path

How to get Directory and file name of an image selected from gallery

↘锁芯ラ 提交于 2019-12-13 03:37:40
问题 I need to use this function, java.io.File.File(File dir, String name) public File (File dir, String name) Added in API level 1 Constructs a new file using the specified directory and name. Parameters dir the directory where the file is stored. name the file's name. Throws NullPointerException if name is null. Now as we can see it needs file dir and name as parameters. Now I am selecting an Image from gallery by intent. How can I get the dir and name for the selected file.? Here is the snippet

Finding the diameter of m-ary tree - C

我的未来我决定 提交于 2019-12-13 03:25:40
问题 I have to analyze an m-ary tree in C - using namely BFS. There are some requirements I don't succeed to implement for a while: 1. Find the diameter of the tree. 2. Given two vertices in the tree - find the shortest simple path between them. As for 1 - I went through the topics in Stack - and have seen some implementations (not in C unfortunately) which are not very clear to me... Some way of calculating the diameter by using BFS twice, starting from a random vertex... I'm not sure if the

C# under Linux, WorkingDirectory not working properly

家住魔仙堡 提交于 2019-12-13 03:25:07
问题 I have an issues with WorkingDirectory , and it is not setting the desired path correctly. I wrote a simple hello world test program, a.out , to try out WorkingDirectory . And the directory hierarchy is such: /home/cli2/test /bin/Debug/netcoreapp2.1/subdir/ a.out /obj Program.cs test.csproj I have the following settings for the Process class process.StartInfo.FileName = "a.out" process.StartInfo.UseShellExecute = false; process.StartInfo.WorkingDirectory = Path.GetDirectoryName(Assembly

Eyebrow raising animation with SVG path

流过昼夜 提交于 2019-12-13 03:18:14
问题 I am trying to animate eyebrows with SVG. But got stuck as I am not getting proper tutorial showing the meaning and use of numbers used in path="" (please share a tutorial link if you know any). Anyone please help me with raising the smiley's eyebrows. Here is my code <svg height="100" width="100"> <circle cx="50" cy="50" r="40" stroke="black" stroke-width="3" fill="none" /> <ellipse cx="35" cy="45" rx="4" ry="5" stroke="red" stroke-width="2" fill="none" /> <ellipse cx="65" cy="45" rx="4" ry=

Add Poppler to Path in Debian

℡╲_俬逩灬. 提交于 2019-12-13 02:39:25
问题 I have just installed poppler on my debian server using the command: sudo apt-get install poppler-utils However, when I execute the command: pdftocairo --help The function cannot be found, so I assume this program has not automatically linked into my PATH variable. My issue is that I am not very experienced with Linux and I don't know how to find out where poppler installed, nor how to create a link file to Poppler from an existing included PATH location. Any help would be appreciated,

Path in Variable with r'

坚强是说给别人听的谎言 提交于 2019-12-13 02:33:44
问题 I want to replace this: path = r'C:/Folder with this: path = r'variable Where variable is defined elsewhere. In not sure how to put the variable name after the r' 回答1: Just use path = variable . The point of the r'...' notation is for writing raw string literals; it changes the rules for character escaping inside of the quotes. If you're just getting the value from another variable, there's no need for an r since you're not writing a string literal. 回答2: This should work: path = r'%s' %

Django FILES upload: path and filename

有些话、适合烂在心里 提交于 2019-12-13 02:13:16
问题 When an uploaded file is received by the Django server, its name can be read using UploadedFile.name If filename in the multipart-data content contains a path like: '/a/b/c', UploadedFile.name seems to contain '/c' . How can I retrieve the full path and not just the file name. Thanks. Laurent Luce 回答1: You can't. Many browsers won't ever send the whole path, as a security measure to prevent information leakage. What's more you know nothing about the file and path naming conventions in force

How can I get the proper capitalization for a path?

巧了我就是萌 提交于 2019-12-13 02:04:36
问题 Let's say I have a class which represents a directory (simplified example of course): import os class Dir: def __init__(self, path): self.path = os.path.normcase(path) To make things easier to implement internally, I am calling os.path.normcase on the path argument before I save it into an attribute. This works great, but it lowercases the path: >>> import os >>> os.path.normcase(r'C:\Python34\Lib') 'c:\\python34\\lib' >>> I would like a way to turn the path back into its properly capitalized

multi-dimensional array hierarchy from key name

≡放荡痞女 提交于 2019-12-13 02:03:57
问题 I like to know how can I get the hierarchy by the identifier Key NAME, just the values with PHP. I already had try some implode functions but without success. I appreciated any help. Thanks This is an example : $treeArray = (Array ( [0] => Array ( [name] => S-ATLANTICO-1 [id] => 1HIk_jh2GHo2VnBbUI8c3P9cADY4NnKQ5 [parents] => [children] => Array ( [0] => Array ( [name] => TESTE [id] => 1EYi_CF7gjANq_MPnUOkquJI609Jkhzf0 [parents] => 1HIk_jh2GHo2VnBbUI8c3P9cADY4NnKQ5 ) [1] => Array ( [name] =>

Expanding the PATH with a list of directories extracted from a text file, the '~' character not expanded to HOME

为君一笑 提交于 2019-12-13 01:42:45
问题 The PATH is expanded by a list of directories extracted from a text file; $ cat ~/.path ~/.local/bin ~/W-space/esp/esp-open-sdk/xtensa-lx106-elf/bin ~/W-space/research/recognition/voxforge/bin ~/W-space/research/recognition/voxforge/bin/julius-4.3.1/bin like so (The following can be found in one of the BASH's startup files): declare -a BATH_ARRAY=($(cat ~/.path)) 2>/dev/null # extend path for BATH in "${BATH_ARRAY[@]}" do case ":${PATH}:" in *:${BATH}:*) ;; *) PATH=${PATH}:$BATH && export