output

I'm trying to print stdout in realtime for a subprocess but it looks like stdout is buffered even with bufsize=0 and I can't figure out how to make it work, I always have a delay. The code I tried : p = subprocess.Popen(cmd, stdout=subprocess.PIPE, stderr=subprocess.STDOUT, bufsize=0) line = p.stdout.readline() while line: sys.stdout.write(line) sys.stdout.flush() # DO OTHER STUFF line = p.stdout.readline() Also tried with for line in iter(p.stdout.readline, b'') instead of the while loop and with read(1) instead of readline() . Always the same result, the output gets delayed by a lot of

For example if I have a python script test.py containing import time print 'foo' time.sleep(5) print 'bar' time.sleep(5) and a shell script run_test.sh containing #!/usr/bin/env bash python test.py then running the latter (using the Run menu item for example) from within PyCharm (2016.1) prints no output until the entire script has completed (after about 10 seconds). Is there a way to print output as my shell script runs? Martijn Pieters Looks like you need to explicitly flush the buffer: import sys print 'foo' sys.stdout.flush() time.sleep(5) print 'bar' sys.stdout.flush() time.sleep(5) See

I am running Modelica simulations with Dymola via the Dymola Python interface. My aim is to have the result file written to textual output (i.e. to a .txt file). Even though my model contains the annotation __Dymola_experimentSetupOutput(textual=true, events=false) , the output is written to a .mat file. Unfortunately, when I type find() into the Dymola command line, I cannot find a suitable flag for setting the output format via dymola.ExecuteCommand() . Is there a possibility to set the output format to textual via the Python interface? Thanks! You can set textual output in the python

@Override public void actionPerformed(ActionEvent e) { if (e.getSource() == thirdBtn) { //System.out.println("Third Button Click"); System.out.println(e.getSource()+" Click"); } } In the code above, I was wondering if instead of doing this: //System.out.println("Third Button Click"); if I could do something like this: System.out.println(e.getSource()+" Click"); However the code outputs: BlackJack.OverBoard$BlackJackButton[,440,395,100x25,alignmentX=0.0,alignmentY=0.5, border=javax.swing.plaf.BorderUIResource$CompoundBorderUIResource@7a3d8738, flags=16777504,maximumSize=,minimumSize=

I heard using gets() is bad in C programming and it's safer using fgets... So I am using fgets. However, I encounter a problem with fgets: I entered too much characters and somehow, it overflows. How to get rid of the extra input characters? char answer[4]; char answer2[4]; fgets(answer,sizeof(answer),stdin); printf("answer: %s\n",answer); fgets(answer2,sizeof(answer2),stdin); printf("answer2: %s\n",answer2); For example, for the first fgets, I enter 123456, the output I get is answer: 123 answer2: 456 How do I remove the 456 from going into the next fgets input? I want the output like this

I was looking the way to create in ReactJs similar output events like Angular. I am making a library of components in ReactJs according to Atomic design, so, I have, for example, a Button injected in other component, and I would like to know how I could write a props for Button, so everytime the user press the button would launch this prop(a output in Angular way) to be detected in the parent where it was injected. I don't want to use the State because I want that the components are fully independent. Thanks in advance There is no equivalent to @output EventEmitter in react. The standard way

When I'm debugging my application something is not right, and I can't continue. So is it possible to see the output code of my app while I'm testing it to see what is wrong? I open the output window but nothing happens in there it's just stay blank. In two words: I want to see what my app is actually doing while I'm testing it. I'm using Visual Studio 2010. So is it possible to see the output code of my app while im testing it to see what is wrong? Yes, but you actually have to output something, otherwise nothing will show up. In VB.NET (which is the language you're using if you have Visual