ora-00904

I have a PL/SQL function with BOOLEAN in parameter: function get_something(name in varchar2, ignore_notfound in boolean); This function is a part of 3rd party tool, I cannot change this. I would like to use this function inside a SELECT statement like this: select get_something('NAME', TRUE) from dual; This does not work, I get this exception: ORA-00904: "TRUE": invalid identifier As I understand it, keyword TRUE is not recognized. How can I make this work? You can build a wrapper function like this: function get_something(name in varchar2, ignore_notfound in varchar2) return varchar2 is begin

I have (and don't own, so I can't change) a table with a layout similar to this. ID | CATEGORIES --------------- 1 | c1 2 | c2,c3 3 | c3,c2 4 | c3 5 | c4,c8,c5,c100 I need to return the rows that contain a specific category id. I starting by writing the queries with LIKE statements, because the values can be anywhere in the string SELECT id FROM table WHERE categories LIKE '%c2%'; Would return rows 2 and 3 SELECT id FROM table WHERE categories LIKE '%c3%' and categories LIKE '%c2%'; Would again get me rows 2 and 3, but not row 4 SELECT id FROM table WHERE categories LIKE '%c3%' or categories

SELECT ename , job , CASE deptno WHEN 10 THEN 'ACCOUNTS' WHEN 20 THEN 'SALES' ELSE 'UNKNOWN' END AS department FROM emp /* !!! */ WHERE department = 'SALES' This fails: ORA-00904: "%s: invalid identifier" Is there a way to overcome this limitation in Oracle 10.2 SQL ? How to use the 'case expression column' in where clause ? ypercubeᵀᴹ The reason for this error is that SQL SELECT statements are logically * processed in the following order: FROM : selection of one table or many JOINed ones and all rows combinations that match the ON conditions. WHERE : conditions are evaluated and rows that do