orm

Why does TypeORM require the inverse side of OneToMany to be provided, but doesn't require the inverse side of ManyToOne to be provided?

这一生的挚爱 提交于 2021-01-01 06:53:30
问题 The following quote is taken from the TypeORM docs: @OneToMany cannot exist without @ManyToOne. If you want to use @OneToMany, @ManyToOne is required. However, the inverse is not required: If you only care about the @ManyToOne relationship, you can define it without having @OneToMany on the related entity. Where you set @ManyToOne - its related entity will have "relation id" and foreign key. Why do you need to provide the inverse side of OneToMany but not ManyToOne? 回答1: It is because

Why does TypeORM require the inverse side of OneToMany to be provided, but doesn't require the inverse side of ManyToOne to be provided?

白昼怎懂夜的黑 提交于 2021-01-01 06:53:05
问题 The following quote is taken from the TypeORM docs: @OneToMany cannot exist without @ManyToOne. If you want to use @OneToMany, @ManyToOne is required. However, the inverse is not required: If you only care about the @ManyToOne relationship, you can define it without having @OneToMany on the related entity. Where you set @ManyToOne - its related entity will have "relation id" and foreign key. Why do you need to provide the inverse side of OneToMany but not ManyToOne? 回答1: It is because

TypeORM: update item and return it

笑着哭i 提交于 2020-12-30 04:55:39
问题 As far as I know, it's a best practice to return an item after it has been updated. TypeORM's updateById returns void , not the updated item though. My question: Is it possible to update and return the modified item in a single line? What I tried so far: await this.taskRepository.updateById(id, { state, dueDate }); return this.taskRepository.findOne({ id }); What I'm looking for: return this.taskRepository.updateById(id, { state, dueDate }); // returns updated task 回答1: I just found out that

How to use 'hasManyThrough' with more than 3 tables in Laravel?

让人想犯罪 __ 提交于 2020-12-29 23:37:30
问题 as stated in the docs the current hasManyThrough can be used when u have something like country > users > posts which result in something like Country::whereName('xx')->posts; which is great but what if i have more than that like country > cities > users > posts or even country > cities > towns > users > posts how would you then implement something like that so you can write the same as above Country::whereName('xx')->posts; or Town::whereName('xx')->posts; 回答1: I created a HasManyThrough

How to use 'hasManyThrough' with more than 3 tables in Laravel?

帅比萌擦擦* 提交于 2020-12-29 23:34:58
问题 as stated in the docs the current hasManyThrough can be used when u have something like country > users > posts which result in something like Country::whereName('xx')->posts; which is great but what if i have more than that like country > cities > users > posts or even country > cities > towns > users > posts how would you then implement something like that so you can write the same as above Country::whereName('xx')->posts; or Town::whereName('xx')->posts; 回答1: I created a HasManyThrough

How to use 'hasManyThrough' with more than 3 tables in Laravel?

大城市里の小女人 提交于 2020-12-29 23:33:34
问题 as stated in the docs the current hasManyThrough can be used when u have something like country > users > posts which result in something like Country::whereName('xx')->posts; which is great but what if i have more than that like country > cities > users > posts or even country > cities > towns > users > posts how would you then implement something like that so you can write the same as above Country::whereName('xx')->posts; or Town::whereName('xx')->posts; 回答1: I created a HasManyThrough

Waterline ORM (sails.js) conditions with NOT Equal in query

不想你离开。 提交于 2020-12-29 09:34:26
问题 How can I write a NOT Equal condition in Waterline? This code: Users .count() .where({ id: { '!=': req.params.id}, lastname: req.body.lastname }) Does nothing... (disk adapter in sails.js) 回答1: First thing, it do nothing because looking into database is asynchronous. You have to make the chain longer and add exec or something from Q library like then. User.count().where({ id: { '!=': req.params.id }, lastname: req.body.lastname }).exec(function(err, num){ console.log(num); }); Now it returns

Eloquent select rows with empty string or null value

半腔热情 提交于 2020-12-29 09:11:37
问题 I have something like $user->albums()->where('col', NULL) , it works fine then I tried to extend it to empty strings with $user->albums()->where('col', NULL)->or_where('col', '') and it's not working. Also I saw on this post that I could use where_null('col') but it's not working and it's not documented. Any simple method to select where empty or NULL col 回答1: Try using orWhereNull for the second clause: $users = DB::table('users') ->where('col', '=', '') ->orWhereNull('col') ->get(); 回答2:

Eloquent select rows with empty string or null value

非 Y 不嫁゛ 提交于 2020-12-29 09:10:24
问题 I have something like $user->albums()->where('col', NULL) , it works fine then I tried to extend it to empty strings with $user->albums()->where('col', NULL)->or_where('col', '') and it's not working. Also I saw on this post that I could use where_null('col') but it's not working and it's not documented. Any simple method to select where empty or NULL col 回答1: Try using orWhereNull for the second clause: $users = DB::table('users') ->where('col', '=', '') ->orWhereNull('col') ->get(); 回答2:

Eloquent select rows with empty string or null value

纵然是瞬间 提交于 2020-12-29 09:06:47
问题 I have something like $user->albums()->where('col', NULL) , it works fine then I tried to extend it to empty strings with $user->albums()->where('col', NULL)->or_where('col', '') and it's not working. Also I saw on this post that I could use where_null('col') but it's not working and it's not documented. Any simple method to select where empty or NULL col 回答1: Try using orWhereNull for the second clause: $users = DB::table('users') ->where('col', '=', '') ->orWhereNull('col') ->get(); 回答2: