outputstream

问题 Hi just wanted to share this servlet it takes 2 arguments ( img-> image name , rot ->rotation of the images) loads the image from the images directory rotates it and outputs it to the servlet stream you can find it in the answer below 回答1: package at.buchinger.mapdisplay; import java.awt.geom.AffineTransform; import java.awt.image.AffineTransformOp; import java.awt.image.BufferedImage; import java.io.File; import java.io.IOException; import java.util.Iterator; import javax.imageio.ImageIO;

问题 I don't know how to explain it but, I'm gonna give it a try. This problem concerns 2 servers, a local and a hosting server. Both servers are running the same PHP version which is 7.0 [with almost same configurations]. And 2 controller actions. And the problem comes from $app->run($input, $out); from the codes below. I have in my controller that action: /** * @Route("/testJson") */ public function testJsonAction() { $app = new \Symfony\Bundle\FrameworkBundle\Console\Application($this->get(

问题 This question already has answers here : How to save image in android gallery (6 answers) Closed 5 years ago . I am saving Image from res/drawable to Gallery using InputStream and OutputStream . It works fine and save image. But issue is that It does not update Image in Gallery. If I check folder using ES File Explorer then I can see image there. I also checked ddms , It also update image there as soon as write code executes. It works fine if I save Server Image. How to prevent this issue ? I

问题 I create ByteArrayOutputStream barr = new ByteArrayOutputStream(1); , i.e. with capacity 1 bytes and write to it more than 1 byte barr.write("123456789000000".getBytes()); . No error occurs, I check the length of barr it is 15. Why my writing was not blocked or wrapped? Is there a way to prevent of writing more than capacity and which outputstream could be used for that? I am very limited in available memory and don`t want to write there more than my limitations define P.S. Thanks a lot for

问题 Here is a snipped code of my problem: Process process = Runtime.getRuntime().exec(command); if (process.waitFor() != 0) throw new Exception("error"); reader = new BufferedReader(new InputStreamReader(process.getInputStream())); The running process is producing a huge output. If i redirect the output to a file, the process terminates quicker then printing the output on screen (standard output). I do not wish to redirect the output to a file, due to low performance of the disk, filesystem

问题 I have a problem with creating an outputstream file. OutputStream output = new FileOutputStream(username + ".txt"); byte buffer[] = data.getBytes(); output.write(buffer); output.close(); It worked fine, until I made another method: public void actionPerformed (ActionEvent e) //When a button is clicked { if (e.getSource() == encrBtn) { menu.setVisible(false); createProfile(); menu.setVisible(true); } else { if (e.getSource() == decrBtn) { menu.setVisible(false); viewProfile(); menu.setVisible

问题 I read in a text file and try to push it to the browser to prompt a user to download but I'm getting my data plus HTML code inside the file. What am I screwing up? Thanks. byte[] eftTextFile = ...calls a method that returns a byte array (does a File.ReadAllBytes on a txt file) Then I try: Response.Clear(); Response.ContentType = "application/octet-stream"; Response.AddHeader("Content-Disposition", String.Format("attachment;filename=\"{0}\"", fileName)); Response.AddHeader("Content-Length",

问题 I have read a similar question, but my problem wasn't solved. I am trying, for the sake of learning, to build my own Java WebSocket server. The server is set up fine, it accepts incoming connections and gets the handshake data from the client. My server then calculates the handshake return data and tries to write it and flush it. Nonetheless, the in the web inspector, no response headers are shown for the client and the onopen -JavaScript event is never fired. String EOL = System.getProperty(

问题 Can I share an InputStream or OutputStream ? For example, let's say I first have: DataInputStream incoming = new DataInputStream(socket.getInputStream())); ... incoming being an object variable. Later on I temporarily do: BufferedReader dataReader = new BufferedReader(new InputStreamReader(socket.getInputStream())); I understand that the stream is concrete and reading from it will consume its input, no matter from where it's done... But after doing the above, can I still access both incoming

问题 I am using gzip utilities in windows machine. I compressed a file and stored in the DB as blob. When I want to decompress this file using gzip utility I am writing this byte stream to process.getOutputStream. But after 30KB, it was unable to read the file. It hangs there. Tried with memory arguments, read and flush logic. But the same data if I try to write to a file it is pretty fast. OutputStream stdin = proc.getOutputStream(); Blob blob = Hibernate.createBlob(inputFileReader); InputStream