ordereddictionary

Implement an ordered dictionary in Robot Framework

醉酒当歌 提交于 2019-12-01 10:29:19
I want to have an ordered dictionary in Robot Framework. Is there any libraries which I can use for this purpose? How can I do that? I am not aware of any library that has a keyword to create an ordered dict, but creating an ordered dict is simple enough. As of Python 2.7, there is an ordered dictionary available from Python. Robot Framework also defines one that is available in Python/Jython versions prior to 2.7. The Robot Framework OrderedDict has more features than the Python one. Creating an ordered dict in Robot Framework would look like this: ${od} Evaluate collections.OrderedDict()

getting the key index in a Python OrderedDict?

前提是你 提交于 2019-11-30 17:32:07
I have a collections.OrderedDict with a list of key, value pairs. I would like to compute the index i such that the i th key matches a given value. For example: food = OrderedDict([('beans',33),('rice',44),('pineapple',55),('chicken',66)]) I want to go from the key chicken to the index 3, or from the key rice to the index 1. I can do this now with food.keys().index('rice') but is there any way to leverage the OrderedDict 's ability to look things up quickly by key name? Otherwise it seems like the index-finding would be O(N) rather than O(log N), and I have a lot of items. I suppose I can do

OrderedDict does not preserve the order

柔情痞子 提交于 2019-11-30 08:43:04
问题 from collections import OrderedDict import pprint menu = {"about" : "about", "login" : "login", 'signup': "signup"} menu = OrderedDict(menu) pprint.pprint(menu.items()) import sys sys.exit() The output is: [('about', 'about'), ('signup', 'signup'), ('login', 'login')] So, the order is not preserved even with the use of OrderedDict . I know the dictionaries don't preserve the initial order by default, and all those things. But I want to learn why the OrderedDict is not working. 回答1: By putting

How to get count dict of items but maintain the order in which they appear?

試著忘記壹切 提交于 2019-11-30 05:49:29
问题 For example, I need to count how many times a word appears in a list, not sorted by frequency but with the order in which the words appear, i.e. insertion order. from collections import Counter words = ['oranges', 'apples', 'apples', 'bananas', 'kiwis', 'kiwis', 'apples'] c = Counter(words) print(c) So instead of: {'apples': 3, 'kiwis': 2, 'bananas': 1, 'oranges': 1} I'd rather get: {'oranges': 1, 'apples': 3, 'bananas': 1, 'kiwis': 2} And I don't really need this Counter method, any way that

getting the key index in a Python OrderedDict?

让人想犯罪 __ 提交于 2019-11-30 01:15:13
问题 I have a collections.OrderedDict with a list of key, value pairs. I would like to compute the index i such that the i th key matches a given value. For example: food = OrderedDict([('beans',33),('rice',44),('pineapple',55),('chicken',66)]) I want to go from the key chicken to the index 3, or from the key rice to the index 1. I can do this now with food.keys().index('rice') but is there any way to leverage the OrderedDict 's ability to look things up quickly by key name? Otherwise it seems

Slicing a Python OrderedDict

戏子无情 提交于 2019-11-29 11:34:58
问题 In my code I frequently need to take a subset range of keys+values from a Python OrderedDict (from collections package). Slicing doesn't work (throws TypeError: unhashable type ) and the alternative, iterating, is cumbersome: from collections import OrderedDict o = OrderedDict([('a', 1), ('b', 2), ('c', 3), ('d', 4)]) # want to do: # x = o[1:3] # need to do: x = OrderedDict() for idx, key in enumerate(o): if 1 <= idx < 3: x[key] = o[key] Is there a better way to get this done? 回答1: The

OrderedDict does not preserve the order

久未见 提交于 2019-11-29 07:38:01
from collections import OrderedDict import pprint menu = {"about" : "about", "login" : "login", 'signup': "signup"} menu = OrderedDict(menu) pprint.pprint(menu.items()) import sys sys.exit() The output is: [('about', 'about'), ('signup', 'signup'), ('login', 'login')] So, the order is not preserved even with the use of OrderedDict . I know the dictionaries don't preserve the initial order by default, and all those things. But I want to learn why the OrderedDict is not working. By putting the items in a (non-ordered) dict and constructing the OrderedDict from that, you've already discarded the

What is the best ordered dict implementation in python?

一世执手 提交于 2019-11-28 20:56:06
I've seen (and written) a number of implementations of this. Is there one that is considered the best or is emerging as a standard? What I mean by ordered dict is that the object has some concept of the order of the keys in it, similar to an array in PHP. odict from PEP 372 seems like a strong candidate, but it's not totally clear that it is the winner. This one by Raymond Hettinger is a drop-in substitute for the collections.OrderedDict that will appear in Python 2.7: http://pypi.python.org/pypi/ordereddict The dev version of the collections docs say it's equivalent to what will be in Python

Generate a pandas dataframe from ordereddict?

时光怂恿深爱的人放手 提交于 2019-11-28 09:13:16
I am trying to create a pandas dataframe from an ordereddict to preserve the order of the values. But for some reason after creating the dataframe the fields are messed up again. Here's the list of ordereddicts: [OrderedDict([ ('key_a', 'value_a'), ('key_b', 'value_b'), ]), OrderedDict([ ('key_a', 'value_c'), ('key_b', 'value_d'), ]) ] Now how should I create a pandas DataFrame from these? What I am looking for is something like that (the important thing is the key_a and key_b etc column name order): key_a key_b 0 value_a value_b 1 value_c value_d I have tried: pd.DataFrame.from_records

OrderedDict comprehensions

淺唱寂寞╮ 提交于 2019-11-28 07:54:57
Can I extend syntax in python for dict comprehensions for other dicts, like the OrderedDict in collections module or my own types which inherit from dict ? Just rebinding the dict name obviously doesn't work, the {key: value} comprehension syntax still gives you a plain old dict for comprehensions and literals. >>> from collections import OrderedDict >>> olddict, dict = dict, OrderedDict >>> {i: i*i for i in range(3)}.__class__ <type 'dict'> So, if it's possible how would I go about doing that? It's OK if it only works in CPython. For syntax I guess I would try it with a O{k: v} prefix like we