path

问题 Is there a way to change the path before the page is routed based on some logic, such as a Session variable? For example: // Before routing Router.onBeforeAction(function () { if(Session.get('key') === true) { prependToPath('prefix'); } }); 回答1: You can get the current path using Iron.Location.get().path , run through your logic, and then use the new path in Router.go() . Like so: // If abc is set on the URL, then keep it there if (Session.get('abc') === true) { // You can use better logic

问题 I want to call a js file with wp_enqueue_script . I use get_template_directory() , like so: $myfile = wp_normalize_path(get_template_directory().'/js/script.js'); $myversion = filemtime($myfile); wp_enqueue_script('myscript', $myfile , array( 'jquery' ), $myversion, true ); this works on the server: If I echo $myfile , it returns a real path, like /home/public_html/folder/wp-content/themes/mytwentysixteen/js/script.js , while on the web page it returns the absolute path to the file correctly.

问题 I am using JAX-RS with RESTEasy. I want to know if we can have represent different resources with path differentiated only by order and number of query parameters? e.g. /customer/1234 /customer?id=1234 /customer?name=James Can I create three different methods e.g. @Path("customer/{id}") public Response get(@PathParam("id") final Long id) { .. } @Path("customer?id={id}") public Response get(@QueryParam("id") final Long id) { .. } @Path("customer?name={name}") public Response get(@QueryParam(

问题 I was wondering about this ever since I've started to successfully implement Igraph into my coding: Can you retrieve with get_all_shortest_paths as many shortest paths as you like. Let's say first 10. I've understood so far that retrieving ALL shortest paths in a undirected graph is non-sense since in most cases you have infinite amount of them. But can I simply retrieve first 10 shortest paths? I've tried to achieve this with an undirected g = Graph() : list = [] list.append(g.get_all

问题 Thanks for helping me! I have a string list coming from a path file: Data="M311.97458,250.39993 L213.97533,248.39996 222.37435,216.7998 C222.37435,216.7998 ......589.5753,173.99994 593.1753,179.9999 ......334.3039,253.21373 311.97458,250.39993 z" (the "......." is used for representing uncessary number") As you can see, the characters (like "M" and "C") have some special meaning, and number pairs are for cooridinate. I want to add 1 to each numbers in "Data" without changing any other things

问题 I'm using python 2.7 on 64 bit win7 and have opencv 2.4.x. When I write cv2.imread('pic') it opens pic in my default python path which is C:\Users\Myname . But how I will manage to browse different directory to open images? ie D:\MyPicLib . Meanwhile, I do not want to change default directory, because all my python modules are saved in C:\Users\Myname . I just want to manage connecting pictures in D:\MyPicLib After this part, can you also help me to browse not one but multiple images (in

问题 I'm attempting to call a batch file which is packaged inside of a jar file from the jar file itself. I'm not altogether sure this is possible, but I figured if anyone knew how it would be someone on here. import java.io.IOException; import java.net.URISyntaxException; public class FileLocationFinder { public static void main(String[] args) throws IOException, URISyntaxException { String curdir = System.getProperty("user.dir"); System.out.println("The User.dir = " + curdir); File newFile = new

问题 I have a path like: $path='somefolder/foo/bar/lastdir'; and I want to remove the last part, so I have: $path='somefolder/foo/bar'; Like I went one folder up. I'm really newbie in php, maybe its just one function, although I can't find it anywhere. 回答1: You could try this (tested and works as expected): $path = 'somefolder/foo/haha/lastone'; $parts = explode('/', $path); array_pop($parts); $newpath = implode('/', $parts); $newpath would now contain somefolder/foo/haha . 回答2: use : dirname

问题 This question already has answers here : How to find the working folder of a servlet based application in order to load resources (3 answers) Closed 3 years ago . I need to get the web container path using java, is there any method for that? I need to use it using JSP or Servlet to get a file path. 回答1: I need to use it using JSP or Servlet to get a file path. So the file is stored in the public webcontent of the WAR? Use ServletContext#getRealPath(). String relativeWebPath = "/file.jpg";

问题 I create a function that downloads a image to my local web server. When I run this function like a Java Application, it works fine. But when I try to run this method using the Web Service made by AXIS2 ( http://localhost:8080/axis2/services/adoroCinemaService2/downloadPhoto ), the AXIS2 returns Internal server error. It happens probabily, because I use a "root path" in my code. So, what I need to do to solve this problem? Where is the root of my service? How can I setup this path? public void