path

Can I apply a gradient along an SVG path?

无人久伴 提交于 2019-12-17 07:27:13
问题 I'd like to put a simple loading indicator on my website that's triggered by a script. It should be a simple circle arc that's got a gradient and is spinning while the user is waiting. I haven't tried the animation part, but got stuck on the static styling for now. Here's what I've got so far: <svg version="1.1" baseProfile="full" xmlns="http://www.w3.org/2000/svg" width="100" height="100"> <defs> <linearGradient id="grad1"> <stop offset="0%" stop-color="red"/> <stop offset="100%" stop-color=

Convert relative path to absolute using JavaScript

旧巷老猫 提交于 2019-12-17 07:10:30
问题 There's a function, which gives me urls like: ./some.css ./extra/some.css ../../lib/slider/slider.css It's always a relative path. Let's think we know current path of the page, like http://site.com/stats/2012/ , not sure how do I convert these relative paths to real ones? We should get something like: ./some.css => http://site.com/stats/2012/some.css ./extra/some.css => http://site.com/stats/2012/extra/some.css ../../lib/slider/slider.css => http://site.com/lib/slider/slider.css No jQuery,

What is __path__ useful for?

心已入冬 提交于 2019-12-17 07:09:52
问题 I had never noticed the __path__ attribute that gets defined on some of my packages before today. According to the documentation: Packages support one more special attribute, __path__ . This is initialized to be a list containing the name of the directory holding the package’s __init__.py before the code in that file is executed. This variable can be modified; doing so affects future searches for modules and subpackages contained in the package. While this feature is not often needed, it can

Find absolute java.exe path programmatically from java code

落花浮王杯 提交于 2019-12-17 06:48:49
问题 If I have a java jar or class file which is launched by the user (assuming java path is set in environment variables), so how can i from within the code, figure out absolute path of java.exe/javaw.exe from which this file is being launched. Like on ubuntu we can run: % which java and it shows the path. However on windows, if i check System.getenv() it may happen that there are multiple path's found e.g for old or new version. If through cmd line, I run java -version it does not show the path.

How to use Selenium WebDriver on local webpage (on my PC) instead of one located somewhere online?

大兔子大兔子 提交于 2019-12-17 06:46:30
问题 I want to use Selenium WebDriver on a webpage that I have on my hard disc. I've tried to something like: selenium = new WebDriverBackedSelenium(driver, "C:\\...dispatcher.html"); ...instead of the normal: selenium = new WebDriverBackedSelenium(driver, "http://www.dunnowhattodo.org"); ...but it doesn't work (I get the error "unknown protocol: c"). 回答1: Try using this method: webdriver.get("file:///D:/folder/abcd.html"); (or) selenium = new WebDriverBackedSelenium(driver, "file:///D:/folder

How to animate a path on canvas - android

自闭症网瘾萝莉.ら 提交于 2019-12-17 06:30:13
问题 Is possible to attach an animator to a path? Is there any other way to draw on canvas animated lines? I searched this before i post , but there is nothing about this. In two other posts here and here there are walk around solutions and does not fit to me. I post my code inside the onDraw method to specify what exactly I want. paint.setStyle(Paint.Style.STROKE); paint.setStrokeWidth(2); paint.setColor(Color.BLACK); Path path = new Path(); path.moveTo(10, 50); // THIS TRANSFORMATIONS TO BE

How to locate the Path of the current project directory in Java (IDE)?

爱⌒轻易说出口 提交于 2019-12-17 06:28:54
问题 I am trying to locate the path of the current running/debugged project programmatically in Java, I looked in Google and what I found was System.getProperty("user.id") , which didn't get me the project's path. I know the command Environment.currentDirectory in C# gives the path of the current running/debugged project,so I am sure there must be a similar way in Java, too. So I am asking if anyone could tell me or give me a code to how locate the path of the currently running/debugged project

How to get rid of double backslash in python windows file path string? [duplicate]

你。 提交于 2019-12-17 06:10:09
问题 This question already has answers here : Why do backslashes appear twice? (2 answers) Windows path in Python (3 answers) Closed last year . I have a dictionary: my_dictionary = {"058498":"table", "064165":"pen", "055123":"pencil"} I iterate over it: for item in my_dictionary: PDF = r'C:\Users\user\Desktop\File_%s.pdf' %item doIt(PDF) def doIt(PDF): part = MIMEBase('application', "octet-stream") part.set_payload( open(PDF,"rb").read() ) But I get this error: IOError: [Errno 2] No such file or

Are “{Binding Path=.}” and “{Binding}” really equal

可紊 提交于 2019-12-17 06:05:12
问题 In my WPF project, I have a ListBox that displays items from a List<string> collection. I wanted to make the text of these items editable, so I wrapped each of them in an ItemTemplate with a TextBox (might not be the best way, but I'm new to WPF). I was having trouble simply binding the TextBoxes' Text property to the value of each item. I finally stumbled upon an example using a single dot or period for its Path property ( {Binding Path=.} ): <ListBox ItemsSource="{Binding ElementName

Do you need to use path.join in node.js?

醉酒当歌 提交于 2019-12-17 05:45:12
问题 as everyone knows Windows does paths with backslashes where Unix does paths with forward slashes. node.js provides path.join() to always use the correct slash. So for example instead of writing the Unix only 'a/b/c' you would do path.join('a','b','c') instead. However, it seems that despite this difference if you do not normalize your paths (e.g. using path.join) and just write paths like a/b/c node.js has no problem with running your scripts on Windows. So is there any benefit over writing