overflow

问题 I am working on a project in which one of the sections is filled with elements by requesting data from the database, therefore the number of elements in it is extremely variable. The tricky part is that our design is based on the idea of not having to scroll on the page, but instead scroll on the sections if it is necessary. I thought using overflow on the sections would suffice but it does not give me the intended result. I tried all of the variations of the overflow property, scroll

问题 I am working on a project in which one of the sections is filled with elements by requesting data from the database, therefore the number of elements in it is extremely variable. The tricky part is that our design is based on the idea of not having to scroll on the page, but instead scroll on the sections if it is necessary. I thought using overflow on the sections would suffice but it does not give me the intended result. I tried all of the variations of the overflow property, scroll

问题 hi i am having some problem with integer over flow in fortran 90. The maximum range of integer number is 10 digits.but, I want to deal with integer of the range 1E13. So what is the way of avoiding this? 回答1: define your variable as integer(kind=8) :: intVar To have a portable code, use the function selected_int_kind. In your case integer, parameter, k14 = selected_int_kind(14) integer(kind=k14) :: intVar selected_int_kind(r) returns the kind value of the smallest integer type that can

问题 hi i am having some problem with integer over flow in fortran 90. The maximum range of integer number is 10 digits.but, I want to deal with integer of the range 1E13. So what is the way of avoiding this? 回答1: define your variable as integer(kind=8) :: intVar To have a portable code, use the function selected_int_kind. In your case integer, parameter, k14 = selected_int_kind(14) integer(kind=k14) :: intVar selected_int_kind(r) returns the kind value of the smallest integer type that can

问题 hi i am having some problem with integer over flow in fortran 90. The maximum range of integer number is 10 digits.but, I want to deal with integer of the range 1E13. So what is the way of avoiding this? 回答1: define your variable as integer(kind=8) :: intVar To have a portable code, use the function selected_int_kind. In your case integer, parameter, k14 = selected_int_kind(14) integer(kind=k14) :: intVar selected_int_kind(r) returns the kind value of the smallest integer type that can

问题 .container { /* Container's width can be dynamically resized. I put width = 300px in the example to demonstrate a case where container's width couldn't hold second msg */ width: 300px; display: flex; flex-direction: column; align-items: flex-start; padding: 1em; background-color: blue; } .parent{ display:flex; flex-direction:row; flex-wrap:nowrap; padding:1em; background-color:red; box-sizing:border-box; margin-bottom: 1em; } .name{ background-color:mistyrose; width: 70px; padding: 1em; }

问题 I have a div that encapsulates many unordered lists (ul). I have each ul set to "float:left". And I also have the parent div that contains them set to "overflow-x:scroll". What's happening is the ul's are wrapping when they hit the edge of the page and not staying side by side to take advantage of the scrolling property of the parent div (the scroll bars are there). Why? How can I fix this? Thanks for any help. 回答1: you need to insert those uls in another div, to which you'll give width=

问题 I have always wondered what happens in case a double reaches it's max value, so I decided to write this code: #include <stdint.h> #include <iostream> #define UINT64_SIZE 18446744073709551615 int main() { std::uint64_t i = UINT64_SIZE; double d1 = ((double)(i+1)) / UINT64_SIZE; double d2 = (((double)(i)) / UINT64_SIZE)*16; double d3 = ((double)(i * 16)) / UINT64_SIZE; std::cout << d1 << " " << d2 << " " << d3; } I was expecting something like this: 0 16 0 But this is my output: 0 16 1 What is

问题 I read many articles about unsafe functions like strcpy, memcpy, etc. which may lead to security problems when processing external data, like the content of a file or data coming from sockets. This may sound stupid, but I wrote a vulnerable program but I did not manage to "hack" it. I understand the problem of buffer overflow. Take this example code: int main() { char buffer[1]; int var = 0; scan("%s", &buffer); printf("var = 0x%x\n", var); return 0; } When I execute the program and type

问题 I'm trying to use only AND OR XOR and NOT to determine whether adding 2 binary number made of 4 bits will overflow. I know, for example, that something like 1100 + 0100 will wind up as 1 | 0000. But how can I find this using just these logical operators? I'm trying to get 1000 when overflow happens, and 0000 when it doesn't. This is easy enough since I can just use XOR with a mask to clear the last 3 bits. Does anyone have suggestions for figuring this out? 回答1: Numbers are ABCD and EFGH, ^