overlap

问题 I'm having difficulty counting overlaps of intervals as I would expect. Here is an R data.table with intervals defined by start to end: > library(data.table) > dt1 = data.table(start=c(1, 5, 3), end=c(10, 15, 8)) > print(dt1) start end 1: 1 10 2: 5 15 3: 3 8 Here is how I would consider overlaps for these intervals, from 0 to 20: [0, 1]: 0 (there are no intervals here) [1, 3]: 1 (there is only one interval here, from [1, 10]) [3, 5]: 2 (two intervals here, both [1, 10] and [3, 8]) [5, 8]: 3

问题 I am trying to solve a question wherein overlapping intervals need to be merged: https://leetcode.com/problems/merge-intervals/description/ The question is: Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. I tried my solution: # Definition for an interval. # class Interval: # def __init__(self, s=0, e=0): # self.start = s # self.end = e class Solution: def merge(self, intervals): """ :type intervals:

问题 Right now, I have a ball that moves around the screen in a random diagonal direction and bounces off the wall when it collides with it. An image of said program My end goal is to have the ball be a matrix and have it perform just the same around a 30x30 grid. I have tried the enumerate() function, but couldn't think of how to make it perform like it does in the picture and code I have referenced at the end of this post. by perform, I mean move randomly in a diagonal direction on the screen

问题 My Problem Consider a set of data with two intervals. For instance, consider a student schedule of classes. Each record has a begin and end date, and each class has a period start time and a period end time. But this schedule is not 'normalized' in the sense that some records overlap. So if you search for records encompassing a given date and period for a student, you might get multiple matches. Here's a contrived example. I represent the dates as integers to simplify the problem: declare

问题 I am studying CalDAV protocol. I have some question for time conflict or overlap for CalDAV. Let me explain by instance for some scenario. I made an event PM1 ~ PM6 in calendar. And then I try to made another event PM2~7 in same calendar. It is time conflict or overlap. How does CalDav server resolve this conflict? Does server make error when second event make? I did search out RFC 6638. But I could not find solution. Please help my question. Thanks for reading. 回答1: It is up to the CalDAV

问题 I am studying CalDAV protocol. I have some question for time conflict or overlap for CalDAV. Let me explain by instance for some scenario. I made an event PM1 ~ PM6 in calendar. And then I try to made another event PM2~7 in same calendar. It is time conflict or overlap. How does CalDav server resolve this conflict? Does server make error when second event make? I did search out RFC 6638. But I could not find solution. Please help my question. Thanks for reading. 回答1: It is up to the CalDAV

问题 I am studying CalDAV protocol. I have some question for time conflict or overlap for CalDAV. Let me explain by instance for some scenario. I made an event PM1 ~ PM6 in calendar. And then I try to made another event PM2~7 in same calendar. It is time conflict or overlap. How does CalDav server resolve this conflict? Does server make error when second event make? I did search out RFC 6638. But I could not find solution. Please help my question. Thanks for reading. 回答1: It is up to the CalDAV

问题 I have a multiple dataframe like below. df1 = pd.DataFrame({'Col1':["aaa","ddd","ggg"],'Col2':["bbb","eee","hhh"],'Col3':"ccc","fff","iii"]}) df2= pd.DataFrame({'Col1':["aaa","zzz","qqq"],'Col2':["bbb","xxx","eee"],'Col3':["ccc", yyy","www"]}) df3= pd.DataFrame({'Col1':"rrr","zzz","qqq","ppp"],'Col2':"ttt","xxx","eee","ttt"],'Col3':"yyy","yyy","www","qqq"]}) The dataframe has 3 columns and sometimes their rows overlap among the dataframes. (e.g. df1 and df2 has an identical row as "aaa, bbb,

问题 I (just like everyone else here) am running into the same Status Bar overlap issue that everyone else is, with a little twist, and that is why I opening a new question about this. There seems to be some mechanism that lets the UISearchBar know where to position it self, which is totally out of whack. jaredsinclair answer here (iOS 7 status bar back to iOS 6 default style in iPhone app?) , explains in great detail how the Apple Engineers allow us to introduce logic to our application in order

问题 Given a 3D coordinate system and rectangular prisms with a non-negative starting point and a non-negative size (e.g. starts at (0, 2, 5) and has a size of (9, 20, 5) ): how can I best check if another rectangular prism intersects with one of the prisms already in the coordinate system? Eventually, the goal would be to perform this check for all prisms present, being able to test one should be sufficient to complete this task. Info: starting points and sizes are 3-tuples of non-negative longs.