overloading

This question already has an answer here : Order of implicit conversions in c# (1 answer) Closed 12 months ago . Consider the following code: public class Test { public static implicit operator int(Test t) { return 42; } public override string ToString() { return "Test here!"; } } var test = new Test(); Console.WriteLine(test); // 42 Console.WriteLine((Test)test); // 42 Console.WriteLine((int)test); // 42 Console.WriteLine(test.ToString()); // "Test here!" Why in the first three cases we have answer 42 even if we explicitly cast to Test ? Does implicit operator have higher priority over

Assume that there is a third-party library written in FSharp, it contains several generic classes, for example as follows: type FirstType<'a> has method DoWork , that accepts: first param of type FirstType<'a> , second param is a function of type ('a -> 'b) DoWork method return type is FirstType<'b> type SecondType<'a> has method DoWork , that accepts: first param of type SecondType<'a> , second param is a function of type ('a -> 'b) DoWork method return type is SecondType<'b> type ThirdType <'a> has method DoWork , that accepts: first param of type ThirdType <'a>, second param is a function

Let's say I have a class named ClothingStore. That class has 3 member functions, that point a visitor to the right department of the store. Member functions are ChildrenDept, MenDept and WomenDept, depending on whether the visitor is a child, a man or a woman. Function overloading can be used to make 3 functions that have same name, say, PointToDept, but take different input argument ( child, man, woman ). What is actually happening on run-time when program is executing ? My guess is that compiler adds switch statements to the program, to select the right member function. But that makes me

How can one define a function in Isabelle that has a different definition depending on either the type of its argument, or the type of the context it is used in? For example, I might want to define a functions is_default with type 'a ⇒ bool , where each different type 'a has a potentially different "default value". (I am also assuming, for the sake of argument, that existing concepts such as zero are not suitable.) This kind of overloading looks like a perfect fit for type classes. First you define a type class for your desired function is_default : class is_default = fixes is_default :: "'a ⇒

I would think that the following code should be working, but both g++ and clang++ return the exact same error (although Visual C++ 2012 doesn't). #include <iostream> #include <tuple> template <int N, typename T> struct A { }; template <typename Tuple> double result(const Tuple& t, const A<0, typename std::tuple_element<0, Tuple>::type>& a) { return 0; } template <typename Tuple> double result(const Tuple& t, const A<std::tuple_size<Tuple>::value-1, typename std::tuple_element<std::tuple_size<Tuple>::value-1,Tuple>::type>& a) { return 1; } template <typename Tuple, int N> double result(const

Does php support method overloading. While trying below code it suggests it supports method overloading. Any views class test { public test($data1) { echo $data1; } } class test1 extends test { public test($data1,$data2) { echo $data1.' '.$data2; } } $obj = new test1(); $obj->test('hello','world'); As i have overload the method it gives the output as "hello world". Above code snippet suggests php supports method overloading. So my question is does php support method overloading. You should make the difference between method overriding (your example) and method overloading Here is a simple

For example, I need to see if a string contains a substring, so I just do: String helloworld = "Hello World"; if(helloworld.Contains("ello"){ //do something } but if I have an array of items String helloworld = "Hello World"; String items = { "He", "el", "lo" }; I needed to create a function inside the String class that would return true if either of the items inside the array is contained in the string, for example. I would like to override the function Contains(string) with Contains(IEnumerable) for this scenario, instead of creating a function in another class. Is it possible to do this,

I don't understand why the compiler can't resolve the correct overload to use here. (code below) There is only one version of Add() that is appropriate- BigFoo is an IFoo, and does not implement IEnumerable where T is an IFoo. But it insists on reporting an ambiguity. Any ideas? I tried adding a second generic type parameter- Add where T : IFoo where U : IEnumerable. But then the overload is completely ignored even for legitimate use. I know I can work around this with casting and specifying generic type parameters but at that point I've defeated the purpose of having an overload. You could

I would to know how get this code compiles: // test3.cpp #include <iostream> using namespace std; template<typename R, typename... rArgs> R universal_exer(R(*f)(rArgs...), rArgs... args) { return (*f)(forward<rArgs>(args)...); } int addition(int a) { return a; } int addition(int a, int b) { return a + b; } template<typename... Args> int addition(int a, int b, Args... args) { return a + b + addition(args...); } int main() { cout << universal_exer(&addition, 1) << endl; } Error message (gcc 4.7.2): test3.cpp: In function 'int main()': test3.cpp:31:40: error: no matching function for call to

In dynamic languages like JavaScript/Python, it's possible to overwrite or "modify" functions during run-time. For example, in order to modify the alert function in JS, one could do: const _prev_alert = window.alert; window.alert = function() { _prev_alert.apply(this, arguments); console.log("Alert function was called!"); } This would output "Alert function was called!" to the console every time the alert function is called. Now, obviously something like this would be impossible during runtime in Kotlin-JVM or Kotlin-Native due to their static nature. However, in regards to those same