output

strange output while printing float as integer and integer as float in C [duplicate]

夙愿已清 提交于 2020-06-23 07:29:29
问题 This question already has an answer here : Why are the int and float passed in printf going to the wrong positions in the format string? (1 answer) Closed 2 days ago . the following code is not showing the expected output which is garbage value ( strangely the values are swapped ) #include<stdio.h> int main() { float f = 4.6; int d = 7; printf("%d %f\n",f,d); return 0; } output: 7 4.600000 回答1: Let's reduce this a bit: float f = 4.6; printf("%d\n", f); That's undefined behavior . The correct

Modifying “… | tee -a out.txt” to stream output live, rather than on completion?

 ̄綄美尐妖づ 提交于 2020-06-15 05:59:08
问题 I would need to output the output of a command on a file. Let's say my command is zip -r zip.zip directory , I would need to append/write (any of these options would be fine) to a file (let's say out.txt ). I got zip zip.zip directory | tee -a out.txt so far, but it doesn't seem to work, it just writes the whole output when the command is over... How can I achieve this? Thanks ;) 回答1: Background (ie. Why?) Redirections are immediate -- when you run somecommand | tee -a out.txt , somecommand

Operator precedence and evaluation order

China☆狼群 提交于 2020-06-09 18:28:12
问题 I can't understand output of this program: #include<iostream> using namespace std; int main() { int x = 1 , y = 1, z = 1; cout << ( ++x || ++y && ++z ) << endl; //outputs 1; cout << x << " " << y << " " << z ; //x = 2 , y = 1 , z = 1; return 0; } Output: 1 2 1 1 If || is evaluated first then this output is fine, however this article says that && has a higher precedence than || , and thus it must be evaluated first. If this is the case then according to me output should be: 1 1 2 2 as ++y && +

Operator precedence and evaluation order

五迷三道 提交于 2020-06-09 18:27:28
问题 I can't understand output of this program: #include<iostream> using namespace std; int main() { int x = 1 , y = 1, z = 1; cout << ( ++x || ++y && ++z ) << endl; //outputs 1; cout << x << " " << y << " " << z ; //x = 2 , y = 1 , z = 1; return 0; } Output: 1 2 1 1 If || is evaluated first then this output is fine, however this article says that && has a higher precedence than || , and thus it must be evaluated first. If this is the case then according to me output should be: 1 1 2 2 as ++y && +

Get class of returned object by PowerShell command - determine a cmdlet's output data type

六月ゝ 毕业季﹏ 提交于 2020-05-29 11:42:05
问题 In PowerShell, if a command returns an array of one or more objects, I can find out the class of the object by the following method: $ab = SampleCommand $ab[0].getType() But, how can I find out the default return type of a command if the command returned nothing (array of 0 values)? Note: For example, I am working on SCOM PowerShell commands, and I am trying to find the default return class type of command get-scomscadvisoragent , but it returns nothing as the advisor agent is not configured

Get class of returned object by PowerShell command - determine a cmdlet's output data type

断了今生、忘了曾经 提交于 2020-05-29 11:41:07
问题 In PowerShell, if a command returns an array of one or more objects, I can find out the class of the object by the following method: $ab = SampleCommand $ab[0].getType() But, how can I find out the default return type of a command if the command returned nothing (array of 0 values)? Note: For example, I am working on SCOM PowerShell commands, and I am trying to find the default return class type of command get-scomscadvisoragent , but it returns nothing as the advisor agent is not configured

Corrupted output with C++, cin, cout, threads and sync_with_stdio

梦想与她 提交于 2020-05-24 08:48:09
问题 I am trying to make a program in C++ to process a lot of packets in the fastest way possible. All the packets come from the standard should be read as fast as possible, sent to one thread from a pool to do the processing and then handled to an output thread that will write the packet to the standard output. When you are using the standard input and output in C++, it's recommended that before any input or output you call to the std::ios_base::sync_with_stdio(false) function. In some

Why does io.WriterTo's WriteTo method return an int64 rather than an int?

↘锁芯ラ 提交于 2020-05-14 18:33:12
问题 Most of the output methods in Go's io package return (int, error) , for example io.Writer 's Write([]byte) method and the io.WriteString(io.Writer, string) function. However, a few of the output methods, such as io.WriterTo 's WriteTo method, return (int64, error) instead. This makes it inconvenient to implement WriteTo in terms of Write or WriteString without storing an intermediate value and type converting it from int to int64 . What is the reason for this discrepancy? 回答1: It's possible

Use the Merge-OUTPUT function to dump results with msdb.dbo.sp_send_dbmail

旧街凉风 提交于 2020-05-14 02:20:12
问题 I frequently use the msdb.dbo.sp_send_dbmail tool in SQL Server for automated reports and such but I've never really used it to for an update/delete type statement in the @query section. Is it possible to do so? When I run this query, it gives 0 results and doesn't execute the actual Merge and Delete function within the @query section. I'm running a test scenario where I know there should be results, and that it should be deleted but no dice. Any advice appreciated as I may be missing

weird delay of the output of an object when followed by start-sleep (or until script end)

人盡茶涼 提交于 2020-05-12 04:46:03
问题 For some reason, the object won't output until the sleep command is done. [pscustomobject]@{message = 'hi'}; sleep 5 Here's another example. You won't see the output until the loop finishes. foreach ($i in 1..60) { if ($i -eq 1) { [pscustomobject]@{message = $i} } sleep 1 } I guess you have to output at least 2 objects to see anything? ¯\_(ツ)_/¯ After 15 seconds, you see both objects. foreach ($i in 1..60) { if ($i -eq 1 -or $i -eq 15) { [pscustomobject]@{message = $i} } sleep 1 } Or output