partitioning

Counting through all binary numbers with equal 1's and 0's

爱⌒轻易说出口 提交于 2019-12-23 18:52:56
问题 I'm implementing a binary representation of an equal-side bi-partitioning algorithm and I'm wondering what the best way to iterate through all combinations of N bits that have equal (N/2) 1's and 0's. I'm trying to find the quickest way, not the easiest to code. Thanks. 回答1: It's just (N choose N/2) ; you're choosing which bits are 0s, the rest are 1s. If you have 10 bits, and you want 5 zeroes and 5 ones, there are (10 choose 5) = 252 possibilities. See also: Algorithm to return all

Spring Batch thread-safe Map job repository

一世执手 提交于 2019-12-23 15:49:37
问题 the Spring Batch docs say of the Map-backed job repository: Note that the in-memory repository is volatile and so does not allow restart between JVM instances. It also cannot guarantee that two job instances with the same parameters are launched simultaneously, and is not suitable for use in a multi-threaded Job, or a locally partitioned Step. So use the database version of the repository wherever you need those features. I would like to use a Map job repository, and I do not care about

SemanticException Partition spec {col=null} contains non-partition columns

耗尽温柔 提交于 2019-12-23 12:51:08
问题 I am trying to create dynamic partitions in hive using following code. SET hive.exec.dynamic.partition = true; SET hive.exec.dynamic.partition.mode = nonstrict; create external table if not exists report_ipsummary_hourwise( ip_address string,imp_date string,imp_hour bigint,geo_country string) PARTITIONED BY (imp_date_P string,imp_hour_P string,geo_coutry_P string) row format delimited fields terminated by '\t' stored as textfile location 's3://abc'; insert overwrite table report_ipsummary

Partitioning an array on a Pivot

你离开我真会死。 提交于 2019-12-23 12:34:13
问题 I am trying to write a simple algorithm for moving the elements around pivot such that the elements on the left of pivot is smaller than the pivot and the element on the right of pivot is greater than it (the same step in quick sort). I have written code that works, but after that I changed the algorithm to the below, and it is not working. The idea of the algorithm is simple. Have two pointers, one at the beginning of the array and one at the end of array. If the elements pointed by i are

Dynamic table partitioning in postgres

空扰寡人 提交于 2019-12-23 09:27:04
问题 I was looking up ways to have postgres partition data into tables based on timestamp for example, but without having to add the relevant child tables manually. I saw this blog post that does just that https://blog.engineyard.com/2013/scaling-postgresql-performance-table-partitioning but I'm dubious about the idea of creating tables based on string concatenation and checking the pg_catalog. Is this a reasonable idea? 回答1: pg_partman is an extension created specifically to manage the complexity

Soundcloud API support pagination?

雨燕双飞 提交于 2019-12-23 06:39:06
问题 How would I use the "linked_partitioning=1" to call on the "next_href" in the response? I see the next_href in the response, but I don't know what to do next? :\ Please help Thank you in advance :) 回答1: You just have to make a call to this url. Read more here: https://developers.soundcloud.com/blog/offset-pagination-deprecated https://developers.soundcloud.com/docs/api/guide#errors EDIT: According to your comments, i have added some code in JS, which print all tracks from Boilerroom. Using

Soundcloud API support pagination?

你说的曾经没有我的故事 提交于 2019-12-23 06:38:28
问题 How would I use the "linked_partitioning=1" to call on the "next_href" in the response? I see the next_href in the response, but I don't know what to do next? :\ Please help Thank you in advance :) 回答1: You just have to make a call to this url. Read more here: https://developers.soundcloud.com/blog/offset-pagination-deprecated https://developers.soundcloud.com/docs/api/guide#errors EDIT: According to your comments, i have added some code in JS, which print all tracks from Boilerroom. Using

Soundcloud API support pagination?

六月ゝ 毕业季﹏ 提交于 2019-12-23 06:38:16
问题 How would I use the "linked_partitioning=1" to call on the "next_href" in the response? I see the next_href in the response, but I don't know what to do next? :\ Please help Thank you in advance :) 回答1: You just have to make a call to this url. Read more here: https://developers.soundcloud.com/blog/offset-pagination-deprecated https://developers.soundcloud.com/docs/api/guide#errors EDIT: According to your comments, i have added some code in JS, which print all tracks from Boilerroom. Using

Faster way to load huge data warehouse table

此生再无相见时 提交于 2019-12-23 02:40:35
问题 I have a table in oracle 11g with size 62GB and 1.2 billion records. Table has 4 columns, range partitioned on month and hash sub partition on transaction number. Around 80 million records are delated and re-inserted into this table once in every week. This delete & insert process is taking ~4 hours when done with NOAPPEND PARALLEL hint and . Is there any way i could speed up this process? One way i could think is to replace NOAPPEND with APPEND but that will lead to space wastage and drastic

faster algorithms for minimum maximum contiguous k partition

别说谁变了你拦得住时间么 提交于 2019-12-23 02:18:44
问题 I was reading this http://www.cas.mcmaster.ca/~terlaky/4-6TD3/slides/DP/DP.pdf and would like to know if there exists a solution with better time complexity to the partition problem. From the link: "Suppose a given arrangement S of non-negative numbers {s1,...,sn} and an integer k. How to cut S into k or fewer ranges, so as to minimize the maximum sum over all the ranges?" e.g. S = 1,2,3,4,5,6,7,8,9 k=3 By cutting S into these 3 ranges, the sum of the maximum range (8,9) is 17, which is the