: grep -oP '(?<=<div class="tag"> ).*?(?= </tag>)' file1.txt I've ensured that all the line endings are in linux (LF). Here's file1.txt: <div class="tag"> <p>hello world!</p> </tag><!-- .end-section --> I would want the output: <div class=

问题 I'm trying to set up rabbitmq authorization against LDAP (Microsoft Active Directory) using the in_group or in_group_nested queries. However, since our OU structure is inconsistent across our users, which results in a variety of DN patterns, I had to rely on a user_dn_pattern that simply passes the "domain\account" when binding, which works great from an authentication perspective with Microsoft Active Directory. However, when it comes to the in_group / in_group_nested queries, it doesn't