pack

问题 I'm trying to use the struct.pack function import struct values = (0, 44) s = struct.Struct('HI') b = s.pack(*values) print(b) print(str(len(b))) and it gives me this output: b'\x00\x00\x00\x00,\x00\x00\x00' 8 while the python docs say: Format - C Type - Python type - Standard size - Notes H - unsigned short - integer - 2 - (3) I - unsigned int - integer - 4 - (3) so len() should be 2 + 4 = 6, and I need bytes with size = 6 Any ideas? I'm using Python 3.6 on Windows 10 回答1: pack will add pad

问题 http://jsfiddle.net/UWLsB/189/ I am trying to make the image slide to the left after 7 seconds, how come it's not working? Html: <div id="container"> <div id="pack"> <img id="pack" src="http://imgur.com/uGMzOGM.png"> </div> Javascript: function FetchData() { $("#pack").css('margin-left', 0); $("#pack").css('margin-right', 0); $("#pack").animate({ left: '-1000px' }, 'slow'); }); } setTimeout(FetchData, 7000); CSS: #pack { margin: 5px auto; position:fixed; } #container { overflow:hidden; } 回答1:

问题 I'm having trouble converting the following code from Perl to PHP. In particular, I'm having trouble with this section, as I have no clue what is happening here: sub md5sum($) { my @ib = unpack("C*", shift); my $encstr = join("", map {sprintf('\%3.3o', $_)} @ib); my ($out) = split(/ /, `printf '$encstr' | md5sum`); return $out; } The main point I'm looking for help on is what does the "C*", shift do in the unpack statement, what's going on in the join part, and what does the | md5sum do at

问题 I need to convert integer to a 4 byte (32 bit) hex for sending it as ACK to a device i am currently trying to integrate. For example 3 = 00000003 15 = 0000000F Check http://www.mathsisfun.com/binary-decimal-hexadecimal-converter.html 1. Select signed 32 bit from the dropdown 2. Enter the value in decomal text box 3. Check value in hex field. I am using php pack function with this parameter but based on the response from the device, it does not seem to be the correct approach. $reply = pack(L*

问题 I'm trying to parse out a single page from YouTube... Which isn't really free of syntax errors. Html Agility Pack screams about these errors, and returns nothing in result. http://codepaste.net/gh3hco 回答1: I haven't tried this, but based on a suggestion in their forum you can use HTML Tidy or Tidy.NET to clean the HTML first. Optionally, you could find the erroneous tags and remove them in a pre-process step. 来源： https://stackoverflow.com/questions/6182404/ignoring-parse-errors-with-html

问题 Here's my current GUI layout for my checkers game: As you can see, it consists of a Menu along the top, a Canvas on the left where I draw the checkerboard, a toolbar (Frame) on the top right where I have various formatting/navigation buttons, and a Text widget that is used to annotate moves. Currently, I am using a grid layout for the widgets. Here's what I need to do: Be able to show/hide a scrollbar in the Text widget when the amount of text grows larger than the widget size. (This seems to

问题 I have some 256-character strings of hexadecimal characters which represent a sequence of bit flags, and I'm trying to convert them back into a bitstring so I can manipulate them with & , | , vec and the like. The hex strings are written in integer-wide big-endian groups, such that a group of 8 bytes like "76543210" should translate to the bitstring "\x10\x32\x54\x76" , i.e. the lowest 8 bits are 00001000 . The problem is that pack 's " h " format works on one byte of input at a time, rather

问题 I would like to pack all the data in a list into a single buffer to send over a UDP socket. The list is relatively long, so indexing each element in the list is tedious. This is what I have so far: NumElements = len(data) buf = struct.pack('d'*NumElements,data[0],data[1],data[2],data[3],data[4]) But I would like to do something more pythonic that doesn't require I change the call if I added more elements to the list... something like: NumElements = len(data) buf = struct.pack('d'*NumElements

问题 I got this code working, which converts from hex to base64, and vice versa. I got to_base64 from another SO question, and I wrote to_hex with some guesswork and trial and error. class String def to_base64 [[self].pack("H*")].pack("m0") end def to_hex self.unpack("m0").first.unpack("H*").first end end But I don't really grok the pack and unpack methods, even after reading the docs. Specifically, I'm confused by the asymmetry between the two implementations. Conceptually, in both cases, we take

问题 i am having some problems using pack() in php $currencypair = "EUR/USD"; $buy_sell = "buy"; $alert_device_token =array("a","a","b"); $message = "Your " . $currencypair . " " . $buy_sell . " alert price has been reached!"; $payload['aps'] = array ( 'alert' => $message, 'badge' => 1, 'sound' => 'default' ); $payload = json_encode($payload); foreach ($alert_device_token as $alert_device) { $apnsMessage = chr(0) . chr(0) . chr(32) . pack('H*', str_replace(' ', '', $alert_device)) . chr(0) . chr