path

How to round out corners when using CSS clip-path

二次信任 提交于 2019-12-18 05:43:16
问题 I want to be able to round out the 3 leftmost corners on this shape that I have created, any idea how that can be done? div { position: absolute; z-index: 1; width: 423px; height: 90px; background-color: #b0102d; color: white; right: 0; margin-top: 10vw; -webkit-clip-path: polygon(100% 0%, 100% 50%, 100% 100%, 25% 100%, 0% 50%, 25% 0%); clip-path: polygon(100% 0%, 100% 50%, 100% 100%, 25% 100%, 0% 50%, 25% 0%); } <div></div> 回答1: I've recently found success experimenting with approaches like

Convert a Google Maps polygon path to an SVG path

梦想的初衷 提交于 2019-12-18 05:23:22
问题 When a user has drawn a polygon in Google Maps using the built in Drawing Manager I save the polygon path. I want to convert this polygon path to an SVG path so that I can reproduce the shape of the polygon drawn easily, without requiring lots of additional map loads and calls to the Google Maps API. I'm sure it's just some fairly trivial mathematics but can't work out how to do it. Do I need to create a bounding box around the points and translate it to LatLng 0, 0 before scaling it down or

PHP - Relative paths “require”

送分小仙女□ 提交于 2019-12-18 04:49:04
问题 My directory structure looks like this: blog -> admin -> index.php blog.php db.php functions.php I have been trying to include ( require , really) blog.php in the admin/index.php , but facing lots of errors. I'm following a PHP course, and the instructor does the same thing successfully. admin/index.php: require "../blog.php"; which, in turn, requires two more files in its directory. require "db.php"; require "functions.php"; 回答1: If you find that relative include paths aren't working as

Window add Java to Path

不想你离开。 提交于 2019-12-18 04:43:12
问题 I used to use My Computer -> Environment variables to set up PATH for Java, but where can I find the same in Windows 8? 回答1: Click: Windows-Key Type: Control Panel In the control panel search box, enter: path Select Edit environment variables for your account or Edit the system environment variables as needed. The environment variable dialog itself is very similar to the one under previous versions of Windows. 回答2: Set Environment variable using Command Prompt in easy two steps: Example of

Can I use any HTML or JavaScript API to get the file's path in input[type=file]?

我是研究僧i 提交于 2019-12-18 04:23:17
问题 I want to implement an upload image function. After uploading, I want get the file local path so I can create a thumbnail. But how can I get the file path? Is there another way to create the thumbnail? I have tried jQuery-File-Upload plugin. 回答1: I think chrome supports this but not sure whether it is removed due to security reasons.Anyways you can try playing with javascrip to set custom width and height of some div and use readAsDataURL of the uploaded file <script type="text/javascript">

Best method for creating absolute path in PHP? (See 3 methods listed inside)

ⅰ亾dé卋堺 提交于 2019-12-18 03:34:24
问题 I can create paths with no problem, but I want to know which of these 3 methods is the most rock solid and reliable and will work on the most servers. Right now I am using method 1 in my script and some users are having path issues. I just want the method that will work on any version of php and almost any server config. 1. <?php echo $_SERVER['DOCUMENT_ROOT']; ?> 2. <?php echo getcwd(); ?> 3. <?php echo dirname(__FILE__); ?> Thank you so much for any expertise you can provide about this! 回答1

Why (or why not) Add Anaconda to path?

廉价感情. 提交于 2019-12-18 02:58:09
问题 I have found a partial answer in this question: Adding Anaconda to Path or not But I still don't fully understand. I have had a lot of installation issues when switching from a normal installation Python to Anaconda, requiring me to completely re-install Windows... So i want to get this right now. What happens internally when I Add Anaconda (or python for that matter) to the PATH? I plan on working with seperate conda environments for different python versions, what could go wrong if I add

setting JAVA_HOME & CLASSPATH in CentOS 6

时光怂恿深爱的人放手 提交于 2019-12-18 01:43:10
问题 I have unpacked my jdk in /usr/java/. and I put CLASSPATH, PATH, JAVA_HOME into /etc/profile like below. export JAVA_HOME=/usr/java/jdk1.7.0_21 export PATH=$PATH:$JAVA_HOME/bin export CLASSPATH=$JAVA_HOME/jre/lib/ext:$JAVA_HOME/lib/tools.jar And when I compile some java file in /usr/java/jdk1.0.7_21/bin, it works. But when I am doing same thing on other folder, it doesn't. It displays NoClassDefFoundError. So I have checked ClASSPATH, PATH, JAVA_HOME via echo. It shows like below. [root

Absolute URL from base + relative URL in C#

為{幸葍}努か 提交于 2019-12-18 01:32:09
问题 I have a base URL : http://my.server.com/folder/directory/sample And a relative one : ../../other/path How to get the absolute URL from this ? It's pretty straighforward using string manipulation, but I would like to do this in a secure way, using the Uri class or something similar. It's for a standard a C# app, not an ASP.NET one. 回答1: var baseUri = new Uri("http://my.server.com/folder/directory/sample"); var absoluteUri = new Uri(baseUri,"../../other/path"); OR Uri uri; if ( Uri.TryCreate(

Absolute URL from base + relative URL in C#

懵懂的女人 提交于 2019-12-18 01:31:08
问题 I have a base URL : http://my.server.com/folder/directory/sample And a relative one : ../../other/path How to get the absolute URL from this ? It's pretty straighforward using string manipulation, but I would like to do this in a secure way, using the Uri class or something similar. It's for a standard a C# app, not an ASP.NET one. 回答1: var baseUri = new Uri("http://my.server.com/folder/directory/sample"); var absoluteUri = new Uri(baseUri,"../../other/path"); OR Uri uri; if ( Uri.TryCreate(