ordereddictionary

问题 With Python 3: >>> from collections import OrderedDict >>> d1 = OrderedDict([('foo', 'bar')]) >>> d2 = OrderedDict([('foo', 'bar')]) I wanted to check for equality: >>> d1 == d2 True >>> d1.keys() == d2.keys() True But: >>> d1.values() == d2.values() False Do you know why values are not equal? I've tested this with Python 3.4 and 3.5. Following this question, I posted on the Python-Ideas mailing list to have additional details: https://mail.python.org/pipermail/python-ideas/2015-December

问题 I've extracted the setting names and their respective values out of a configuration file into an ordered dictionary. The dictionary contains keys and values which are of the ICollection class. I want to bind that data and display it in a DataGridView. I've tried copying the strings to arrays and displaying those arrays, but when I ran the program the columns were blank and it did not seem to be binded at all. I've also attempted to set the DataGridView source directly to one the ordered

问题 This question already has answers here : Converting dict to OrderedDict (4 answers) Closed 2 years ago . I'm trying to create an OrderedDict object but no sooner do I create it, than the elements are all jumbled. This is what I do: from collections import OrderedDict od = OrderedDict({(0,0):[2],(0,1):[1,9],(0,2):[1,5,9]}) The elements don't stay in the order I assign od OrderedDict([((0, 1), [1, 9]), ((0, 0), [2]), ((0, 2), [1, 5, 9])]) docs.python.org doesn't have an example and I can't

问题 I have a list of orderdicts. And I would like to combine all of them together and then sort them by the fruit attribute in each of them. I have been to combine and sort them using defaultdict through the code below. super_dict_apple = defaultdict(list) super_dict_orange = defaultdict(list) super_dict_no_fruit = defaultdict(list) for d in dict: if 'fruit' not in d: for k, v in d.iteritems(): super_dict_no_fruit[k].append(v) elif d['fruit'] == 'Apple': for k, v in d.iteritems(): super_dict

问题 def positive(self): total = {} final = {} for word in envir: for i in self.lst: if word in i: if word in total: total[word] += 1 else: total[word] = 1 final = sorted(total, reverse = True) return total This returns {'climate': 10, 'ecosystem': 1, 'energy': 6, 'human': 1, 'world': 2, 'renewable': 2, 'native': 2} I want to get this dictionary back to a dictionary that is in order. How do you I sort it and return a dictionary? 回答1: An ordered dictionary would get you what you need from

问题 I have a csv file and i need the columns to be printed as OrderedDict I am able to convert the rows into an ordereddict using collections.OrderedDict((row[0], row[1:]) for row in r) in python (2.7.5) But when i try the same for columns i am getting ' cannot unpack more than one value ' error. Is there any workaround? fileLocation = 'C:/test.csv' with open(fileLocation,'rb') as f: r = csv.reader(f) od = collections.OrderedDict((row[0], row[1:]) for row in r) print od 回答1: try using this od =

问题 The orderedDictionary instantiation is this: IOrderedDictionary orderedDictionary= gridview.DataKeys[index].Values; orderedDictionary is read only. How can I make a deep copy of orderedDictionary that is not read only? Serialization/deserialization doesn't work cause it also copies the read only part. 回答1: The easiest way would be to just copy the objects: var newDictionary = new OrderedDictionary(); foreach(DictionaryEntry de in orderedDictionary) { newDictionary.Add(de.Key, de.Value); }

问题 If I have a CSV file that has a dictionary value for each line (with columns being ["Location"], ["MovieDate"], ["Formatted_Address"], ["Lat"], ["Lng"]), I have been told to use OrderDict if I want to group by Location and append on all the MovieDate values that share the same Location value. ex of data: Location,MovieDate,Formatted_Address,Lat,Lng "Edgebrook Park, Chicago ",Jun-7 A League of Their Own,"Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672

问题 The idea of this loop was to iterate through a list. If a certain property of an object was not a key of the OrderedDict, it would add it. It is a dictionary of lists of objects for object in someList: if object.DATE not in myOrderedDict: myOrderedDict[object.DATE]=[] myOrderedDict[object.DATE].append(object) while it does seem to make the OrderedDict mostly correctly, it ends up out of order when it's printed. Instead of having something like (01/13) (02/13) (03/13) it goes more like (02/13)

问题 I'm reading @Martijn Pieters' response to Converting dict to OrderedDict. The main point of his answer is that passing a regular dict to OrderedDict() will not retain the order as desired, because the dict that you are passing has already "lost" any semblance of order. His solution is to pass tuples that make up the dict's key/value pairs instead. However, I also noticed the following in the docs: Changed in version 3.6: With the acceptance of PEP 468, order is retained for keyword arguments