path

问题 Using MAMP + MAMP Pro 3.5 for local development. Using the envvars file, I'm supplying my own PATH, that is different from the PATH for any other user or purpose. Let's pretend it's /my/unique/custom/path . I put the following file on my local development site: <ol> <li><?php print $_SERVER['PATH']; ?></li> <li><?php print $_ENV['PATH']; ?></li> <li><?php print exec('echo $PATH'); ?></li> </ol> And this is the result: /my/unique/custom/path /my/unique/custom/path /usr/gnu/bin:/usr/local/bin:

问题 I have a webapp running in my local Tomcat. The path is: tomcat/webapps/myproject . I have some resources in this project all in a folder with this path: tomcat/webapps/myproject/resources So, I am trying to acces to this resources from a Java project, using a file config.properties . In this file I have something like this: tomcat.url= http://localhost tomcat.port=8080 tomcat.resources=/myproject/resources I tryed also different combinations of / or \ but I get this error running my project:

问题 Based on my testing, bash is very happy with ~ in $PATH but /usr/bin/which is not. Is there any standard (like POSIX) regarding this? Example: [STEP 100] # echo $BASH_VERSION 4.4.12(1)-release [STEP 101] # echo $PATH /root/bin:/usr/sbin:/usr/bin:/sbin:/bin [STEP 102] # /usr/bin/which passh /root/bin/passh [STEP 103] # type passh passh is /root/bin/passh [STEP 104] # [STEP 105] # PATH='~/bin':/usr/sbin:/usr/bin:/sbin:/bin [STEP 106] # echo $PATH ~/bin:/usr/sbin:/usr/bin:/sbin:/bin [STEP 107] #

问题 I am trying to open a file on another folder with nodejs using an absolute path. This file contains a js program that has to be executed the node. I am using johnny five to program an Arduino but the file is not in the same folder as the node files and the libraries. How can this be done? 回答1: require('C:\\run.js') This will get 'run.js' file from C disk. But if you already tried this, than please can you explain in more detail what you want to do? 来源： https://stackoverflow.com/questions

问题 I installed ffmpeg on mac through brew install. When i run ffmpeg command from terminal, it is running fine. But when i create a program in java and execute command like Runtime.getRuntime().exec("ffmpeg"); It is throwing IOException Cannot run program "ffmpeg":error=2, No such file or directory. Any idea how to resolve it? 回答1: Try using the below code String[] command = new String[]{"/bin/bash","-c","ffmpeg -version"}; Process p = Runtime.getRuntime().exec(command); 来源： https:/

问题 I want to write a gradle script which will run ruby (sass). The way I do it now is task compileCss (type: Exec){ def dir = "" if (System.properties['os.name'].toLowerCase().contains('windows')) { dir = "C:\\ruby22\\bin\\sass.bat" } else { dir = "/usr/bin/sass" } commandLine dir, '--update', 'source.scss:dest.css' } I don't like this code for the obvious concern that someone may install ruby in a "non-standard" directory (such as /usr/local/bin :) ). Is there a way to see if sass is in path

问题 I'm trying to figure out how to plug in a bootstrap theme. I have the compass-rails gem and Rails 4. I have a series of errors showing in my console which say: Failed to load resource: the server responded with a status of 404 (Not Found) I think its because my paths to where the vendor assets are saved are not correct. I have a layout called 'profile.html.erb' In that layout, i have included: <link href="vendor/assets/stylesheets/magnific-popup.css" rel="stylesheet" type="text/css"/> The css

问题 I'm trying to write a bash script that is jumping into each subfolder and then jumps back to main folder (and so on...). The difficulty are the path names that have spaces. for path in "`find -type d | tr -d './'`" do echo "Next Pathname: $path" cd $path echo "I'm in path $pathr" cd .. done The Error Message is "filename or path not found". When I change cd $path to "cd $path" then I get the error message "filename too long". Could you help me? - I don't know how to separate this string (or

问题 I have been trying hard to set the animation on circle. I have reached to this point : <svg version="1.1" id="Layer_1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px" viewBox="0 0 376 56.6" enable-background="new 0 0 376 56.6" xml:space="preserve"> <path fill="#232527" d="M345.8,53.3C345.8,53.3,345.8,53.3,345.8,53.3c-1.1,0-2.2-0.7-2.7-1.7l-21.7-44c-0.7-1.5-0.1-3.3,1.4-4 c1.5-0.7,3.3-0.1,4,1.4l19,38.6l19.2-38.6c0.7-1.5,2.5-2.1,4-1.3c1.5,0.7,2.1,2.5

问题 I am looking for a way to retrieve the path to the all users start menu directory in C++. I am only able to get the one of the current user (using Qt): QString startMenuPath = QStandardPaths::standardLocations(QStandardPaths::ApplicationsLocation).at(0); However, Qt does not allow to retrieve the one for all users. As far as I know there also is no environment variable containing that path, that I could read. 回答1: To get a known folder, use SHGetFolderPath, and pass a KNOWNFOLDERID or CSIDL