path

问题 I am trying to display a page to show all products by current user. Because of this, I have created a new page showall.html.erb under products view. I have done the following: ProductsController def showall @products = current_user.products end routes resources :products do get :showall end I am aware that because of the nested resources the URL Pattern became /products/:product_id/showall(.:format) How do I actually get rid of the product_id part to achieve /products/showall to have one

问题 I have a zip file that has a path. When I unzip the file using python and put it in my target folder, it then creates all of the files in the path inside my target folder. Target: d:\unzip_files zip file has a path and file name of: \NIS\TEST\Files\tnt.png What happens: d:\unzip_files\NIS\TEST\Files\tnt.png Is there a way to hae it just unzip the tnt.png file into d:\unzip_files? Or will I have to read down the list and move the file and then delete all of the empty folders? import os, sys,

问题 my question is pretty much what the title suggests. my research has led me to try something like this: import os pathname = os.path.abspath("some/relative/directory") print pathname this problem is that whenever i do something like this, it simply returns whatever relative directory i gave it preceded by my python directory. for example: C:\Python27\some\relative\directory which is not even an existing directory on my computer. i understand that the python interpreter searches the working

问题 My php file is here: D:/Appserv/www/x/y/file.php I want to load stuff from this folder: E:/foldie I don't know what path will lead me there. $somePath="HELP ME HERE!!!!" $dir=opendir($somePath); //looping through filenames while (false !== ($file = readdir($dir))) { echo "$file\n"; } 回答1: Use full Windows path to the file it should be working: "E:\folder\file.txt" or just copy the file in the local/project directory for testing purpose. 回答2: Set $somePath = "e:\\foldie" . If that doesn't work

问题 In my application I have a lot of pictures divided into few categories (the following is an application tree inside a project and at my HDD): ApplicationName - Resources -- Thumbs -- Images -- Buttons -- Default.png In the thumbs folder I have a lot of .png files. The problem is I want to know how many of these files are in this folder. I type such a command: NSArray *namesArray = [[NSBundle mainBundle] pathsForResourcesOfType:@".png" inDirectory:@"Resources/Thumbs"]; And it doesn't find any

问题 Let's say I have the current file structure : app\modules\module.py app\modules\somefile.txt app\scripts\script.py app\main.py modules\script.py : import sys sys.path.append("..\\") from modules.module import module [...] main.py : import sys from modules.module import module [...] modules\module.py : [...] fileToRead="somefile.txt" The problem is : If my module is imported from main.py, the path to somefile.txt should be "modules\\somefile.txt" If my module is imported from script.py, the

问题 When I have a path, I can use os.path.split() in Python to get directory name, and file name. >>> x = '/a/b/c/hello.txt' >>> import os.path >>> os.path.split(x) ('/a/b/c', 'hello.txt') What's the equivalent function in Objective-C/cocoa? 回答1: There is an easier way (well, than messing with subarrays); look in NSPathUtilities.h. - (NSString *)lastPathComponent; - (NSString *)stringByDeletingLastPathComponent; - (NSString *)stringByAppendingPathComponent:(NSString *)str; - (NSString *

问题 I am working on a simple map drowning with svg path tag But it dose not work on fire fox or IE (the drawing itself does not appear) hear is a sample of them <svg xmlns="http://www.w3.org/2000/svg" version="1.1"> <path id="lineAB" d= "M450.59,294.28l3.64-0.29l5.97,8.44l-5.54,4.18l-4.01-1.03l-5.39,0.07l-0.87,3.16l-4.52,0.22l-1.24-1.69l1.6-5.14L450.59,294.28L450.59,294.28z" stroke="blue" stroke-width="3" fill="blue" onclick="alert('Hello')"/> </svg> 回答1: You shouldn't be using commas for the d

问题 I have some code that looks like that: GraphicsPath p = new GraphicsPath(); // Add some elements to p ... // ... g.FillPath(bgBrush, p); // where g : Graphics and bgBrush : Brush Which results in something that looks like this: ### | ##| ## | How can I fill the exact complement of the path? Desired output: #| ## | # #| 回答1: I'm surprised no one answered so far - the solution is pretty simple. Just add a Rectangle to the path and everything inside gets reverted. protected override void OnPaint

问题 I am new to the batch script programming.Getting error while executing batch file if I give the relative path. I have following folder structure Script folder - C:\batch\script\ServiceRegister.bat Bin path - C:\batch\bin\ERecruitGenerateReportsWindowsService.exe ServiceRegister.bat Batch file – %windir%\Microsoft.NET\Framework\v4.0.30319\InstallUtil.exe %~dp0%~1\bin\ERecruitGenerateReportsWindowsService.exe When I execute ServiceRegister.bat file I got the error: Exception occurred while