os.walk

This question already has an answer here: Can I force python3's os.walk to visit directories in alphabetical order? how? 3 answers I am concerned about the order of files and directories given by os.walk() . If I have these directories, 1 , 10 , 11 , 12 , 2 , 20 , 21 , 22 , 3 , 30 , 31 , 32 , what is the order of the output list? Is it sorted by numeric values? 1 2 3 10 20 30 11 21 31 12 22 32 Or sorted by ASCII values, like what is given by ls ? 1 10 11 12 2 20 21 22 3 30 31 32 Additionally, how can I get a specific sort? os.walk uses os.listdir . Here is the docstring for os.listdir :

I would like to know if it's possible to force os.walk in python3 to visit directories in alphabetical order. For example, here is a directory and some code that will walk this directory: ryan:~/bktest$ ls -1 sample CD01 CD02 CD03 CD04 CD05 -------- def main_work_subdirs(gl): for root, dirs, files in os.walk(gl['pwd']): if root == gl['pwd']: for d2i in dirs: print(d2i) When the python code hits the directory above, here is the output: ryan:~/bktest$ ~/test.py sample CD03 CD01 CD05 CD02 CD04 I would like to force walk to visit these dirs in alphabetical order, 01, 02 ... 05 . In the python3 doc

I'm looking for a way to do a non-recursive os.walk() walk, just like os.listdir() works. But I need to return in the same way the os.walk() returns. Any idea? Thank you in advance. next(os.walk(...)) Add a break after the filenames for loop: for root, dirs, filenames in os.walk(workdir): for fileName in filenames: print (fileName) break #prevent descending into subfolders This works because (by default) os.walk first lists the files in the requested folder and then goes into subfolders. Kamiccolo My a bit more parametrised solution would be this: for root, dirs, files in os.walk(path): if not

How do I limit os.walk to only return files in the directory I provide it? def _dir_list(self, dir_name, whitelist): outputList = [] for root, dirs, files in os.walk(dir_name): for f in files: if os.path.splitext(f)[1] in whitelist: outputList.append(os.path.join(root, f)) else: self._email_to_("ignore") return outputList Use the walklevel function. import os def walklevel(some_dir, level=1): some_dir = some_dir.rstrip(os.path.sep) assert os.path.isdir(some_dir) num_sep = some_dir.count(os.path.sep) for root, dirs, files in os.walk(some_dir): yield root, dirs, files num_sep_this = root.count

I need to list all files with the containing directory path inside a folder. I tried to use os.walk , which obviously would be the perfect solution. However, it also lists hidden folders and files. I'd like my application not to list any hidden folders or files. Is there any flag you can use to make it not yield any hidden files? Cross-platform is not really important to me, it's ok if it only works for linux (.* pattern) Martijn Pieters No, there is no option to os.walk() that'll skip those. You'll need to do so yourself (which is easy enough): for root, dirs, files in os.walk(path): files =