overriding

how to override a method in java and then call the superclass method

由 只愿长相守 提交于 2019-12-02 20:29:44
问题 I am trying to override a method in the superclass in my java subclass and then call the overriden method from the superclass. Is this the correct way to do it. The method in the super class i want to overrride is called describe() public static void describe() { Item.describe(); } 回答1: Use the super keyword. @Override public void describe() { super.describe(); } Note the annotation which although is not necessary is "correct". As was pointed out, static methods do not get inherited. It's

Which operator needs to be overridden in order to use std::set in the C++ code?

由 ◇◆丶佛笑我妖孽 提交于 2019-12-02 19:32:34
问题 This is an interview question. Referring to the sample code, which one of the operators needs to be overridden in order to use std::set<Value> #include<iostream> class Value { std::string s_val; int i_val; public: Value(std::string s, int i): s_val(s) , i_val(i){} }; // EOF /* a operator != b operator > c operator <= d operator >= e operator < */ Actually, I do not understand why an operator needs to be overridden here. "set" does not allow duplicated elements, maybe operator != needs to be

How can I override methods in Java when I create an Object via reflection?

由 匆匆过客 提交于 2019-12-02 19:28:59
In Java , is it possible to override methods in a class that you create using reflection ? For example, say I have the following class: public class MyObject { public String foo, bar; public MyObject(String foo) { this.foo = foo; this.bar = foo + "bar"; } public void setBar(String bar) { this.bar = bar; } } And in one class I want to create it directly and override its setBar method as follows: MyObject obj = new MyObject("something") { @Override public void setBar(String bar) { this.bar = this.foo; } }; Is there a way to override a method in this same manner using reflection? Maybe something

How do I override CSS set on a pseudo element?

由 痴心易碎 提交于 2019-12-02 17:23:50
I know that has been asked before, but I find no clean way of overriding this CSS: .ui-input-search:after { content: ""; height: 18px; left: 0.3125em; margin-top: -9px; opacity: 0.5; position: absolute; top: 50%; width: 18px; } I need to leave ui-input-search on the element, but can add my own class, like: .ui-input-search-no-pseudo:after { content: ""; } Question : Is there an easy way to remove "pseudo-css" without having to overwrite the CSS line by line? Thanks! Sacha As far as I can tell there is no other way than to override all properties. The styles are defined on the element, they won

Override identifier after destructor in C++11

由 好久不见. 提交于 2019-12-02 17:14:57
Does the override identifier after virtual destructor declaration have any special meaning? class Base { public: virtual ~Base() {} virtual int Method() const {} }; class Derived : public Base { public: virtual ~Derived() override {} virtual int Method() override // error: marked override, but does not override - missing const {} }; Using override identifier on virtual method is useful as check: compiler will report error when the Base virtual method is actualy not overriden. Does override on virtual destructor has any meaning/function too? John Dibling It is not override that has special

Does final imply override?

由 你离开我真会死。 提交于 2019-12-02 16:58:48
As I understand it, the override keyword states that a given declaration implements a base virtual method, and the compilation should fail if there is no matching base method found. My understanding of the final keyword is that it tells the compiler that no class shall override this virtual function. So is override final redundant? It seems to compile fine . What information does override final convey that final does not? What is the use case for such a combination? final does not require the function to override anything in the first place. Its effect is defined in [class.virtual]/4 as If a

Override and reset CSS style: auto or none don't work

由 落花浮王杯 提交于 2019-12-02 16:32:51
I would like to override following CSS styling defined for all tables: table { font-size: 12px; width: 100%; min-width: 400px; display:inline-table; } I have specific table with class called 'other' . Finally table decoration should looks like: table.other { font-size: 12px; } so i need remove 3 properties: width , min-width and display I tried to reset with none or auto , but didn't help, I mean these cases: table.other { width: auto; min-width: auto; display:auto; } table.other { width: none; min-width: none; display:none; } I believe the reason why the first set of properties will not work

Is it wrong trying to suppress overriding on a case by case basis? [closed]

由 梦想的初衷 提交于 2019-12-02 16:31:34
问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 5 years ago . I understand why polymorphism achieved through method overriding is very useful. I am asking what problems, if any, might arise with trying to suppress it in certain situations, at the time the polymorphic object is received as an argument (not at the time its class is

Stack overflow exception thrown from overridden property from abstract base class

由 与世无争的帅哥 提交于 2019-12-02 16:22:39
问题 I have a base class with the following (trimmed for brevity) declaration: public abstract class MyBaseClass { public int RecordId { get; private set; } public string ObjectName { get; set; } public abstract string Status { get; set; } public GetMyObject(int id) { MyObject myObject = context.GetObjectById(id); this.RecordId = myObject.RecordId; this.ObjectName = myObject.ObjectName; this.Status = myObject.Status } } Which is used by the following class: public class MySpecificClass :

How does java compiler choose correct methods and variables in inheritance

由 微笑、不失礼 提交于 2019-12-02 15:01:16
问题 I am a bit confused when inheritance and type casting is mixed. I want to understand the rules which java compiler follows when choosing correct methods and variables in inheritance. I have read something like Variables are bound at compile time and methods are bound at run time. The second one is from stackoverflow (@John Skeet) Overload resolution (which method signature is called) is determined at compile-time, based on the compile-time types of both the method target and the argument
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